A jar holds 16 ounces of honey. A cook is going to make two recipes. One calls for 2.5 ounces of honey, and the other calls for 4.25 ounces of honey. After the cook has made those two recipes, how many ounces of honey will be left in the jar?

Answers

Answer 1
Answer:

The amount of ounces of honey that will be left in the jar is 9.25 ounces.

How many ounces of honey will be left in the jar?

To find out how many ounces of honey will be left in the jar after making the two recipes, we need to subtract the total amount of honey used in the recipes from the initial amount of honey in the jar.

The first recipe calls for 2.5 ounces of honey, and the second recipe calls for 4.25 ounces of honey. Therefore, the total amount of honey used in both recipes is:

2.5 ounces + 4.25 ounces = 6.75 ounces

Now, to determine howmany ounces of honey will be left in the jar, we subtract the total amount used from the initial amount:

16 ounces - 6.75 ounces = 9.25 ounces

After making both recipes, there will be 9.25 ounces of honey left in the jar.

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Answer 2
Answer:

Answer: 9.25

Step-by-step explanation:

16- 2.5- 4.25= 9.25


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You deposit 350 in an account that pays 3% annual intrest. Find the balance afer 2 years if the intrest is compounded

Answers

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \n\n A=P\left(1+(r)/(n)\right)^(nt) \quad \begin{cases} A=\textit{accumulated amount}\n P=\textit{original amount deposited}\dotfill &\$350\n r=rate\to 3\%\to (3)/(100)\dotfill &0.03\n n= \begin{array}{llll} \textit{times it compounds per year}\n \textit{annually, thus once} \end{array}\dotfill &1\n t=years\dotfill &2 \end{cases} \n\n\n A=350\left(1+(0.03)/(1)\right)^(1\cdot 2)\implies A=350(1.03)^2\implies A=371.315

2x-3y=-143x-2y=-6
if (x,y) is a solution to the system of equations above, what is the value of x-y?
A)-20
B)-8
C)-4
D)8
can you show your work please

Answers

Answer:

Step-by-step explanation:

The given system of equations :

2x-3y=-14.............................(1)\n3x-2y=-6.........................(2)

Multiply equation (1) with 3 and equation (2) with 2 , we get

6x-9y=-42.............................(3)\n6x-4y=-12.........................(4)

Now subtract equation (4) from equation (3), we get

5y=30\n\n\Rightarrow\ y=6

Substitute the value of y in equation (1), we get

2x-3(6)=-14\n\n\Rightarrow\ 2x=-14+18\n\n\Rightarrwo\ 2x=4\n\n\Rightarrow\ x=2

Hence, the solution of the system : (x,y)=(2,6)

Now, consider  x-y and substitute the value of x and y , we get

2-6=-4

The solution to the equation is x - y = -4

Given data ,

To solve the system of equations, we can use the method of substitution or elimination. Let's use the method of elimination:

Multiply the first equation by 3 and the second equation by 2 to make the coefficients of x in both equations equal:

(3)(2x-3y) = (3)(-14)

(2)(3x-2y) = (2)(-6)

Simplifying these equations gives:

6x-9y = -42

6x-4y = -12

Now, subtract the second equation from the first equation:

(6x-9y) - (6x-4y) = (-42) - (-12)

-5y = -30

Divide both sides by -5:

y = 6

Substitute this value of y back into one of the original equations, let's use the first equation:

2x - 3(6) = -14

2x - 18 = -14

2x = 4

x = 2

Now , the value of x - y is given by

A = x - y

A = 2 - 6

A = -4

Hence , the equation is solved

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Sam has a budget of $24 to buy ham and cheese to make sandwiches. If he bought only ham, he could buy 8 lb. If he bought only cheese, hecould buy 3 lb. Let x represent the amount of ham and y represent the amount of cheese. Write an equation standard form to model the
different amounts of ham and cheese he can buy.
Help me please ?

Answers

Answer:

can you show the answers?

Step-by-step explanation:

Answer:

3

Step-by-step explanation:

Which of the following statements have the same result? Explain each step in solving each one.f(1) when f(x) = 5x + 1
f−1(3) when f(x) = 2x plus 3, all over 5
3y − 7 = y + 5

Answers

f(x) = 5x + 1\n\nsubtitute\ x = 1\ to\ the\ equation\n\nf(1) = 5\cdot1 + 1 = 5 + 1 = 6\n----------------------\nf(x)=(2x+3)/(5)\to y=(2x+3)/(5)\ \ \ \ |multiply\ both\ sides\ by\ 5\n\n5y=2x+3\ \ \ \ |subtract\ 3\ from\ both\ sides\n\n2x=5y-3\ \ \ \ \ |divide\ both\ sides\ by\ 2\n\nx=(5y-3)/(2)\n\nf^(-1)(x)=(5\cdot(-1)-3)/(2)=(-5-3)/(2)=(-8)/(2)=-4\n---------------------\n3y-7=y+5\ \ \ |add\ 7\ to\ both\ sides\n3y=y+12\ \ \ \ |subtract\ y\ from\ both\ sides\n2y=12\ \ \ \ |divide\ both\ sides\ by\ 2\ny=6

Answer: f(1) when f(x) = 5x + 1 and 3y - 7 = y + 5


3. A prop for the theater club's play is constructed as a cone topped with a half-sphere. What is the volume of the prop? Round your answer to the nearest tenth of a cubic inch. Use 3.14 to approximate pi. 12 radius 18 height ​

Answers

Answer:

8138.88 cubic unit.

Step-by-step explanation:

Given that,

Radius, r = 12

Height, h = 18

We need to find the volume of the prop. The volume of a cylinder is given by the formula as follows :

V=\pi r^2 h\n\nV=3.14* 12^2 * 18\n\nV=8138.88\

So, the volume of the cylinder is 8138.88 cubic unit.

Jayden measured a community college and made a scale drawing. He used the scale 22 millimeters : 9 meters. The actual length of a building at the college is 99 meters. How long is the building in the drawing?

Answers

Hey there! :)

Answer:

x = 242 mm.

Step-by-step explanation:

Begin by setting up a proportion between the actual college building and the drawing.

(22mm)/(9m) = (x)/(99m)

Cross multiply:

99 × 22 = 9 × x

2178 = 9x

Divide both sides by 9:

2178/9 = 9x/9

x = 242 mm.