The sum of two numbers is 36. The larger number is 8 more than the smaller number. Find the two numbers (please show work)
Answers
larger number is 14 +8 = 22
Related Questions
Y is 2 less than the product of 9 and x. write a function rule
Coconuts were on sale, 4 for $4.44. Pineapples were on sale, 3 for $3,63. Whichof the following is true?ОА.1/6Coconuts are 10¢ less each than pineapples,Coconuts are 10¢ more each than pineapples,B.OC. Coconuts are each $1.21.OD. Pineapples are each $1.11.
Nine more than thirty divided by ten
If T(n) = 6n + 2 what is the 3rd term
b. 28.26 square feet
c. 63.61 square feet
d. 254.34 square feet
Answers
The area of the circular ring of the fountain with a radius of 9 feet is approximately 254.34 square feet.
To find the area of the ring, we need to subtract the area of the smaller circle from the area of the larger circle. The area of a circle is given by the formula A = πr^2, where r is the radius of the circle. Therefore, the area of the larger circle is π(9^2) = 81π square feet, and the area of the smaller circle is π((9/2)^2) = 20.25π square feet.
Subtracting the area of the smaller circle from the area of the larger circle, we get:
81π - 20.25π = 60.75π
Using the approximation π ≈ 3.14, we get:
60.75π ≈ 60.75(3.14) ≈ 190.845
Therefore, the area of the ring is approximately 190.845 square feet, which is closest to option (d) 254.34 square feet.
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Answer:
I would say about 60 to 70 pounds. But I have no more information from you to better answer your question, so that's all I have right now.
Step-by-step explanation:
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4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 = 32
or...
4 * 8 = 32
The diameter of the gazebo in the park is 32 feet long.
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so expand this stuff
-3(y+2)^2-5+6y
do exponent first
(y+2)^2=(y+2)(y+2)=y²+2y+2y+4=y²+4y+4
now
-3(y²+4y+4)-5+6y
multiply/distribute
-3y²-12y-12-5+6y
regroup like terms
-3y²-12y+6y-12-5
-3y²-6y-17
that is standard form
The simplified product in standard form is
Given the following equation:
To find the simplified product in standard form:
A quadratic equation is a mathematical expression that one of its variables is to the degree of 2 and as such, it has two roots.
In Mathematics, the standard form of a quadratic equation is given by;
Simplifying the given mathematical equation, we have;
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The shapes formed by vertical, angled, and horizontal cross-section of a rectangular prism are: vertical: rectangle, horizontal: rectangle and angled: parallelogram
What is a cross-section of an object?
A cross-section of a solid is a plane figure obtained by the intersection of that solid with a plane. The cross-section of an object therefore represents an infinitesimal "slice" of a solid, and may be different depending on the orientation of the slicing plane.
Given is a rectangular prism, we need to define its cross-section
The vertical and horizontal cross-section are fairly straight forward. They are simply mirror images of the outward showing faces.
The angled cross-section is a bit more complicated and there's a lengthy proof involved, but long story short, the angled cutting plane divides the 3D solid such that we have 2 sets of lines that have the same slope (if we consider a 2D view), which leads to 2 sets of parallel sides.
Hence, the shapes formed by vertical, angled, and horizontal cross-section of a rectangular prism are: vertical: rectangle, horizontal: rectangle and angled: parallelogram
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L = 10
H = 6
W = 4
Imagine the shape is facing slightly towards your left
A left vertical cross section (perpendicular to the base) of the cuboid would result in a 10 by 6 rectangle
A right vertical cross section (perpendicular to the base) of the cuboid would result in a 6 by 4 rectangle
A horizontal cross section (parallel to the base) of the cuboid would result in a 10 by 4 rectangle
An angled cross section (through the middle) would also give a rectangle but the dimensions would be different. If the cut went from one '4' edge to the one in the opposite corner, the length of that would be found using Pythagoras
a² + b² = c²
6² + 10² = c²
36 + 100 = 136
√136 ≈ 11.66cm
11.66 by 4 rectangle
The shows that the resulting shape will always be a rectangle for these cross sections.
The only case in which it would not, would be if one of the faces of the cuboid was a square - in which case one of the cross sections would also be a square.
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16) area of square with side lengths (x-3) units
area of a square = a²
A = (x-3)²
A = (x-3)(x-3)
A = x(x-3) -3(x-3)
A = x² - 3x -3x + 9
A = x² - 6x + 9
Area of a rectangle with a length of x units and a width of (x-5)units
Area of a rectangle = length * width
A = x * (x-5)
A = x(x-5)
A = x² - 5x
Value of x for Area of square and Area of rectangle to be equal.
Area of square = Area of rectangle
x² - 6x + 9 = x² - 5x
x² - x² - 6x + 5x = -9
-x = -9
x = -9/-1
x = 9
x² - 6x + 9 = x² - 5x
9² - 6(9) + 9 = 9² - 5(9)
81 - 54 + 9 = 81 - 45
90 - 54 = 36
36 = 36