F(x) = x^2 what is the derivative
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Answer:
General Formulas and Concepts:
Calculus
Differentiation
- Derivatives
- Derivative Notation
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Step-by-step explanation:
Step 1: Define
Identify
Step 2: Differentiate
- Basic Power Rule:
Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Differentiation
Answer:
(x) = 2x
Step-by-step explanation:
F(x) = x²
differentiate F(x) with respect to x
(x) = 2x
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What is 82/100 in its simplest form?
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if we substitute x = 1
y = 2*1
y = 2
so the equation is valid
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k+3 3/4=4 1/3
lets find the lcm first then multiply both sides by it but first change it to improper fraction
LCM is 12
[k+15/4]=[13/3]12
12k+45=52
12k=7
k=7/12
b.write the equation in slope intercept form.
c.what is the setup fee?
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Final answer:
The setup fee for the cable service can be found by creating an equation using the given point and solving for the y-intercept. This y-intercept, in this context, represents the setup fee.
Explanation:
Firstly, we understand that the cost per month for the premium cable is $39.95. Considering this cost as a rate, we can say that the total monthly cost can be calculated by multiplying the number of months with the rate per month. The setup fee is a fixed cost, and thus it doesn't change with the number of months.
To find this setup fee, we need to find the y-intercept. In this situation, the y-intercept, denoted usually as b in the slope-intercept form equation y = mx + b, is the setup fee.
So let's solve it step-by-step:
- Given the point (6, 264.70) substitutes into the equation as x and y. We can set up the following equation from this point: 264.70 = 39.95*6 + b.
- After multiplying and subtracting, we solve for b. The value of b comes out to be the setup fee.
So, the setup fee is found out by subtracting from the total cost of 6 months, the cost of the cable service for these 6 months.
Learn more about slope-intercept form here:
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