Graph with a line going through points zero comma two point five and four comma two point five.Select the equation of the line that passes through the point (3, -1) and is parallel to the line on the graph.
a) y = -1
b) y = 3
c) y = x -1
d) y = 3x - 1
*graph is attached for 1st question*
Graph with a line going through points negative 2 comma zero and 0 comma negative one.
Select the equation of a line that is perpendicular to the line on the graph and passes through the point (-1, 2).
y = 2x + 4
y = - 2x + 2
y = - 1 over 2 x + 2
y = 2x - 1
Answers
Answer:
1 -
2 -
Step-by-step explanation:
The general form of a straight line is , where m = slope and b = y-intercept.
Ques 1: We are given that the line passes through (0,2.5) and (4,2.5).
Then the slope of the line is given by,
Then, the y-intercept is given by,
That is, the equation of the line is
Since, 'Two parallel lines have equal slope'.
Then, the line parallel to have slope 0 i.e.
.
As, the line passes through the point (3,-1) i.e. y= -1 for any value of x.
Then, the equation of line is
So, option A is correct.
Ques 2: We are given that the line passes through (-2,0) and (0,-1).
Then the slope of the line is given by,
Then, the y-intercept is given by,
That is, the equation of the line is
Since, 'The product of slopes of two perpendicular lines is -1'.
Then, we have,
The line perpendicular to have slope 2.
As, the line passes through the point (-1,2) with slope 2.
The y-intercept is given by,
Thus, the equation of the line is
So, option A is correct.
The graph of the first line is 0. The graph of the second line will also be equal to 0. Replacing in the general equation of a line y=mx+c;
y=(0)x+c
y=c
Using the point (3,-1)
-1=c
y=-1
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