The answer would be, B-False
Answer:100 g of ca
Explanation:
(1) 2 × 10^–2 m (3) 2 × 10^0 m
(2) 2 × 10^–1 m (4) 2 × 10^1 m
The object be going at the bottom of the hill with velocity 7.75 m/s.
When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time.
Given in the question a 400 kg object is sitting at rest at the top of a hill that is 30.0 m high and 80.0 m long measured along the hill . If there is no friction, velocity with which object be going at the bottom of the hill,
θ =sin^-1(30/80)
θ =22
F = 400 g sin(22) = 150 N
F = ma
150 = 400 a
a = 0.375 m/s²
v² - u²= 2 a s
v² - 0 = 2 x 0.375 x 80
v = 7.75 m/s
The object be going at the bottom of the hill with velocity 7.75 m/s.
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Answer:
Watts
Explanation:
A. Constant Velocity
B. 0 Acceleration
if it is horizontal line, that means position is same but time is increasing.
velocity=0 . particle is not even moving