Efforts to restore wetlands and forests along the coast will most likely _______. a. benefit the economy by providing jobs b. improve wildlife populations c. reduce soil erosion and flooding in coastal areas d. all of the above

Answers

Answer 1
Answer:

The right answer is D. all of the above.

The restoration and rehabilitation of wetlands are today major challenges to maintain a fabric of natural spaces with high heritage value. The ecological engineering that has developed over many years, inspired by methods of renaturation of coastal, alluvial, grassland and forest natural areas has specificities that it is necessary to share to allow access to the greatest number. This knowledge is built on the basis of feedback and scientific knowledge, which is itself constantly evolving. They constitute a base for conducting sustainable operations that are consistent with the maintenance of ecological trajectories as close as possible to the natural model in balance with human activities.

Answer 2
Answer: option d. all of the above

all the option have positive outcomes; benefit the economy by providing jobs, specifically it contributes welfare to the society. Improve wildlife populations, when you say improvement there is an additional change that makes something better or valuable. Reduce soil erosion and flooding in coastal areas; we cannot avoid it but we can prevent the destructive effect of this in our lives. Being prepared from those sudden change can restore wetlands and forests not just along the coast as well as to other areas.

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When dissolved in water, all acids willA. Form hydroxide ions B. have a negative eletrical charger C. conduct eletricity D. turn blue

Answers

When dissolved in water, all acids will conduct electricity. The correct answer is C.

Calculate the mass of 25,000 molecules of nitrogen gas. (1 mole = 6.02 x 1023 molecules)

Answers

Answer: 116.2* 10^(-26) grams

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number 6.023* 10^(23) of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text {Given molecules}}{\text {Avogadros number}}

\text{Number of moles}=(25000)/(6.023* 10^(23))=4.15* 10^(-26)moles  

Now 1 mole of N_2 gas weighs = 28 grams

4.15* 10^(-26)moles of N_2 gas weighs =(28)/(1)* 4.15* 10^(-26)=116.2* 10^(-26) grams

Thus the mass will be 116.2* 10^(-26) grams.

Hey there!

Molar mass N2 = 28.01 g/mol

Therefore:

28.01 g N2 -------------- 6.02*10²² molecules N2

( mass N2 ?? ) ----------- 25,000 molecules N2

mass N2 =  ( 25,000 * 28.01 ) /  ( 6.02*10²³ )

mass N2 = 700250 / 6.02*10²³

mass N2 = 1.163*10⁻¹⁸ g


Hope that helps!

What type of intermolecular force is CO3

Answers

Answer:

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Which formula represents lead(II) chromate?(1) PbCrO4 (3) Pb2CrO4
(2) Pb(CrO4)2 (4) Pb2(CrO4)3

Answers

The formula that represents Lead (II) Chromate is PbCrO4. It is a chemical compound with a strong yellow color. 

Lead chromate and lead sulfate are found in the crystal Pb(Cr, S)O₄, which is a changeable solid mixed phase. This material is the end product of a co-precipitation reaction between lead and chrome salts (see the chapter on production and usage for further information). The correct option is 1.

Water does not dissolve lead chromate, which is produced by the double decomposition process. It is also used as a pigment and is referred to as chrome yellow. In a media that has been buffered with a solution of acetic acid and lead acetate, the lead precipitates as chrome.

There may be significant amounts of water-soluble lead compounds in lead chromate pigments. The formula that represents Lead (II) Chromate is PbCrO₄.

Thus the correct option is 1.

To know more about lead(II) chromate, visit;

brainly.com/question/34268715

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Helppp meee plzzz plzzzz
Helppp

Answers

Answer:F =MAX

Explanation:I did that

Answer:

F=MAX

Explanation:

I DID THAT TODAY AT 9:05AM FRIDAY 1/22/2021    

A bullet of mass 50g is fired from a gun at a speed of 250ms. What is the kinetic energy possessed by the bullet?

Answers

Answer: the kinetic energy possessed by the bullet is 1562.5 Joules (J).

Explanation: