If y is 9 and x is 12, what additional information is necessary to show that triangle DUM is congruent to triangle MAP using the SAS postulate?

Answers

Answer 1

Answer: Δ DUM Δ MAP

hypotenuse: 15 2y-3
short leg: 12 0.5x + 6

y = 9 ⇒ 2(9) - 3 = 18 - 3 = 15 Congruent with the hypotenuse of Δ DUM
x = 12 ⇒ 0.5(12) + 6 = 6 + 6 = 12 Congruent with the short leg of Δ DUM

SAS postulate states that two triangles are congruent if 2 of its sides and 1 angle have equal measure. Both the hypotenuse and short leg are equal in measure. Thus, both triangles are congruent with each other.

Answer 2

Answer:

Answer: DM is congruent to PM

Step-by-step explanation: TOOK QUIZ!!!

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(9x3 - 2x2 - 3) - (4x3 - 9x + 6)

Answers

Answer: 22

Step-by-step explanation:

I need help with math 1) Find the LCD of these fraction 6/2a and 1/5 a. 5a2 b.5a c.a2+5 d.a+5 2) Find the LCD of these fraction a.25xy2 b.50xy2 c.25x4y3 d.50x4y3 3) Find the LCD of these fraction 14/x2y and 7/xy2 a.xy b.xy2 c.x2y d.x2y2

Answers

Hmh this seem like a tough one let me see get back with u when i find the answer

Show work
solve x^2-6x= -25

Answers

Answer: x = 3 ± 4i

Step-by-step explanation:

x² - 6x + 25 = 0

a=1 b= -6 c=25

Use Quadratic Formula:

$x = \frac{-b +/- \sqrt{b^(2)-4ac}}{2a}$

$= \frac{-(-6) +/- \sqrt{(-6)^(2)-4(1)(25)}}{2(1)}$

$= (6 +/- √(36-100))/(2)$

$= (6 +/- √(-64))/(2)$

$= (6 +/- 8i)/(2)$

$= (2(3 +/- 4i))/(2)$

= 3 ± 4i

Answer:

x= 3+4i , x= 3-4i

Step-by-step explanation:

x^2-6x= -25

To solve for x we need to make right hand side

So add 25 on both sides

$x^2-6x+25=0$

Now apply quadratic formula

$x=(-b+-√(b^2-4ac))/(2a)$

From the given equation a=1, b=-6 and c=25

Plug in all the values in the formula

$x=(-(-6)+-√((-6)^2-4(1)(25)))/(2(1))$

$x=(6+-√(-64))/(2)$

We know $√(-1) =i$

So equation becomes

$x=(6+8i)/(2)$

Divide by 2

x= 3+-4i

So x= 3+4i , x= 3-4i

Solve x/ x-2 + x+2/ x >2

Answers

$(x)/(x - 2) + (x + 2)/(x) \ \textgreater \ 2$
$(x(x))/(x(x - 2)) + ((x - 2)(x + 2))/(x(x - 2)) \ \textgreater \ 2$
$(x^(2))/(x(x - 2)) + (x^(2) - 4)/(x(x - 2)) \ \textgreater \ 2$
$(x^(2) + x^(2) - 4)/(x(x - 2)) \ \textgreater \ 2$
$(2x^(2) - 4)/(x(x - 2)) \ \textgreater \ 2$
$2x(x - 2) \ \textgreater \ 2x^(2) - 4$
$2x^(2) - 4x \ \textgreater \ 2x^(2) - 4$
$-4x \ \textgreater \ 4$
$x \ \textgreater \ -1$

The weights (to the nearest pound) of some boxes to be shipped are found to be:. Weight 65 68 69 70 71 72 90 95 frequency 1 2 5 8 7 3 2 2 Their mean weight is 72.97 pounds. What is the standard deviation of these weights? The standard deviation, to the nearest tenth, is a0.

Answers

A is the weight
B is the frequency
C is weight times frequency
D is mean minus weight
E is D raised to the 2nd power ; variance
F is E times frequency ; total variance

A B C D E F
65 1 65 7.97 63.47 63.47
68 2 136 4.97 24.70 49.40
69 5 345 3.97 15.76 78.80
70 8 560 2.97 8.82 70.57
71 7 497 1.97 3.88 27.17
72 3 216 0.97 0.94 2.82
90 2 180 17.03 290.02 580.04
95 2 190 22.03 485.32 970.64
30 2,189 1,842.91

2,189 / 30 = 72.97 mean
1,842.91 / 30 = 61.43 variance
√61.43 = 7.8377 or 7.84 standard deviation.

the sum of present ages of ria and abby is 48 years. today abby is 4 years older than shweta. the respective ratio of the present ages of ria and shweta is 4: 7. what was abby's age two years ago?

Answers

Answer:

30 years then.

Step-by-step explanation:

Let the present age of Ria be x and Abby be y, and of Sweta be z.

Then, according to the question,

x + y = 48 ..1

Today, Abby is 4 yrs older than Sweta,i.e.,

y = 4+z.(2)

Also, ratio of present ages of Ria:Sweta

x:z = 4:7
x/z = 4/7
4z = 7x..(3)

Putting the value of y from eqn (2) to eqn 1,

x + 4 + z = 48
x + z = 44( eqn : 4)

From eqn (3),

4z = 7x
x = 4z/7(eqn:5)

Putting the value of x in eqn (4),

4z/7 + z = 44
11z/7 = 44
z = 4*7 = 28

From eqn 5, putting the value of z in it,

x = 4*28/7
x = 4*4 = 16

Putting the value of x in eqn 1,

x+y = 48
y = 48 -16 =32

We have to find the age of Abby two years ago, i.e. 32-2 = 30 years old then back.

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