Given\qquad \overline{OL}\perp\overline{ON}
OL
⊥
ON
start overline, O, L, end overline, \perp, start overline, O, N, end overline
\qquad m \angle LOM = 3x - 15^\circm∠LOM=3x−15
∘
m, angle, L, O, M, equals, 3, x, minus, 15, degrees
\qquad m \angle MON = 5x - 23^\circm∠MON=5x−23
∘
m, angle, M, O, N, equals, 5, x, minus, 23, degrees
Find m\angle MONm∠MONm, angle, M, O, N:
Answers
Segments LO and ON are perpendicular, providing the required
information for the value of the sum of ∠LOM and ∠MON.
- m∠MON is 57°
Reasons:
The given parameter are;
is perpendicular to
;
m∠LOM = (3·x - 15°)
m∠MON = (5·x - 23°)
Required:
Find m∠MOM
Solution:
Given that is perpendicular to
, we have;
m∠LON = 90° by definition of perpendicular lines
m∠LON = m∠LOM + m∠MON by angle addition postulate
Therefore;
m∠LOM + m∠MON = 90° by substitution property of equality
Which gives;
(3·x - 15°) + (5·x - 23°) = 90° by substitution property
8·x - 38° = 90°
x = 16°
m∠MON = 5·x - 23°
m∠MON = 5 × 16° - 23° = 57°
- m∠MON = 57°
Learn more here:
Answer:57
Step-by-step explanation:
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and if a=5
what is b,c,d,and e equal
Answers
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b+d=e
a=5
subsitute
5+b=c
c=b+5
c-5=b
b=c-5 so
c-5+c=d
d=2c-5
b+d=e
c-5+2c-5=e
so
a=5
b=c-5
c=b+5
d=2c-5
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Using the Pythagorean Theorem, the length of a square diagonal, in function of it's sides s, is given by:
The Pythagorean Theorem relates the length of the legs and
of a right triangle with the length of the hypotenuse h, according to the following equation:
In a square, as given in the figure below, the legs are the sides s, of equal measure, while the hypotenuse is the diagonal d, thus:
A similar problem is given at brainly.com/question/21691542
the original Pythagorean theorem is
that means the Pythagorean theorem for this question is: