Suppose that y varies inversely with x and that y=2 when x=8. What is an equation for the inverse variation?

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Answer 1
Answer: x=2 and y=8 Im guessing?

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The farmer's market has a total of 98 tents.  the ratio of food tents to retail tents is 9:5.a. Write a system of linear equations that represent this situation.b.  How many food tents are at the market?c. How many retail tents are at the market?

I have no idea what im doing, please help :,)

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Answer: 2 4 6 4 55567890

What is the correct answer? ​

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Step-by-step explanation:

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There are 5 roads from Allen to baker, 7 roads from baker to Carlson, and 4 roads from Carlson to dodge. How many different routes from Allen to dodge by way of baker and Carlson are possible?

Answers

Answer:

140 routes

Total Number of roads from allen to dodge through baker and Carlson is 140 routes.

Step-by-step explanation:

Given;

Number of roads from Allen to baker = 5

Number of roads from baker to Carlson = 7

Number of roads from Carlson to dodge = 4

Total Number of routes from allen to dodge through baker and Carlson is;

N = 5×7×4

N = 140 routes

Answer:

140 different routes

Step-by-step explanation:

The first path (Allan to Baker) has 5 different options, so there are 5 possibilities. After that, there are 7 possibilities from Baker to Carlson. Then, there are 4 possibilities from Carlson to Dodge. To find the total number of possibilities, we just need to multiply the number of possibilities of each track, so:

5 * 7 * 4 = 140 possibilities, that is, 140 different routes.

In the diagram, ΔGEF and ΔHEF are congruent. What is the value of x?. . 60. . 41. . 28. . 30

Answers

I added a screenshot with the diagram


Answer:

x = 28


Explanation:

When two triangles are congruent, corresponding sides as well as corresponding angles are equal


We are given that:

ΔGEF and ΔHEF are congruent


This means that:

angle G = angle H

angle GEF = angle HEF

angle EFG = angle EFH

GE = HE

GF = HF

EF = EF


We are given that:

angle GFE =60° and angle HFE = 2(x+2)


Since the two angles are equal, we can get x as follows:

2(x+2) = 60

x + 2 = 30

x = 30 - 2

x = 28


Hope this helps :)

If Δ GEF and Δ HEF are congruent than:
2 ( x + 2 ) = 60   / : ( -2 )  we will divide both sides of the equation by -2.
x + 2 = 30
x = 30 - 2
x = 28
Answer : C ) 28° 

Let's write the whole numbers from 90 to 100 . Select the appropriate number to form the following sets . Then , write the type of sets .A={ even number}
B={ odd number}
C={ X:X is a prime numbers}
D={ y:y is a composite number}
E={z:z is a square number}
F={ cube number}
G={ multiples of 7}
H={ X:X is divisible by 11}​

Answers

Answer:

A

The even numbers between 90 and 100 are: 90, 92, 94, 96, 98, 100

B

The odd numbers between 90 and 100 are: 91, 93, 95, 97, 99

C

The prime number between 90 and 100 is: 97

D

The composite numbers between 90 and 100 are: 91, 92, 93, 94, 95, 96, 98 and 99.

E

The square numbers between 90 and 100 are:

90 = 8100

91 = 8281

92 = 8464

93 = 8649

94 = 8836

95 = 9025

96 = 9216

97 = 9409

98 = 9604

99 = 9801

100 = 10000

F

The answer for this is on the attached picture above. Kindly look at it. The cube numbers between 90 and 100.

G

The multiples of 7 between 90 and 100 are: 91 and 98

H

Divisible by 11 (between 90 and 100) is: 99

A={ even number}

B={ odd number}

C={ X:X is a prime numbers}

D={ y:y is a composite number}

E={z:z is a square number}

F={ cube number}

G={ multiples of 7}

H={ X:X is divisible by 11}

꧁Aɴsᴡᴇʀ꧂

A

  • The even numbers between 90 and 100 are: 90, 92, 94, 96, 98, 100

B

  • The odd numbers between 90 and 100 are: 91, 93, 95, 97, 99

C

  • The prime number between 90 and 100 is: 97

D

  • The composite numbers between 90 and 100 are: 91, 92, 93, 94, 95, 96, 98 and 99.

E

  • The square numbers between 90 and 100 are:

90 = 8100

91 = 8281

92 = 8464

93 = 8649

94 = 8836

95 = 9025

96 = 9216

97 = 9409

98 = 9604

99 = 9801

100 = 10000

F

  • The answer for this is on the attached picture above. Kindly look at it. The cube numbers between 90 and 100.

G

  • The multiples of 7 between 90 and 100 are: 91 and 98

H

  • Divisible by 11 (between 90 and 100) is: 99

ʰʰˡˢ

I am a quadrangleI have 2 pairs of parallel sidesall of my angles are right anglesI am not a square

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In that case, it must follow as the night follows the day
that you are none other than a rectangle !