The table below shows data from a survey about the amount of time, in hours, high school students spent reading and the amount of time spent watching videos each week (without reading): Reading Video
3 1
3 2
4 3
5 4
6 6
7 7
10 8
12 8
14 9
30 15

Which response best describes outliers in these data sets?
A, Reading has a suspected outlier in the 30-hour value.
B. Reading has a suspected outlier in the 30-hour value, and video has a possible outlier in the 15-hour value.
C. Neither data set has suspected outliers.
D. The range of data is too small to identify outliers.

Answers

Answer 1

Answer: Reading: 3, 3, 4, 5, 6, 7, 10, 12, 14, 30
Video: 1, 2, 3, 4, 6, 7, 8, 8, 9, 15

Reading Video
Minimum 3 1
1st quartile 4 3
Median 6.5 6.5
3rd quartile 12 8
Maximum 30 15
IQR 8 5
Outliers 30 no outliers

A, Reading has a suspected outlier in the 30-hour value.

Answer 2

Answer:

Answer:

The correct option is: A,B

Step-by-step explanation:

" An outlier is a odd value which on removing from the data leads to the less mean as calculated mean on including that value ".

There are total 10 data points.

The table for reading is given as:

3 3 4 5 6 7 10 12 14 30

The mean of this data is given by:

$(3+3+4+5+6+7+10+12+14+30)/(10)=(94)/(10)=9.4$

Also the mean after omitting the odd value i.e. 30 we get:

$(3+3+4+5+6+7+10+12+14)/(9)=(64)/(9)=7.11$

Hence, there is a change in its mean;

Hence the outlier for reading is 30.

The table for Video is given by:

1 2 3 4 6 7 8 8 9 15

The possible maximum value here is 15 so we will check whether it is an outlier or not.

The mean of this data is given by:

$(1+2+3+4+6+7+8+8+9+15)/(10)=(63)/(10)=6.3$

Also the mean after omitting the odd value i.e. 15 we get:

$(1+2+3+4+6+7+8+8+9)/(9)=(48)/(9)=5.33$

Hence, there is a change in its mean hence 15 is an outlier.

Hence option A and B are true.

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Answers

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Answers

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Answers

Answer:

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Answer:

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Answers

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Answers

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Answer:

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Step-by-step explanation:

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