What is the output value for the following function if the input value is 1?y = 3x + 1

32
5
4
0

Answers

Answer 1
Answer: If you would like to find the output value for the following function if the input value is 1, you can calculate this using the following steps:

input value ... 1
y = 3x + 1 = 3 * 1 + 1 = 3 + 1 = 4

The correct result would be 4.

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What property is -23 x 1 = -23 (I need an answer like distributive property, zero product, additive inverse etc.)

Answers

Answer:

A B

Additive Identity (x) x + 0 = x

Additive Inverse (x) b + (-b) = 0

Multiplicative Identity (x) x • 1 = x

Multiplicative Inverse (x) x • (1/x) = 1

Write an equation with variables on both sides that has no solution. How can you change the equation so that it has infinitely many solutions?

Answers

Answer:

No Solution: 2x + 3 = 4x + 3

Infinite Solutions: 2x + 3 = x + x + 3

Step-by-step explanation:

You're welcome

you have 160 boxes of cookies, in each case you can pack 8 boxes. how many cases will be packed from these cookies ?

Answers

1 case=8 boxes of cookies   and we have 160 boxes
160/8=20
we will have 20 cases

Which of the following equations is of a parabola with a vertex at (0, 3)?

Answers

Parabola has a vertex at: ( 0, 3 )
h = 0, k = 3;
y = a ( x - h )² + k
a = 1
y = ( x - 0 )² + 3
y = x² + 3
Answer:
The parabola with a vertex at ( 0, 3 ) is : y = x² + 3

The equation that is of a parabola with a vertex at (0, -3), is y=x^2+3.

A cyclist travels 3 miles in 15 minutes. what is her average speed in mph

Answers

Answer:

12 mph

Step-by-step explanation:

Step 1: Convert 15 minutes to hours

15/60

1/4

0.25 hours

Step 2: Divide 3 by 0.25 hours

12 mph

On average Exante Express trains are 50km/hr faster than Paral passenger trains. A Paral passenger train requires 60% more time then Exante train to travel 1800 km from Matsay to Rawindi. Calculate average speed of each train. Calculate time it takes for each train for the journey.

Answers

V- average\ speed\ of\ Exante\ Express\ train\nt-travel\ time\ of\ Exante\ Express\ train \n \nV= (S)/(t) \ \ \ \ and\ \ \ V-50= (S)/(t+60\%t) = (S)/(1.6t)\ \ \ \ and\ \ \ S=1800\n \nV= (1800)/(t) \ \ \ and\ \ \ V-50=(1800)/(1.6t)\ \ \ \Rightarrow\ \ \ (1800)/(t)-50= (1125)/(t) \ /\cdot t\n \n1800-50 t=1125\ \ \ \Rightarrow\ \ \ 50t=1800-1125\ \ \ \Rightarrow\ \ \ 50t=675\ /:50\n \nt=13.5\ [h]=13\ [h]\ 30\ [min]\n\n1.6t=21.6\ [h]=21\ [h]+ 0.6\cdot60\ [min]=21\ [h]\ 36\ [min]

V= (1800)/(t) =(1800)/(13,5) =133 (1)/(3) \ [km/h]\approx133.3\ [km/h]\n\nV-50\approx83.3\ [km/h]

Ans.\n average\ speed\ of\ Exante\ Express\ train\ is\ 133.3\ km/h,\ntravel\ time\ of\ Exante\ Express\ train\ is\ 13\ h\ 30\ min;\naverage\ speed\ of\ Paral \ passenger \ train\ is\ 83.3\ km/h,\ntravel\ time\ of\ Paral \ passenger\ train\ is\ 21\ h\ 36\ min