Which constants can be multiplied by the equations so one variable will be eliminated when the systems are added together?5x + 13y = 232
12x + 7y = 218
The first equation can be multiplied by –13 and the second equation by 7 to eliminate y.
The first equation can be multiplied by 7 and the second equation by 13 to eliminate y.
The first equation can be multiplied by –12 and the second equation by 5 to eliminate x.
The first equation can be multiplied by 5 and the second equation by 12 to eliminate x.
Answers
The first equation can be multiplied by -12 and the second equation by 5, to eliminate x.
Let's do this:
(1st equation) 5*x + 13*y = 232 / *(-12)
(2nd equation) 12*x + 7*y = 218 / *(5)
---------------------------------
When multiplied, we get:
(1st equation) -60*x - 156*y = -2784
(2nd equation) 60*x + 35*y = 1090
---------------------------------
Further, first equation now will be obtained when ADDING 1st and 2nd equation together:
(1st equation) -60x+60x-156y+35y=-2784+1090
2nd equation we get from just writing any equation from the beginning, for example, the second one:
(2nd equation) 12*x + 7*y = 218
-----------------------------------------
(1st equation) 0*x - 121*y = -1694
(2nd equation) 12*x + 7*y = 218
------------------------------------------
(1st equation) -121*y = -1694 [x variable is in this step eliminated]
(2nd equation) 12*x + 7*y = 218
----------------------------------------------
(1st equation) y = 1694/121
(2nd equation) 12*x + 7*y = 218
----------------------------------------------
(1st equation) y = 14
(2nd equation) 12*x + 7*14 = 218
----------------------------------------------
(1st equation) y = 14
(2nd equation) 12*x + 98 = 218
----------------------------------------------
(1st equation) y = 14
(2nd equation) 12*x = 218 - 98
----------------------------------------------
(1st equation) y = 14
(2nd equation) 12*x = 120
----------------------------------------------
(1st equation) y = 14
(2nd equation) x = 120/12
----------------------------------------------
(1st equation) y = 14
(2nd equation) x = 10
----------------------------------------------
So, solution of the system of this two equations is obtained, and it is:
(x,y)=(10,14)
Answer:
The first equation can be multiplied by –12 and the second equation by 5 to eliminate x.
Related Questions
WILL GIVE BRAINLIEST FOR RIGHT ANSWER Solve the equation
(17 PTS)GEOMETRY QUESTIONS, PLEASE HELP!
5(x+4)<75Please help me
Solve the equation for x. 2 3 x −1 9 x + 5 = 20 x =
What is the value of c?
[Blank] units
Answers
Answers
Answer:
the least common denominator is 40
Step-by-step explanation:
brainliest pls
Answer:
40
Step-by-step explanation:
because the the LCD of them is 40
Answers
Answer: The Binomial distribution assumes a predetermined number of trials, but the Poisson has no upper limit of possible successes.
Step-by-step explanation:
$93.32
b.
$95.40
c.
$211.33
d.
$253.60
Answers
Answer:
The monthly payment is $93.32 ⇒ answer a
Step-by-step explanation:
* Lets explain how to solve the problem
- The monthly payment is
where:
# P is the loan amount
# r is the rate per period in decimal
# n is the number of periods
- The loan is $3000
- We need to find the monthly payment
∴ P = $3000
- The compound monthly interest is 7.5% for 36 months
∵ The period is 12 (1 year = 12 months)
- Divide the rate as a decimal by 12
∴
∴ r = 0.00625
∴ n = 36
* Lets calculate the monthly payment using the rule above
∵ Monthly payment =
∴ The monthly payment is $93.32
Answer:
$93.32
Step-by-step explanation:
Answers
cross multiply
x=12
12-8 = 4
So there are 4 women in the crew
Answers
The ratio of boys to girls in a school is 5:4. if there are 180 students, how many girls are there?
Let the number of girls and boys be 'x'.
Add 5 and 4
Now, multiply the ratios by 20.
Boys = 20 × 5 = 100
Girls = 20 × 4 = 80.
There were 80 girls.
Hope I helped (:
Have a great day!