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How many grams of water will form if 10.54 g H2 react with 95.10 g O2?

Answers

Answer 1

Answer:

The mass of water that will be produced if 10.54 g of H₂ react with 95.10 g of O₂ is 94.86 g

Balanced equation

2H₂ + O₂ —> 2H₂O

Molar mass of H₂ = 2 × 1 = 2 g/mol

Mass of H₂ from the balanced equation = 2 × 2 = 4 g

Molar mass of O₂ = 2 × 16 = 32 g/mol

Mass of O₂ from the balanced equation = 1 × 32 = 32 g

Molar mass of H₂O = (2×1) + 16 = 18 g/mol

Mass of H₂O from the balanced equation = 2 ×18 = 36 g

SUMMARY

From the balanced equation above,

4 g of H₂ reacted with 32 g of O₂ to produce 36 g of H₂O

How to determine the limiting reactant

From the balanced equation above,

4 g of H₂ reacted with 32 g of O₂

Therefore,

10.54 g of H₂ will react with = (10.54 × 32) / 4 = 84.32 g of O₂

From the calculation made above, we can see that only 84.32 g out of 95.10 g of O₂ given, is needed to react completely with 10.54 g of H₂.

Therefore, H₂ is the limiting reactant.

How to determine the mass of water produced

From the balanced equation above,

4 g of H₂ reacted to produce 36 g of H₂O

Therefore,

10.54 g of H₂ will react to produce = (10.54 × 36) / 4 = 94.86 g of H₂O

Thus, 94.86 g of H₂O were obtained from the reaction.

Learn more about stoichiometry:

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Related Questions

Write a balanced equation for each of the following reactions:the reaction of solid lithium with nitrogen to form solid lithium nitride.the reaction between aqueous solutions of cobalt(III) nitrate and sodium hydroxide to form aqueous sodium nitrate and solid cobalt(III) hydroxide.the reaction between solid zinc and aqueous hydrochloric acid in a single replacement reaction.classify the reactions in (a) and (b).
Why is a molecule of CO2 nonpolar even though the bonds between the carbon atom and the oxygen atoms are polar?(1) The shape of the CO2 molecule is symmetrical. (2) The shape of the CO2 molecule is asymmetrical. (3) The CO2 molecule has a deficiency of electrons. (4) The CO2 molecule has an excess of electrons.
What is the three-dimensional shape of the molecule with this Lewis structure?
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The crystal lattice structure of ionic compounds is responsible for which set of characteristic properties?

What is the approximate pH at the equivalence point of a weak acid-strong base titration if 25 mL of aqueous formic acid requires 29.80 mL of 0.3567 MNaOH? Ka = 1.8×10−4 for formic acid.

Answers

Explanation:

Below is an attachment containing the solution

Answer:

pH= 0.369

Explanation:

The formic acid reacts with NaOH as

HCOOH + NaOH= HCOONa + H2O

Apply CaVa/ CbVb = Na/Nb

Ca×25/(29.8×0.3587) = 1/1

Ca= (29.8×0.3587)/25= 0.428M

pH = - log(H+)

Since only 0ne H+ is in the stoichiometric equation, it means H+ = 0.428M

pH = -log(0.428) =0.369

Which of these statements about enzymes is NOT true? - If enough substrate is added, the normal Vmax of a reaction can be attained even in the presence of a competitive inhibitor.
- When [S] << Km, the reaction is second order and V0 depends on [S] and [Et].
- Their kcat is a second order rate constant.
- The lower their Km, the better they recognize their substrate, but the lower their reaction rate.
- When [S] << Km, V0 depends on [S] and [Et].

Answers

Answer:

1. True. 2. True. 3. Not true. 4. True. 5. True

Explanation:

1. Yes, because if the amount of substrate i much greater than of competitive inhibitor then the probability of substrate to bind to ferment is much higher than of inhibitor (if we have noncompetitive inhibitor it damages the structure of active site and the substrate concentration does not have a role in reaction rate).

2. Yeah, because then the michaelis-menten equation will transform into [tex} V0=(kcat*[E]*[S])/Km [/tex] and it is a second order equation.

3. No, because it is measured in sec-1 and that means it is 1 rate constant.

4. True, if the lower Km the better is binding and due to that rate is slower because it's harder for substrate to unbind.

5. The same as question two.

The standard enthalpy of ________ is the enthalpy change of reaction to form one mole of a substance from its elements under standard conditions of temperature and pressure.

Answers

Formation.
The standard enthalpy of formation occurs under the standard conditions of 298k and 1bar.

GUYS HELP ME PLEASE. MY TEACHER IS GONNA KILL ME IF I DONT SOLVE THIS RIGHT. Write the election configuration (H, Al, S,CI, Ni)

Answers

Explanation:

1s 2s 2p

1s 2s 2p1s2 2s1

1s 2s 2p1s2 2s1 2 1 1

1s 2s 2p1s2 2s1 2 1 11s2 2s2

What types of epithelial cells would you expect to find in an area of the body where diffusion of nutrients needs to occur?1) Cuboidal
2) Columnar
3) Squamous

Answers

The type of epithelial cells that would be found in an area of the body where diffusion of nutrients needs to occur is squamous.

Epithelial cells refer to the cells that are vital in the lining of the surface of the body. Epithelial cells can be found on the blood vessels, skin, and urinary tract.

It should be noted that epithelial cells are important as they act as a protective barrier and help in stopping viruses from getting inside the human body.

It should be noted that squamous can be found in an area of the body where diffusion of nutrients needs to occur. They're flat cells and they are usually thin and resembles the scale of fishes.

In conclusion, squamous can be found on the surface of the skin.

Read related link on:

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Answer: C. Squamous

Explanation:

I got it right on my test...lol

a gas has a volume of 590 mL at a temperature of 590 mL at a temperature of -55.0 degrees Celsius. What volume will the gas occupy at 30.0 degrees Celsius?