One fourth-grade class ate32 slices of pizza for lunch.
Each of the 6 fourth-grade
classes ate the same amount of
pizza. How many slices of pizza
did the fourth graders eat in all?

Answers

Answer 1
Answer:

Answer:

6 times 32 is 192

Step-by-step explanation:

Since there are six classes, and all the classes eat the same amount of food, we know that you would do 6 times X. X is 32, because 1 class ate 32 slices of pizza. So the answer is 32.


Related Questions

What is the combined volume of 2 identical rectangular prisms with the dimension 7 cm x 9 cm x 3 cm?
A towns population went from 25800 to 42600 in 15 years. What was the percent of change
What is the value of 7x-2x+3 when x= 5 ?
HELP ME QUICK! Which fraction is equivalent to 20%? StartFraction 1 Over 20 EndFraction StartFraction 2 Over 20 EndFraction StartFraction 4 Over 20 EndFraction StartFraction 5 Over 20 EndFraction.
How many times does 50,000 go into 37,000,000

What's 97156 divided by 107

Answers

The answer is 908. Your welcome.
97156 ÷ 107 =
908

Hope I Helped!!!

Jordan was trading baseball cards with some friends. He gave 15 cards to Tommy and got 3 back. He gave two thirds of his remaining cards to Elaine and kept he rest for himself m. In the end he had 25 cards. How many baseball cards did he start with?

Answers

87; If he gave two thirds of his remaining cards to Elaine, then he had one third left.  If one third of his remaining cards is 25, then 25 x 3 will give you what he had after trading with Tommy.  When he finished trading with Tommy he had 75 cards.  if he gave away 15 cards, but got three back, then he must have had 87 cards to begin with.

Check your answer:

87-15 = 72

72+3 = 75

2/3 of 75 = 50

75-50 = 25

Great!

Help please because I need help and its confusing

Answers

First sort the number form least to greatest

24,26,27,28,30,30,33,36

To find the mean, we divide to sum of all numbers in the data set by the number of numbers given,'8'.

(24+26+27+28+30+30+33+36)/8=234/8=29.25

Mean=29.25

To find the inter quartile range, we must solve for the lower and upper quartile mean.

Lower Quartile=(24+26+27+28)/4=26.25
Upper Quartile=(30+30+33+36)/4=32.25

32.25=26.25=6

Interquartile range=6

The median is the middle number in the data set, or the sum of the two middle numbers if there isn't a sole middle number

24,26,27,28,30,30,33,36

Median=(28+30)/2=29

Median=29

1st quartile we already solved for...
Lower/1st Quartile=(24+26+27+28)/4=26.25

3rd quartile we already solved for....
Upper/3rd Quartile=(30+30+33+36)/4=32.25

The mean would be most effected by an outlier of 52, the median would only go from 29 to 30. 

Select all the answers that are true for the equation:4x^2-20=0
The equation has two solutions.
One of the answers is -√20.
One of the answers is √5.

Answers

One of the answer is 5

Answer:

5

Step-by-step explanation:

n adult tiger weighs 650 pounds. a baby tiger weighs 2 pounds at birth . Write the ratio of the newborn tigers weight to the adults tigers weight

Answers

1/325. Its just 2/650....

Anybody know the right answer?

Answers

Quadrant I : cot(x) > 0 → -cot(x) < 0

Quadrant II : cot(x) < 0 → -cot(x) > 0

Quadrant III : cot(x) > 0 → -cot(x) < 0

Quadrant IV : cot(x) < 0 → -cot(x) > 0

------------------------------------------------------------------

a)\ \left((11\pi)/(6),\ -\sqrt3\right)\n\n(11\pi)/(6)\in\text{Quadrant IV, then -cot(x)} > 0,\ \text{we have}\ -\cot(11\pi)/(6)=-\sqrt3 < 0

Answer: a)

b)\n(2\pi)/(3)\in\text{Quadrant II},\ -\cot(x) > 0,\ \text{we have}\ (\sqrt3)/(3) > 0\n\nc)\n(5\pi)/(4)\in\text{Quadrant III},\ -\cot(x) < 0,\ \text{we have}\ -1 < 0\n\nd)\n(4\pi)/(3)\in\text{Quadrant III},\ -\cot(x) < 0,\ \text{we have}\ -(\sqrt3)/(3) < 0

We know that one answer is only true, so we did not check the correctness of the cotangent value, only to the number sign