A woman takes her dog Rover for a walk on a leash. She pulls on the leash with a force of 30.0 N at an angle of 29° above the horizontal sidewalk. What force is tending to pull Rover forward, parallel to the horizontal?

Answers

Answer 1

Answer:

Answer:

The force parallel to the horizontal is 26.24 N

Explanation:

She pulls on the leash with a force F = 30 N, this force, since its at an angle of 29° (i will cal this angle $\theta$ ), it has a force component on x (the horizontal, i will call this force $F_(x)$ ) and a force component on y (the vertical, i will call this $F_(y)$ ).

This can be seen in the attached picture.

Since we are asked about the force parallel to the horizontal, we need to find the component of the force $F_(x)$ , since $F_(x)$ is the adjacent angle, we need to use cosine:

$F_(x)=Fcos \theta$

since $F=30N$ and $\theta=29$

$F_(x)=(30N)cos(29)$

$F_(x)=(30N)(0.8746)$

$F_(x)=26.24N$

The force parallel to the horizontal is 26.24 N

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