The following lines are parallel. 2x + 6y = 5 and y = 3x + 8
a. True
b. False

Answers

Answer 1
Answer: To find out whether these lines are parallel or not, we have to calculate the slope. If the slope is same in both equations, then we can say both lines are parallel to each other.
For that purpose, we have to change the format of the equation in this way, y=mx+C.

2x + 6y = 5
y = -1/3 x + 5

y = 3x + 8

Since the slope ( -1/3 and 3 ) of the equations are not equal, these are not parallel to each other.

Answer is b.False

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a paddle boat can move at a speed of 6km/h in still water. the boat is paddeled 16km downstream in a river in the same time it takes to go 8km upstream what is the speed of the river?

Answers

v-the\ speed\ of\ the\ river\n\n16:(6+v)=8:(6-v)\n\n(16)/(6+v)=(8)/(6-v)\n-------------\nmultiply\ on\ the\ cross\n-------------\n8(6+v)=16(6-v)\n\n48+8v=96-16v\n\n8v+16v=96-48\n\n24v=48\ \ \ /:24\n\nv=2\ (km/h)\leftarrow Answer

Point F is on line segment EG. Given EG = 20 and EF = 18, determine the
length FG.

Answers

Answer:

ef \:  +  \: fg \: =  eg \n  \n 18 + fg = 20 \n  \n fg = 20 - 18 \n  \n fg \:  =  \: 2

Answer:

EF+FG =EG

18 + FG =20

FG = 20-18

FG = 2

Expand and simplify: 1.(n-2)(3n+7)+2n(2n+3)

factor each expression fully:
2. 4xsquared-25

Answers

1.\n(n-2)(3n+7)+2n(2n+3)\n\n=n\cdot3n+n\cdot7-2\cdot3n-2\cdot7+2n\cdot2n+2n\cdot3\n\n=3n^2+7n-6n-14+4n^2+6n\n\n=7n^2+7n-14

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2.\n4x^2-25=(2x)^2-5^2=(2x-5)(2x+5)
1.(n-2)(3n+7)+2n(2n+3)
We'll start with (n-2)(3n+7)
Use the FOIL method to simplify: First, Outside, Inside, Last. 
Multiply the first numbers of each bracket (n and 3n), the outside numbers (n and 7), the inside numbers (-2 and 3n) and the last numbers (-2 and 7)
F=  3n×n= 3n²
O= n×7= 7n
I= -2×3n= -6n
L= -2×7= -14
Add them together, you get 3n² + n -14.
The second part is 2n(2n+3)
Multiply both numbers inside the bracket by 2n
2n×2n= 4n²
3×2n= 6n
Add these terms with the previous ones
7n² + 7n -14
Because they all have a common factor of 7, we can represent the equation as 
7(n² + n -2)

2. 4x²-25
To factor this, we convert it into two expressions that we multiply together (like converting -9 into 3×-3)
2x × 2x= 4x²
5 × -5= -25
The answer is (2x+5)(2x-5)

154 sq. cm is the area of a circle
so find its radius
\pi =(22)/(7)

Answers

Answer:

r = 7 cm

Step-by-step explanation:

The area (A) of a circle is calculated as

A = πr² ( where r is the radius )

Given A = 154 , then

πr² = 154 , that is

(22)/(7) r² = 154 ( multiply both sides by 7 to clear the fraction )

22r² = 1078 ( divide both sides by 22 )

r² = 49 ( take square root of both sides )

r = √(49) = 7 cm

What is the image point of (-1,8)(−1,8) after a translation right 1 unit and up 2 units?

Answers

The image point of (-1, 8) after a translation right 1 unit and up 2 units is (0, 10).

To find the image point of (-1, 8) after a translation right 1 unit and up 2 units, we need to add 1 to the x-coordinate and 2 to the y-coordinate of the given point.

The new x-coordinate is (-1 + 1) = 0, and the new y-coordinate is (8 + 2) = 10.

Therefore, the image point of (-1, 8) after the translation is (0, 10).

Learn more about translation here:

brainly.com/question/23277238

#SPJ3

Answer:

(0,10)

Step-by-step explanation:

Im pretty sure bc of subtracting 1 from the -1 in your x vaue and adding 2 to the 8 in you Y value

1. The main show tank has a radius of 70 feet and forms a quarter sphere where the bottom of the pool is spherical and the top of the pool is flat. (Imagine cutting a sphere in half vertically and then cutting it in half horizontally.) What is the volume of the quarter-sphere shaped tank? Round your answer to the nearest whole number. You must explain your answer using words, and you must show all work and calculations to receive credit.2. The holding tanks are congruent. Each is in the shape of a cylinder that has been cut in half vertically. The bottom of each tank is a curved surface and the top of the pool is a flat surface. What is the volume of both tanks if the radius of tank #1 is 35 feet and the height of tank #2 is 120 feet? You must explain your answer using words, and you must show all work and calculations to receive credit.

3. The company is building a scale model of the theater’s main show tank for an investor's presentation. Each dimension will be made one sixth of the original dimension to accommodate the mock-up in the presentation room. What is the volume of the smaller mock-up tank?

Using the information from #3, answer the following question by filling in the blank: The volume of the original main show tank is ____% of the mock-up of the tank.

Answers

Answer:

1. Volume = 5128.67 ft³

The volume if sphere is given by:

V = (4/3)πr³

If the tank is cut into half vertically, then the volume of sphere becomes.

V = (4/3)πr³ / 2

If the tank is cut into half again horizontally, then the volume of the sphere becomes.

V = (4/3)πr³ / 4

Hence, as the main tank forms a quarter sphere, its Volume is given by:

V = (4/3)πr³ / 4

It is given in the question that the radius is 70 ft.

Substitute that in the given formula:

V = (4/3)π(70)³ / 4

V = 5128.67 ft³

 2. Volume of tank = 461,814 ft³

Step-by-step explanation:

Congruent tanks implies that both tanks are of identifical shape, form & dimensions. Congruent means that the tanks have the same radius as well as height. Hence, the heights and radii of tanks #1 and #2 are equal and the same.

Let's list out the information given us:

radius(tank #1) = 35 ft ⇒ radius(tank #2) = 35 ft, height(tank #2) = 120 ft ⇒ height(tank #2) = 120 ft

Volume of cylinder = πr²h

The tanks have been cut into half, as such:

Volume of tank = ½πr²h

Volume of tank = Volume(tank #1) + Volume(tank #2)

Since the tanks are congruent (same dimensions), we have:

⇒ ½πr²h + ½πr²h ⇒ πr²h

Volume of tank =  π * 35² * 120 = 147,000 π

Volume of tank = 461,814 ft³

3.  1047.2 ft³

Step-by-step explanation:

The following information is missing:

The main show tank has a radius of 60 feet and forms a quarter sphere where the bottom of the pool is spherical and the top of the pool is flat. (Imagine cutting a sphere in half vertically and then cutting it in half horizontally)

The only dimension needed for the main show tank is its radius. Then the model radius will be 1/6 * 60 = 10 feet

The volume of a sphere is:

V = 4/3 * π * r³

For a quarter sphere it is:

V = 4/3 * π * r³ * 1/4

V = 1/3 * π * r³

For the smaller mock-up tank:

V = 1/3 * π * 10³

V = 1047.2 ft³