Which products result in a sum or difference of cubes? Check all that apply.A=(x – 4)(x2 + 4x – 16)
B=(x – 1)(x2 – x + 1)
C=(x – 1)(x2 + x + 1)
D=(x + 1)( + x – 1)
E=(x + 4)(x2 – 4x + 16)
F=(x + 4)(x2 + 4x + 16)

Sum of cubes:
(a + b)(a2 – ab + b2) = a3 + b3
Difference of cubes:
(a – b)(a2 + ab + b2) = a3 – b3

Answers

Answer 1

Answer: C and E.
Formulas for sum of cubes and difference of cubes are:
a^3 + b^3 = (a + b) * (a^2 - a*b + b^2)
a^3 - b^3 = (a - b) * (a^2 + a*b + b^2)
-----------------------------------------------------
So, when you check each A, B, C, D, E, F, you can see that ONLY C and E satisfy the operators in both first and second parentheses.

Answer 2

Answer:

Answer:

if you're from edge, the answer is C and E

Step-by-step explanation:

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Which is equivalent to 21.76 grams per minute?

Answers

1.3056 kg/hour

sorry i took so long

Suppose the surface area of a sphere is 324π square units. What is the volume, in cubic units, of this sphereA) 9π
B) 81π
C) 324π
D) 972π

Answers

Answer:

Option D is correct

$972 \pi$ is the volume, in cubic units, of this sphere

Step-by-step explanation:

Surface area of sphere(S) and volume of sphere (V) is given by:

$S = 4 \pi r^2$

$V = (4)/(3) \pi r^3$ .....[1]

As per the statement:

Suppose the surface area of a sphere is 324π square units

⇒S = 324π square units

then;

$324 \pi = 4 \pi r^2$

Divide both side by $4 \pi$ we have;

$81 = r^2$

$r^2= 81$

⇒ $r = √(81) = 9$ units

We have to find the volume, in cubic units, of this sphere.

Substitute the given value in [1] we have;

$V = (4)/(3) \pi \cdot 9^3 = (4)/(3) \pi \cdot 729$

Simplify:

$V = 4 \cdot \pi \cdot 243 = 972 \pi$ cubic units

Therefore, $972 \pi$ is the volume, in cubic units, of this sphere

D would be the answer

Which of the following polygons is not a regular polygon?

Answers

The above is scam. Listen to me the correct answer is the theird.

The LCD for the fractions 1/3, 3/4, 5/32, and 8/9 is A. 3,072.
B. 288.
C. 24.
D. 64.

Answers

The LCD for the fractions 1/3, 3/4, 5/32, and 8/9 is
B. 288.

What is the least common denominator of 4 and 8

Answers

Answer: Least common multiple of 4 and 8 is 8

Find the second derivative for y=(x+2)/(x-3)

Answers

Let's find the first derivative.

Using quotient rule

$f(x)=(g(x))/(h(x))$

$f'(x)=(g'(x)*h(x)-g(x)*h'(x))/(h^2(x))$

then:

$y=(x+2)/(x-3)$
$f(x)=y$

$g(x)=x+2$

$g'(x)=1$

$h(x)=x-3$

$h'(x)=1$

Let's replace

$f'(x)=(g'(x)*h(x)-g(x)*h'(x))/(h^2(x))$

$y'=(1*(x-3)-(x+2)*1)/((x-3)^2)$

$y'=(x-3-x-2)/((x-3)^2)$

$\boxed{y'=(-5)/((x-3)^2)}$

the second derivative is the derivative of our first derivative.

$y'=(-5)/((x-3)^2)$

We can write this function as

$y'=-5*(x-3)^(-2)$

now we have to use the Chain rule's

$f(u)=-5u^(-2)$

and

$g(x)=x-3$

$f[g(x)]=-5*(x-3)^(-2)$

then

$f'[g(x)]=f'(u)*g'(x)$

$f'(u)=-5*(-2)*u^(-3)=10*u^(-3)$

$g'(x)=1$

$f'[g(x)]=f'(u)*g'(x)$

Let's replace

$f'[g(x)]=10*u^(-3)*1$

Let's change u by $(x-3)$

$f'[g(x)]=10*u^(-3)$

$f'[g(x)]=10*(x-3)^(-3)$

$\boxed{\boxed{y''=(10)/((x-3)^(3))}}$

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