If the volume of a container is increased, the pressure of the gas in the container also increases (when the amount of gas and temperature are held constant).TRUE

FALSE

Answers

Answer 1
Answer: False. Because if there is more space in the container for the gas to move, there is less pressure.  There would be a decrease in the pressure.

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Imagine our class has discovered a new element and named it Berkmarium. Berkmarium is known to have 3 naturally occurring isotopes. In nature, 70% of the element is Berkmarium-95, 28% is Berkmarium-97, and 2% is Berkmarium-94. Which isotope will the average atomic mass of Berkmarum be closest to, and why? Support your answer with a calculation.

Answers

Answer:

Detail is given below.

Explanation:

Given data;

Abundance of Berkmarium-95 = 70%

Abundance of Berkmarium-97 = 28%

Abundance of Berkmarium-94 = 2%

Average atomic mass closer to which isotope = ?

Solution:

1st of all we will calculate the average atomic mass of Berkmarium.

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) + (abundance of 3rd isotope × its atomic mass) / 100

Average atomic mass  = (70×95)+(28×97)+(2×94) /100

Average atomic mass =  6650 + 2716+ 188 / 100

Average atomic mass= 9554 / 100

Average atomic mass = 95.54 amu

The average atomic mass is closer to the isotope Berkmarium-95  because it is present in abundance as compared to the other two isotope. So this isotope constitute most of the part of Berkmarium.

How many molecules are in 2.6 grams H4C

Answers

Molar mass of H4C = 1 * 4 + 12 = 16 g/mol

Number of moles:

n = m / mm

n = 2.6 / 16

n = 0.1625 moles

Number of molecules:

number of moles * 6.02x10²³

0.1625 * 6.02x10²³

= 9.78x10²² molecules

hope this helps!



CHEMISTRYWhich of the following properties of an element is least likely to change with beta decay?

A. the mass number
B. the period number
C. the atomic number
D. the name of the element

When a nucleus has too many protons, it can absorb an electron and create _________.

A. a proton
B. a neutron
C. an electron
D. an alpha ray

Which of the following occurs in beta decay?

A. A neutron of an atom emits a high energy proton.
B. A neutron of an atom emits a high energy electron.
C. An electron of an atom emits a high energy proton.
D. A neutron of an atom emits a second high energy neutron.

What kind of ray is given off after electron capture?

A. a beta ray
B. a delta ray
C. an alpha ray
D. a gamma ray

Answers

number 1.c
number 2.a
number 3.b
number 4.d

Answer:

Which of the following occurs in beta decay?

Answer: A neutron of an atom emits a high energy electron.

Explanation:

Via Educere/ Founder's Education

Which compound has the highest melting point? A) octane (C8H18), a molecular compound
B) carbon dioxide (CO2), a common gas
C) water (H2O)
D) silicon carbide (SiC), a network solid

Answers

I think b carbon dioxide

6X, Y and Z are all gases that behave ideally and react according to the equation shown.
X(g) + 2Y(g) → 2Z(9)
When 3.0 mol of X and 3.0 mol of Y are placed inside a container with a volume of 1.0 dmº, they
react to form the maximum amount of Z.
The final temperature of the reaction vessel is 120°C.
What is the final pressure inside the reaction vessel?
А
4.49 x 10 Pa
B
9.80 x 106 Pa
C
1.47 x 10' Pa
D
1.96 x 10' Pa

Answers

Answer:

D

Explanation:

PV=nRT

n=nx + my

n=3mol+3mol

n=6mol

T=120+273=393K

P=nRT/V

P=6×0.0821×393/1

P=193atm

1atm=1.01325×10^5Pa

193atm=xPa

x=1.96×10^7Pa

In the following reaction, how many grams of NaBr will react with 311 grams of Pb(NO3)2?pb(no3)2(aq)+2NaBr(g) -> PbBr2(s) + 2NaNO3(aq)
The molar mass of NaBr is 102.9 grams and that of Pb(NO3)2 is 331.21 grams.

Answers

Answer: 193.4 grams

Explanation: According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number 6.023* 10^(23) of particles.

Pb(NO_3)_2(aq)+2NaBr(g)\rightarrow PbBr_2(s)+2NaNO_3(aq)

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

{\text{Number of moles} of Pb(NO_3)_2}=(311g)/(331.21gmol)=0.94moles

According to stoichiometry

1 mole of Pb(NO_3)_2 reacts with 2 moles of NaBr

0.94 moles of Pb(NO_3)_2 will react with=(2)/(1)* 0.94=1.88moles of NaBr

Mass of NaBr=moles* {\text {molar mass}}=1.88* 102.9=193.4g

Answer:

193.24g

Explanation:

Step 1:

The balanced equation for the reaction. This is illustrated below:

Pb(NO3)2(aq) + 2NaBr(g) -> PbBr2(s) + 2NaNO3(aq)

Step 2:

Determination of the masses of Pb(NO3)2 and NaBr that reacted from the balanced equation. This is illustrated below:

Molar Mass of Pb(NO3)2 = 331.21g/mol

Molar Mass of NaBr = 102.9g/mol

Mass of NaBr from the balanced equation = 2 x 102.9 = 205.8g.

From the balanced equation,

Mass of Pb(NO3)2 that reacted = 331.21g

Mass of NaBr that reacted = 205.8g

Step 3:

Determination of the mass of NaBr that reacted with 311g of Pb(NO3)2. This is illustrated below:

From the balanced equation above,

331.21g of Pb(NO3)2 reacted with 205.8g of NaBr.

Therefore, 311g of Pb(NO3)2 will react with = (311x205.8)/331.21 = 193.24g of NaBr.

From the calculations made above, 193.24g of NaBr will react with 311g of Pb(NO3)2