Answer:
C. It is a negative ion that has one more valence electron than a neutral bromine atom.
Explanation:
took test
When balancing the nuclear reaction, explain the following:
How does the Law of Conservation of Matter dictate what the daughter nuclide is?
How do we calculate the atomic mass and atomic number for the daughter nuclide?
Where do we look up what the new daughter nuclide element is?
The balanced nuclear reaction is 234/91 Pa -> 4/2 He + 230/89 Ac. You calculate the atomic mass and atomic number of the daughter nuclide by subtracting the atomic mass and atomic number of the alpha particle from the parent nuclide. Then, refer to the periodic table to identify the element with the corresponding atomic number.
The process described in the question is a typical alpha decay nuclear process. In this reaction, a Protactinium-234 nuclide emits an alpha particle (which is a Helium nucleus) to produce a new nuclide, the daughter nuclide.
According to the Law of Conservation of Matter, the sum of the mass and atomic numbers (protons + neutrons) of the reactants must equal the sum of the mass and atomic numbers of the products. This means we can calculate the atomic number and atomic mass of the daughter nuclide. The atomic mass would be the difference: 234 - 4 = 230. The atomic number would be the difference: 91 - 2 = 89.
After that, you can identify the new element by its atomic number, 89, from a periodic table, which shows it to be Actinium (89/230 Ac).
So, the balanced nuclear reaction is: 234/91 Pa -> 4/2 He + 230/89 Ac
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at 100 degrees Celsius. Calculate the amount of heat required for this
conversion.
3. A student measured 15.0 grams of ice in a beaker. The beaker was then
placed on a hot plate where it was heated uniformly for a certain amount
of time. During the melting process of the ice, the student noted that the
temperature was at 0 degree Celsius. When all the ice converted to water,
the final temperature was also at 0 degree Celsius. How much heat was
used to melt the ice?
4. If 5.0 grams of water was cooled from 50 degrees Celsius to 40
degrees Celsius, then calculate the amount of heat released by the water.
5. A certain amount of water used exactly 84.0 Joules of heat energy to
change from 25.0 degrees Celsius to 35 degrees Celsius. How many
grams of water was used?
Please help me
Answer:
Explanation:
1 )
amount of heat required = mass x specific heat x rise in temperature
= 25 x 4.2 x 20 = 2100 J .
2 )
Amount of heat required
= mass x latent heat of vaporisation
= 50 x 2260 = 113000 J .
3 )
Amount of heat required in melting the ice
= mass x latent heat of fusion
= 15 x 336 = 5040 J
4)
heat released in cooling water
= mass x specific heat x fall in temperature
= 5 x 4.2 x 10
= 210 J
5 )
amount of heat required = mass x specific heat x rise in temperature
84 = mass x 4.2 x 10
mass = 2 grams .
Explanation:
The electron configuration you provided is for the element with 3 electrons. The 2p² electron configuration would involve adding two more electrons to the 2p subshell. Let's determine the four quantum numbers (n, l, ml, and ms) for one of these 2p² electrons:
1. Principal Quantum Number (n): In this case, n is the same as the principal quantum number for the 2p subshell, which is 2.
2. Azimuthal Quantum Number (l): The azimuthal quantum number (l) represents the subshell within the principal energy level. For the 2p subshell, l = 1.
3. Magnetic Quantum Number (ml): The magnetic quantum number (ml) specifies the orientation or orbital within a subshell. For the 2p subshell, ml can take on three values: -1, 0, and 1. Since we're describing one of the two 2p² electrons, you can choose either -1 or 1 for ml.
4. Spin Quantum Number (ms): The spin quantum number (ms) represents the spin of the electron. It can have two values: +1/2 (spin up) or -1/2 (spin down). You can choose either +1/2 or -1/2 for ms.
So, one possible set of quantum numbers for one of the 2p² electrons could be:
n = 2
l = 1
ml = 1 (or -1)
ms = +1/2 (or -1/2)
You can choose either ml = 1 and ms = +1/2 or ml = -1 and ms = -1/2 for one of the 2p² electrons, as long as the other electron in the same orbital has the opposite spin.
The quantum numbers of an electron in the 2p orbital with the electron configuration 1s² 2s² 2p¹ are principal quantum number (2), azimuthal quantum number (1), magnetic quantum number (-1, 0 or 1) and spin quantum number (+1/2 or -1/2). These numbers represent the energy level, orbital shape, orbital orientation and electron's spin respectively.
The electron configuration expressed as 1s² 2s² 2p¹ represents how electrons are distributed in an atom's atomic orbitals. Examining this, it indicates that there are two electrons in the 1s orbital, two electrons in the 2s orbital, and one electron in the 2p orbital. The four quantum numbers of the electron in the 2p orbital are principal quantum number (n), azimuthal quantum number (l), magnetic quantum number (m_l), and spin quantum number (m_s).
The principal quantum number (n), denotes the energy level the electron is in, in this case, 2.
The azimuthal quantum number (l), also, known as the orbital quantum number indicates the shape of the orbital, for a 'p' orbital, l = 1.
The magnetic quantum number (m_l), describes the orientation of the orbital - this can have any value from -l to +l. For a 'p' orbital, m_l could be -1, 0, or 1, representing the three 'p' orbitals, 2px, 2py, and 2pz respectively.
Finally, the spin quantum number (ms) will be either +1/2 or -1/2, representing the two possible spin states of an electron.
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