The process of gas converting to a liquid is called evaporation.

TRUE

FALSE

Answers

Answer 1

Answer: False. Because gas to a liquid is called condensation

Related Questions

This is the equation for the combustion of propane.C3H8 + 5O2 → 3CO2 + 4H2O + heatWhich are the reactants and the products in this reaction?A.The reactants are C3H8 (propane) and H2O (water). The products are O2 (oxygen) and CO2 (carbon dioxide).B.The reactants are C3H8 (propane) and O2 ( oxygen). The products are CO2 (carbon dioxide) and H2O (water).C.The reactants are CO2 (carbon dioxide) and H2O (water). The products are C3H8 (propane) and O2 ( oxygen).D.The reactants are O2 (oxygen) and CO2 (carbon dioxide). The products are C3H8 (propane) and H2O (water).
Which of the following is not an example of a polymer?Select one: a. Polystyrene b. Nylon c. Sucrose d. PVC
Find the mistake Cu(NO3)2(s) + CuO(s) → 2NO(g) + O3(g)
Name two compounds in unpolluted air?
Why do chloride ions move to the positive electrode?

Which of the following molecules contains a covalent bond? (Use the electronegativity values from the periodic table link to help you answer this question.)A. HF
B. LiCl
C. CN-
D. MgO.)

Answers

If the electronegativity difference is less than 1.6 or when the difference is 1.6 - 2.0 and it only involves nonmetal, then the molecule contains a covalent bond.
A. HF: 4.0 - 2.1 = 1.9 (Covalent)
B. LiCl: 3.16 - 0.96 = 2.2 (Non-covalent)
C. CN-: 3.04 - 2.65 = 0.39 (Covalent)
D. MgO: 3.44 - 1.31 = 2.13 (Non-covalent)

Answer:

C APEX APPROVED

Explanation:

2.0 g of H2 gas reacts with 32 g of O2 gas to form water. Assuming the reaction goes to completion, how many grams of water will be produced?

Answers

In order to solve this problem, the balanced chemical equation of the reaction must be used. This gives the equation:

2H2 + O2 --> 2H2O

Next, the moles of the reactants must be used in order to apply their stoichiometric relationships. Note that 1 mole of oxygen needs 2 moles of hydrogen for the reaction proceed. Since there is only 1 mole of H2, only 0.5 moles of oxygen are consumed.

moles H2 = 2 g/ 2g/mol = 1 mole H2
moles O2 = 32 g/ 32g/mol = 1 mole O2

2H2 + O2 --> 2H2O
i 1 1 0
c 1 0.5 1
e 0 0.5 1

Assuming the reaction will proceed, there will be an excess of 0.5 mol O2 and a product of 1 mol H2O. This gives 18 grams of water.

What is the value of mass of electron?for which has 6.25 × 10^18?

Answers

Answer: the mass of an electron is approximately 9.10938356 × 10^-31 kilograms (kg)

Explanation:

Experimental data are collected as: x[100]={1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99, 100}; y[100]={-92.3973,14.0677,98.9626,49.6151,111.88,-38.7967,52.1535,-101.325,65.6111,125.129,151.762, -123.132,-41.8744,-39.3356,-99.7856,-128.881,58.5477,-111.692,-75.3057,4.4723,-100.051,169.051, -15.6953,58.3125,147.346,10.9835,42.3421,166.697,-105.534,-90.2199,151.189,130.022,-8.1448,-51.3493, 164.427,119.154,-99.2704,155.986,133.212,118.035,13.1819,139.678,81.5178,-12.4377,-11.7671,146.627, -25.787,107.25,19.8867,15.6437,112.871,122.552,8.42037,-10.1364,146.682,178.531,203.565,-70.7871, 171.256,-50.6232,193.836,-34.7733,-68.9564,25.3423,75.6537,21.5484,46.5259,-64.22,-13.5792, 74.9213,-26.6872,30.5302,169.534,-36.7224,65.4419,113.978,68.1137,181.414,127.76,145.447,75.5486, 164.201,169.504,110.07,96.713,114.974,155.46,2.72803,-59.9407,13.426,29.9344,-11.052,176.639, 162.505,-18.3784,184.418,234.104,127.227,145.18,0.440172}; Obtain the regression line in the form of y = a x + b.

Answers

hi myself thx for the answers

Use Hess's law and the following equations to calculate the ΔHreaction for the reaction CO(g) + 3H2(g) CH4(g) + H2O(g). (Show your work.) (4 points) • C(s) + O2(g) CO(g) ΔH = –110.5 kJ • C(s) + 2H2(g) CH4(g) ΔH = –74.85 kJ • H2(g) + O2(g) H2O(g) ΔH = –241.83 kJ

Answers

Answer: The enthalpy of reaction is, -206.18 kJ

Explanation:-

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The final reaction is

$CO(g)+3H_2(g)\rightarrow CH_4(g)+H_2O(g)$ $\Delta H_(rxn)=?$

The intermediate balanced chemical reaction will be,

(1) $C(s)+(1)/(2)O_2(g)\rightarrow CO(g)$ $\Delta H_1=-110.5kJ$

(2) $C(s)+2H_2(g)\rightarrow CH_4(g)$ $\Delta H_2=-74.85kJ$

(3) $H_2(g)+(1)/(2)O_2(g)\rightarrow H_2O(g)$ $\Delta H_3=-241.83kJ$

Now adding (2) and (3) and subtracting (1) , we get :

$\Delta H_(rxn)=(\Delta H_2+\Delta H_3)-\Delta H_1$

$\Delta H_(rxn)=((-74.85)+(-241.83))-(-110.5)$

$\Delta H_(rxn)=-206.18kJ$

Therefore, the enthalpy of reaction is, -206.18 kJ

Final answer:

To calculate the ΔHreaction for the given reaction using Hess's Law, we need to manipulate the given equations and sum up the ΔH values. After manipulating the equations and summing up the ΔH values, the ΔHreaction is -280.03 kJ.

Explanation:

To calculate the ΔHreaction for the given reaction, we can use Hess's Law. We need to manipulate the given equations to match the overall reaction. Since the overall reaction involves CO, H2, CH4, and H2O, we can use the given equations as follows:

Reverse the equation for CO(g) + O2(g) → CO(g) to get CO(g) → C(s) + O2(g).
Double the equation for C(s) + 2H2(g) → CH4(g) to get 2C(s) + 4H2(g) → 2CH4(g).
Leave the equation for H2(g) + O2(g) → H2O(g) as is.

Add up the manipulated equations and their respective ΔH values:

CO(g) → C(s) + O2(g) (ΔH = 110.5 kJ)
2C(s) + 4H2(g) → 2CH4(g) (ΔH = -2 * 74.85 kJ = -149.7 kJ)
H2(g) + O2(g) → H2O(g) (ΔH = -241.83 kJ)

Now, sum up the ΔH values:

110.5 kJ + (-149.7 kJ) + (-241.83 kJ) = -280.03 kJ

Therefore, the ΔHreaction for the reaction CO(g) + 3H2(g) → CH4(g) + H2O(g) is -280.03 kJ.

Learn more about Hess's Law here:

brainly.com/question/33958417

#SPJ3

Which of the following measurements has three significant figures?A. 5100 m
B. 0.005 m
C. 0.510
D. 0.051

Answers

The correct answer is C: 0.510 m

N I C E - D A Y!

Answer:

Explanation:

a) has 2 sig. figures

b) has 1 sig. figures

c) has 3 sig. figures

d) has 2 sig. figures

Other Questions

What would be the mass of 9.65x1025 molecules of water

When the equation H2S + HNO3 → S + NO + H2O is balanced, what is the coefficient for H2O?

What is mean by scientific approach in chemistrybrief it

Place the terms compounds; mixtures, and elements in the proper sequence according to increasing complexity

The process of gas converting to a liquid is called evaporation. TRUE FALSE

Answers

Related Questions

Answers

Answers

Answers

Answers

Answers

Final answer:

Explanation:

Learn more about Hess's Law here:

Answers

The process of gas converting to a liquid is called evaporation.

TRUE

FALSE