What should be place in _C6H12O6(s) + _O2(g) mc018-1.jpg _CO2(g) + _H2O(l)

Answers

Answer 1

Answer: I am thinking that you are asking for the balanced equation for this chemical reaction. In order to balance this, you have to count each element where the elements in the reactants side and the product side should have equal number of molecules. The balanced reaction is as follows:

C6H12O6(s) + 6O2(g) = 6CO2(g) + 6H2O(l)

Answer 2

Answer:

Answer: $C_6H_(12)O_6(s)+6O_2(g)\rightarrow 6CO_2(g)+6H_2O(l)$

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

Combustion of glucose is represented by following balanced equation:

$C_6H_(12)O_6(s)+6O_2(g)\rightarrow 6CO_2(g)+6H_2O(l)$

where (s) represents solid state, (g) represents gaseous state and (l) represents liquid state.

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2. A magnifying glass is an example of a _______ lens.A. converging
B. double-concave
C. plano-convex
D. plano-concave
Student Answer: C
Answer: Incorrect
Reference:

3. If the distance from a converging lens to the object is less than the focal length of the lens, the image will be _______ the object.
A. real, inverted, and smaller than
B. virtual, upright, and larger than
C. virtual, upright, and smaller than
D. real, inverted, and larger than
Student Answer: A
Answer: Incorrect
Reference:

4. Which of the following values represents an index of refraction of an actual material?
A. .25
B. 0
C. .5
D. 1.25
Student Answer: C
Answer: Incorrect
Reference:

5. Which, if any, of these mirrors can produce a real image?
A. Plane
B. Convex spherical
C. No mirrors can produce a real image.
D. Concave spherical
Student Answer: A
Answer: Incorrect
Reference:

6. When white light is incident on a prism, which one of the resulting color components will have the lowest index of refraction?
A. Yellow
B. Blue
C. Green
D. Orange
Student Answer: C
Answer: Incorrect
Reference:

12. Which of the following is not a reason fluorescent lamps are advantageous over incandescent lamps?
A. Fluorescent lamps operate at a higher temperature than incandescent lamps.
B. Fluorescent lamps are more efficient than incandescent lamps.
C. Fluorescent lamps dissipate more energy as light instead of heat than incandescent lamps.
D. Fluorescent lamps produce light with less glare than incandescent lamps.
Student Answer: B
Answer: Incorrect
Reference:

15. Which of the following is not a characteristic of electromagnetic waves?
A. They can travel through a vacuum.
B. They can be refracted.
C. They can be reflected.
D. They can travel at various speeds through any one material.
Student Answer: B
Answer: Incorrect
Reference:

16. A ray at which angle would produce the most glare?
A. 37 degrees
B. 70 degrees
C. 25 degrees
D. 59 degrees
Student Answer: B
Answer: Incorrect
Reference:

18. Which of the following statements is true of glare control?
A. Using bulbs that aren't frosted will help to diffuse the light and reduce glare.
B. Special care must be taken to prevent glare where a low illuminance is required.
C. Redirecting lamp fixtures and adjusting bulb types will do little to control glare.
D. Indirect lighting is preferred to direct lighting because it produces less glare.
Student Answer: C
Answer: Incorrect
Reference:

19. Which of the following objects uses two converging lenses to produce two images, the second of which is virtual, magnified, and inverted?
A. Slide projector
B. Compound microscope
C. Corrective eyeglasses
D. Camera
Student Answer: D
Answer: Incorrect
Reference:

20. The light intensity of a source is 100 candelas. The illuminance on a surface is 4 lux. How far is the surface from the source?
A. 4 meters
B. 6 meters
C. 5 meters
D. 7 meters
Student Answer: B
Answer: Incorrect

Answers

The answer to question 2 is C. A magnifying glass is an example of a plano-convex lens, where one side of the lens is flat and the other is a convex curve. The answer to question 3 is either B or C. A converging lens is curved on both sides and so the rays of light coming out of it converge at a point, which is known as the focal point. When the object is inside the focal point, the image is real and inverted. If it is inside the focal point, the image is virtual and upright. Therefore the image in this question will be upright. The focal length is the distance between the image that is being magnified and the centre of the magnifying lens. A real image can only be formed when the object is further away from the lens than the focal length. Therefore, in this question, the image is virtual, as the object is closer to the lens than the focal length. The answer to question 4 is D because the index of refraction cannot be less than 1. The answer to question 5 is D because only concave mirrors can produce real images; other types produce virtual images. For question 6, the answer is D. In the rainbow, each of the colours refracts at a slightly different angle; red has the smallest refractive index and violet the largest. Of the options, orange is closest to red. For question 12, A is the answer. A higher operating temperature is not a reason fluorescent lamps are better than incandescent lamps because they have a lower operating temperature. Question 15: all of these are characteristics of different electromagetic waves. For question 18, B is true - special care must be taken when low illuminance is required to reduce glare. The answer to question 19 is B - a compound microscope makes use of two lenses. For question 20, the answer is 5 meters away. The illuminance (E) is equal to light intensity (I) divided by the square distance from the light source (d). Therefore, 4 = 100/d squared. To switch this around, d squared is equal to 100/4 = 25. Then find the square root of 25, which is 5.

Select all that apply.1: Which of the following particles are of approximately equal mass?

A: protons
B:electrons
C:neutrons
D:quarks
------------------------------------------------------------------------------------------------------------------------------
2: If the atomic number of an element is 16, then it has 16 electrons.

True
False
------------------------------------------------------------------------------------------------------------------------------

3: An unknown substance is tested and found to have the following physical properties:

brittle
fair conductor of electricity
dull (not shiny)

The substance is most likely a _____.

A:metal
B:metalloid
C:nonmetal
D:can not be determined without more data
---------------------------------------------------------------------------------------------------------------------------

Answers

1)Protons and Neutrons have approximately equal masses

2)TRUE

3) B-Metalloid

Answer:

its a and b

Explanation:

i got it right on test

Describe the sequence of events in the formation of an evaporite

Answers

- Water enter from creeks, bringing whatever material it has dissolved in its way

- The materials is being build up throughout time in the lake or sea, causing its salinity to increase

- when this saline solution is evaporated, the ions in the water precipitate, forming an evaporite

Sediments are buried, pressure increases, volume of sediment decreases, sandstone compresses, saline solution becomes evaporated,and thenforms an evaporite.

What is an evaporite?

An evaporite can be defined as a mineral deposit containing saline substances that are produced due to the evaporation of a water body.

In this context, the sequence of events in the formation of an evaporite are listed as follows:

Sediments are buried.
Increase pressure pushes the grains closer together.
Decrease in the volume of sediment, which cause fluids between the grains to be squeezed out.
Sandstone are left tightly compressed together.
The saline solution becomes evaporated, and then the ions contained in the water precipitates, forming an evaporite.

Read more on evaporite here: brainly.com/question/506772

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a student used 10 mL water instead of 30 mL for extraction of salt from mixture. How may this change the percentage of NaCl extracted?

Answers

It will be extracted only 1/3 of NaCl less in 10 mL of water than in 30 mL of water.

If it is known that solubility of NaCl is 360 g/L, let's find out how many NaCl is in 30 mL of water:

360 g : 1 L = x g : 30 mL

Since 1 L = 1,000 mL, then:
360 g : 1,000 mL = x g : 30 mL

Now, crossing the products:
x · 1,000 mL = 360 g · 30 mL
x · 1,000 mL = 10,800 g mL
x = 10,800 g ÷ 1,000
x = 10.8 g

So, from 30 mL mixture, 10.8 g of NaCl could be extracted.

Let's calculate the same for 10 mL water instead of 30 mL.

360 g : 1 L = x g : 10 mL

Since 1 L = 1,000 mL, then:
360 g : 1,000 mL = x g : 10 mL

Now, crossing the products:
x · 1,000 mL = 360 g · 10 mL
x · 1,000 mL = 3,600 g mL
x = 3,600 g ÷ 1,000
x = 3.6 g

So, from 10 mL mixture, 3.6 g of NaCl could be extracted.

Now, let's compare:
If from 30 mL mixture, 10.8 g of NaCl could be extracted and from 10 mL mixture, 3.6 g of NaCl could be extracted, the ratio is:
3.6/10.8 = 1/3

Therefore, it will be extracted only 1/3 of NaCl less in 10 mL of water than in 30 mL of water.

f chlorine gas is bubbled through an aqueous solution of sodium iodide, the result is elemental iodine and aqueous sodium chloride solution. What kind of reaction took place?

Answers

If chlorine gas is bubbled through an aqueous solution of sodium iodide, the result is elemental iodine and aqueous sodium chloride solution. The kind ofreaction that took place is decomposition reaction. Because sodium iodide is broken down into sodium and iodide atoms.

When calcium carbonate is added to hydrochloric acid, calcium chloride, carbon dioxide, and water are produced. CaCO3 ( s ) + 2 HCl ( aq ) ⟶ CaCl2 ( aq ) + H 2 O ( l ) + CO 2 ( g ) How many grams of calcium chloride will be produced when 30.0 g of calcium carbonate is combined with 10.0 g of hydrochloric acid

Answers

Answer: The mass of $CaCl_2$ produced is, 15.2 grams.

Explanation : Given,

Mass of $CaCO_3$ = 30.0 g

Mass of $HCl$ = 10.0 g

Molar mass of $CaCO_3$ = 100 g/mol

Molar mass of $HCl$ = 36.5 g/mol

First we have to calculate the moles of $CaCO_3$ and $HCl$ .

$\text{Moles of }CaCO_3=\frac{\text{Given mass }CaCO_3}{\text{Molar mass }CaCO_3}$

$\text{Moles of }CaCO_3=\frac{\text{Given mass }CaCO_3}{\text{Molar mass }CaCO_3}=(30.0g)/(100g/mol)=0.300mol$

and,

$\text{Moles of }HCl=\frac{\text{Given mass }HCl}{\text{Molar mass }HCl}$

$\text{Moles of }HCl=\frac{\text{Given mass }HCl}{\text{Molar mass }HCl}=(10.0g)/(36.5g/mol)=0.274mol$

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

$CaCO_3(s)+2HCl(aq)\rightarrow CaCl_2(aq)+H_2O(l)+CO_2(g)$

From the balanced reaction we conclude that

As, 2 mole of $HCl$ react with 1 mole of $CaCO_3$

So, 0.274 moles of $HCl$ react with $(0.274)/(2)=0.137$ moles of $CaCO_3$

From this we conclude that, $CaCO_3$ is an excess reagent because the given moles are greater than the required moles and $HCl$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $CaCl_2$

From the reaction, we conclude that

As, 2 mole of $HCl$ react to give 1 mole of $CaCl_2$

So, 0.274 mole of $HCl$ react to give $(0.274)/(2)=0.137$ mole of $CaCl_2$

Now we have to calculate the mass of $CaCl_2$

$\text{ Mass of }CaCl_2=\text{ Moles of }CaCl_2* \text{ Molar mass of }CaCl_2$

Molar mass of $CaCl_2$ = 110.98 g/mole

$\text{ Mass of }CaCl_2=(0.137moles)* (110.98g/mole)=15.2g$

Therefore, the mass of $CaCl_2$ produced is, 15.2 grams.

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