For the following data distribution, find the value that best defines the central tendency of the distribution and characterize the distribution.{23, 29, 12, 14, 27, 23, 23, 18, 23, 1, 7, 18, 43, 24, 28, 17, 32, 33, 38}
Answers
After graphing the data, the distribution is a bit skewed to the right although it could be considered symmetrical.
Here are the values that define the central tendency:
mean = 22.79
median = 23
mode = 23
The three are almost equal. So, the distribution can be classified as symmetrical.
Answer:
Step-by-step explanation:
The given data set is:
23, 29, 12, 14, 27, 23, 23, 18, 23, 1, 7, 18, 43, 24, 28, 17, 32, 33, 38
firstly arrange the given data set in ascending order, we have
1, 7, 12, 14, 17, 18, 18, 23, 23, 23, 23, 24, 27, 28, 29, 32, 33, 38, 43
Now, Mode is the observation point which occurs frequently in the given data set, thus
Mode=23
Mean is given as:
≈
Median of the given data set is the middle value of the given set, thus
Median=23
Hence, the value that would best describe the central tendency is 23. Since, the values to the left of 23 are more scattered than those to its right, the distribution exhibits negative.
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Determine the equation in the form y=mx+b for passing through each pair of points (0,8) and (4,3)
Is 0.21 less or greater than half
Where does the irrational number 1.8693… fall? A. Between 0.1 and 1.1, while being closer to 1.1 B. Between 8.1 and 9.1, while being closer to 9.1 C. Between 1.6 and 1.8, while being closer to 1.8 D. Between 1.8 and 1.9, while being closer to 1.9
Answers
Answer:
2/1 or 2
Step-by-step explanation:
m(slope)= y2-y1/ x2-x1
i hope this helps
Answers
State B 14 12 10 13 15 14 11 15 16
Part A: Create a five-number summary and calculate the interquartile range for the two sets of data. (6 points)
Part B: Are the box plots symmetric? Justify your answer. (4 points
Answers
State A: 4, 5, 6, 6, 7, 8, 9, 21, 25
State B: 10, 11, 12, 13, 14, 14, 15, 15, 16
5 number summary:
State A State B
minimum 4 10
Q1 5.5 11.5
median 7 14
Q3 15 15
maximum 25 16
IQR 9.5 3.5
The box plot are not symmetric. The distance of the median from each Q1 and Q3 should be equal for the box plot to be symmetric.
Answers
Answer: B. 4,000
Step-by-step explanation:
Given: The initial amount of bacteria in the dish A= 500
Since, The amount of bacteria in the dish doubles every 3 hours.
The multiplicative rate of change after every 3 hours = 2
Time period = 3 hours
By exponential function, we have the amount of bacteria after time period 'x' is given by :-
, where A is the initial amount , b is the multiplicative rate of change in time period x.
Number of 3 hours period in 9 hours = 3
Therefore, x=3
Therefore, the amount of bacteria in the dish after 9 hours is given by :_
*3
*3 = 13500
Answers
Let us assume that the number of books Jan bought = x
the number of magazines Jan bought = y
Then
x + y = 6
x = 6 - y
and
3x + 2.5y = 16
Replacing the value of x from the first equation in the second we get
3x + 2.5y = 16
3(6 - y) + 2.5y = 16
18 - 3y + 2.5y = 16
- 0.5y = -2
y = 2/0.5
= 4
Replacing the value of y in first equation we get
x + y = 6
x + 4 = 6
x = 2
So Jan bought 2 books and 4 magazines.
Answer:
She bought 2 books and 4 magazines
b. Write a two-step ordered-pair rule, for the transformation sequence.
Answers
Answer:
a) Δ ABC is rotated around the origin by angle 180° and then translated 1
unite to the right and 3 units up
b) R (O , 180°) and T (x + 1 , y + 3)
Step-by-step explanation:
* Lets revise some transformation
- If point (x , y) rotated about the origin by angle 180° then its image
is (-x , -y)
- If the point (x , y) translated horizontally to the right by h units
then its image is (x + h , y)
- If the point (x , y) translated horizontally to the left by h units
then its image is (x - h , y)
- If the point (x , y) translated vertically up by k units
then its image is = (x , y + k)
- If the point (x , y) translated vertically down by k units
then its image is (x , y - k)
* Lets solve the problem
∵ Δ ABC change its place from 2nd quadrant to the 4th quadrant
and reverse its direction Point A up and its image A" down
∵ No change in its size
∴ Triangle ABC rotates 180° clockwise around the origin
# Remember : There is no difference between rotating 180° clockwise
or anti-clockwise around the origin
∵ The vertices of Δ ABC are:
# A = (-3 , 5)
# B = (-3 , 2)
# C = (-1 , 2)
∵ If point (x , y) rotated about the origin by angle 180° then its image
is (-x , -y)
∴ A'' = (3 , -5)
∴ B'' = (3 , -2)
∴ C'' = (1 , -2)
∴ Triangle ABC rotates 180° around the origin to form ΔA"B"C"
∵ The vertices of Δ A'B'C are:
# A' = (4 , -2)
# B' = (4 , 1)
# C' = (2 , 1)
- By comparing the x-coordinates and y-coordinates of points of
Δ A''B''C'' and Δ A'B'C' we will find that every x-coordinate add by 1
and every y-coordinate add by 3
∵ 4 - 3 = 1 and 2 - 1 = 1 ⇒ x- coordinates
∵ -2 - (-5) = -2 + 5 = 3 and 1 - (-2) = 1 + 2 = 3 ⇒ y-coordinates
∴ ΔA''B''C'' translates to the right 1 unite and up 3 units to form
Δ A'B'C'
a) Δ ABC is rotated around the origin by angle 180° and then
translated 1 unite to the right and 3 units up
b) R (O , 180°) and T (x + 1 , y + 3)