CHEMISTRY HIGH SCHOOL

Which would most likely be the pH of a highly-corrosive acid

Answers

Answer 1

Answer: The answer is 1, (if it isn't, tell me the answer choices)

Answer 2

Answer:

Answer:

a) 1

Explanation:

got it right 100%

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Chemists use activity series to determine whether which type of reaction will occur?

Answers

Answer:

The correct answer is "single replacement".

Explanation:

The activity series is a representation of a series of metals that are organized according to their order of reactivity. They start from the highest order of reactivity to the lowest order of reactivity.

The purpose of the series is to determine which products are formed in single-displacement reactions. The higher-order metals replace the lower order metals if there are two of them in the same solution. If metal is higher in the series it is more reactive than a metal that is below it in the activity series.

Have a nice day!

Which sequence describes the result of increasing the number of gas particles in a container? A.) fewer collisions --> lower collision force --> lower pressure B.)more collisions --> lower collision force --> lower pressure. C.) fewer collisions --> greater collision force -->higher pressure. D.)more collisions --> greater collision force --> higher pressure

Answers

Answer: Option (D) is the correct answer.

Explanation:

It is known that relation between pressure and force is that, pressure equals force divided by area.

Mathematically, P = $(F)/(a)$

where P = pressure

F = force

a = area

Hence, when there is increase in number of gas particles in a container the there will be more number of collisions due to increase in number of particles. This will lead to greater collision force and as a result there will be increase in pressure because force is directly proportional to pressure.

Thus, we can conclude that the sequence more collisions --> greater collision force --> higher pressure best describes the result of increasing the number of gas particles in a container best describes the result of increasing the number of gas particles in a container.

I believe the correct response is D. More collisions that result in greater collision force and higher pressure.

Which method can be used to make a reliable guess that a victim was under 17 years old?A) look for flat-bladed incisors
B) look for presence or absence of wisdom teeth
C) multiply the internal distance in centimeters between the coronoid processes by the external distance in centimeters between the jaw angles(mandibular angles)
D) look for shovel shaped incisors
(It's not C)

Answers

Answer:

B) look for presence or absence of wisdom teeth

Explanation:

The only way to make a reliable guess if a victim was under 17 years old is by looking if he already had the wisdom teeth, this teeth are located in the back of the mouth, and are the third molars that humans develop after the age of 17 or 18 years on average, some could develop them after.

B-Look for the presence or absenceof wisdom teeth

What is the result of multiplying 2.55 x 10^10 m x 3.5 x 10^-7m using proper significant figures and scientific notation.1. 8.925 x 10^2 m^2
2. 8.92 x 10^1 m^2
3. 8.92 x 10^2
4. 8.9 x 10^3 m^2

Answers

3 I think I’m sure much love

The fuel used in many disposable lighters is liquid butane, C4H10. Butane has a molecular weight of 58.1 grams in one mole. How many carbon atoms are in 4.00 g of butane?

Answers

Matter is made of very tiny particles. One mole of a substance contains a given amount of particles. This number is constant for all particles- 6.022×10^23 , and is called Avogadro's constant. To get the number of particles in 4g of butane, we need to calculate the number of moles represented by 4 g, then multiply by the Avogadro's constant (Since each mole has particles equivalent to the Avogadro's constant)
Therefore, if 1 mole = 58.1g
how many moles will be equal to 4g?
we cross multiply (4x1) divide by 58.1
equals 0.068847moles
multiply by Avogadro constant = 4.1466 x 10^molecules
But remember the question is not about the number of molecules in butane, its about the number of carbon atoms.
Since there are four carbons in butane, and each has 4.1466 x 10^22 atoms
to get the number of atoms, we multiply by four
equals 1.6586 x 10^atoms

$\boxed{1.657 * {\text{1}}{{\text{0}}^{{\text{23}}}}{\text{ atoms}}}$ of carbon is present in 4.00 g of butane.

Further Explanation:

The number of atoms or molecules that can be present in one mole of any substance is determined by a number, known as Avogadro’s number. The numerical value of Avogadro’s number is ${\text{6}}{\text{.022}} * {\text{1}}{{\text{0}}^{{\text{23}}}}\;{\text{units}}$ . Such units can either be atoms or molecules.

The formula to calculate the moles of ${{\text{C}}_{\text{4}}}{{\text{H}}_{{\text{10}}}}$ is as follows:

${\text{Moles of }}{{\text{C}}_{\text{4}}}{{\text{H}}_{{\text{10}}}} = \frac{{{\text{Given mass of }}{{\text{C}}_{\text{4}}}{{\text{H}}_{{\text{10}}}}}}{{{\text{Molar mass of }}{{\text{C}}_{\text{4}}}{{\text{H}}_{{\text{10}}}}}}$ …… (1)

The given mass of butane is 4.00 g.

The molar mass of butane is $58.1 \text{g/mol}.$

Incorporate these values in equation (1).

$\begin{aligned}{\text{Moles of }}{{\text{C}}_{\text{4}}}{{\text{H}}_{{\text{10}}}} &= \left( {{\text{4}}{\text{.00 g}}} \right)\left( {\frac{{{\text{1 mol}}}}{{{\text{58}}{\text{.1 g}}}}} \right)\n&= {\text{0}}{\text{.0688 mol}}\n\end{aligned}$

The number of molecules present in one mole of butane is ${\text{6}}{\text{.022}} * {\text{1}}{{\text{0}}^{{\text{23}}}}\;{\text{molecules}}$ . So the expression to calculate the number of molecules of butane is as follows:

${\text{Molecules of butane}} = \left( {{\text{Moles of butane}}} \right)\left( {{\text{Avogadro's Number}}} \right)$ …… (2)

The number of moles of butane is 0.0688 mol.

The value of Avogadro’s number is ${\text{6}}{\text{.022}} * {\text{1}}{{\text{0}}^{{\text{23}}}}\;{\text{molecules}}$ .

Incorporate these values in equation (2).

$\begin{aligned}{\text{Molecules of butane}}{\mathbf{ }}&=\left( {0.0688{\text{ mol}}} \right)\left( {\frac{{{\text{6}}{\text{.022}} * {\text{1}}{{\text{0}}^{{\text{23}}}}{\text{ molecules}}}}{{{\text{1 mol}}}}} \right)\n&= 4.143 * {\text{1}}{{\text{0}}^{{\text{22}}}}{\text{ molecules}}\n\end{aligned}$

A molecule of butane consists of four carbon atoms in it. So the number of carbon atoms can be calculated as follows:

$\begin{aligned}{\text{Atoms of carbon}}&= \left( {4.143 * {\text{1}}{{\text{0}}^{{\text{22}}}}{\text{ molecules}}} \right)\left( {\frac{{{\text{4 C atoms}}}}{{{\text{1 molecule of butane}}}}} \right)\n&= 1.657 * {\text{1}}{{\text{0}}^{{\text{23}}}}{\text{ C atoms}}\n\end{aligned}$

Learn more:

How many grams of potassium were in the fertilizer? brainly.com/question/5105904
Determine how many moles of water produce: brainly.com/question/1405182

Answer details:

Grade: Senior School

Chapter: Mole concept

Subject: Chemistry

Keywords: $4.00 \text{g}, 58.1 \text{g/mol},$ butane, C4H10, Avogadro’s number, $1.657*10^22$ C atoms, moles, one mole, chemical formula, carbon atoms, molar mass of C4H10, given mass of C4H10.

Does anyone know how to do this? the solubility of barium carbonate, BaCO3, is 0.0100 g/L. Its molar mass is 197.3 g/mol. What is the Ksp of barium carbonate?

Answers

The value of ${{\text{K}}_{{\text{sp}}}}$ for barium carbonate is $\boxed{{\text{2}}{{.6 * 1}}{{\text{0}}^{{\text{ - 9}}}}}$ .

Further explanation:

Solubility product constant:

The equilibrium constant between the compound and its ion, when dissolved in solution, is known as solubility product constant. It is denoted by ${{\text{K}}_{{\text{sp}}}}$ . The solubility product constant is used to calculate the product of the concentration of ions at equilibrium.

Higher the solubility product constant more will be the solubility of the compound.

The general reaction is as follows:

${\text{AB}}\left({aq}\right)\to{{\text{A}}^+}\left({aq}\right)+{{\text{B}}^-}\left({aq}\right)$

The expression to calculate the solubility product for the general reaction is as follows:

$\boxed{{{\text{K}}_{{\text{sp}}}}=\left[{{{\text{A}}^+}}\right]\left[{{{\text{B}}^-}}\right]}$

Here,

${{\text{K}}_{{\text{sp}}}}$ is the solubility product constant.

$\left[ {{{\text{A}}^ + }} \right]$ is the concentration of ${{\text{A}}^ + }$ ions.

$\left[ {{{\text{B}}^ - }} \right]$ is the concentration of ${{\text{B}}^ - }$ ions.

The dissociation of ${\text{BaC}}{{\text{O}}_{\text{3}}}$ occurs as follows:

${\text{BaC}}{{\text{O}}_3}\to{\text{B}}{{\text{a}}^(2+)}+{\text{CO}}_3^(2-)$

The given solubility of ${\text{BaC}}{{\text{O}}_{\text{3}}}$ is 0.0100 g/L. Firstly, it is to be converted in mol/L. So the solubility of ${\text{BaC}}{{\text{O}}_{\text{3}}}$ is calculated as follows:

${\text{Solubility of BaC}}{{\text{O}}_{\text{3}}}\left({{\text{mol/L}}}\right)= \frac{{{\text{Solubility of BaC}}{{\text{O}}_{\text{3}}}\left({{\text{g/L}}}\right)}}{{{\text{Molar mass of BaC}}{{\text{O}}_{\text{3}}}\left({{\text{g/mol}}}\right)}}$ …… (1)

The solubility of ${\text{BaC}}{{\text{O}}_{\text{3}}}$ is 0.0100 g/L.

The molar mass of ${\text{BaC}}{{\text{O}}_{\text{3}}}$ is 197.3 g/mol.

Substitute these values in equation (1).

$\begin{aligned}{\text{Solubility of BaC}}{{\text{O}}_{\text{3}}}&=\left( {\frac{{{\text{0}}{\text{.0100 g}}}}{{{\text{1 L}}}}}\right)\left({\frac{{{\text{1 mol}}}}{{{\text{197}}{\text{.3 g}}}}} \right)\n&=0.00005068\;{\text{mol/L}}\n\end{aligned}$

It is evident from the chemical equation, one mole of ${\text{BaC}}{{\text{O}}_{\text{3}}}$ dissociates to form one mole of ${\text{B}}{{\text{a}}^(2+)}$ and one mole of ${\text{CO}}_3^(2-)$ . So the solubility of both ${\text{B}}{{\text{a}}^(2+)}$ and ${\text{CO}}_3^(2-)$ is 0.00005068 mol/L.

The formula to calculate the solubility product of is as follows:

${{\text{K}}_{{\text{sp}}}}=\left[{{\text{B}}{{\text{a}}^{{\text{2+}}}}}\right]\left[{{\text{CO}}{{_3^2}^-}}\right]$ …… (2)

Substitute 0.00005068 mol/L for $\left[{{\text{B}}{{\text{a}}^{{\text{2+}}}}}\right]$ and 0.00005068 mol/L for $\left[{{\text{CO}}_3^(2-)}\right]$ in equation (2).

$\begin{aligned}{{\text{K}}_{{\text{sp}}}}&=\left({{\text{0}}{\text{.00005068}}} \right)\left({{\text{0}}{\text{.00005068}}}\right)\n&=2.6*{10^(-9)}\n\end{aligned}$

Therefore, the value of ${{\mathbf{K}}_{{\mathbf{sp}}$ for ${\mathbf{BaC}}{{\mathbf{O}}_{\mathbf{3}$ is ${\mathbf{2}}{\mathbf{.6 * 1}}{{\mathbf{0}}^(-9)}$ .

Learn more:

1. Sort the solubility of gas will increase or decrease: brainly.com/question/2802008.

2. What is the pressure of the gas?: brainly.com/question/6340739.

Answer details:

Grade: School School

Subject: Chemistry

Chapter: Chemical equilibrium

Keywords: solubility, Ba2+, CO32-, BaCO3, Ksp, solubility product, molar mass, 197.3 g/mol, mol/L, g/L, 0.0100 g/L.

It's simple, just follow my steps.

1º - in 1 L we have $0.0100~g$ of $BaCO_3$

2º - let's find the number of moles.

$\eta=(m)/(MM)$

$\eta=(0.0100)/(197.3)$

$\boxed{\boxed{\eta=5.07*10^(-5)~mol}}$

3º - The concentration will be

$C=5.07*10^(-5)~mol/L$

But we have this reaction

$BaCO_3\rightleftharpoons Ba^(2+)+CO_3^(2-)$

This concentration will be the concentration of $Ba^(2+)~~and~~CO_3^(2-)$

$K_(sp)=([Ba^(2+)][CO_3^(2-)])/([BaCO_3])$

considering $[BaCO_3]=1~mol/L$

$K_(sp)=[Ba^(2+)][CO_3^(2-)]$

and

$[Ba^(2+)]=[CO_3^(2-)]=5.07*10^(-5)~mol/L$

We can replace it

$K_(sp)=(5.07*10^(-5))*(5.07*10^(-5))$

$K_(sp)\approx25.70*10^(-10)$

Therefore the $K_(sp)$ is:

$\boxed{\boxed{\boxed{K_(sp)\approx2.57*10^(-11)}}}$

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