A heavier mass m1 and a lighter mass m2 are 20.5 cm apart and experience a gravitational force of attraction that is 8.50 10-9 N in magnitude. The two masses have a combined value of 5.80 kg. Determine the value of each individual mass.m1 = ____ kgm2 = ____ kg

Answers

Answer 1
Answer:

Final answer:

The gravitational force between two individual masses can be calculated using Newton's law of universal gravitation. Given the total mass and the gravitational force, we can derive a quadratic equation to solve for the individual masses. The quadratic formula is then used to solve this equation.

Explanation:

The properties of the gravitational force between two masses can be derived from Newton's law of universal gravitation: F = G * (m1*m2) / r². In this equation, F is the force between the masses, G is the gravitational constant (approximately 6.674 * 10^{-11} N*(m²/kg²)), m1 and m2 are the masses, and r is the distance between the centers of the two masses.

Given that F = 8.50 * 10^{-9} N, r = 0.205 m (we need to convert cm to m), and m1 + m2 = 5.80 kg, we can substitute the known values into the equation to solve for the two masses.

This results in a quadratic equation in terms of one of the masses, which can be solved using the quadratic formula: -b ± sqrt(b² - 4ac) / 2a. Once we solve this equation we get the individual values of m1 and m2.

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Answer 2
Answer:

Final answer:

To find the values of m1 and m2, we can use the formula for gravitational force and solve for each mass. By substituting the given values, solving the equation, and simplifying, we can find the individual masses. The value of m1 is approximately 0.07415 kg and the value of m2 is approximately 0.05728 kg.

Explanation:

To determine the value of the individual masses, we can use the formula for gravitational force: F = G * (m1 * m2) / r^2, where G is the gravitational constant and r is the distance between the masses. Rearranging the formula, m1 = (F * r^2) / (G * m2). Substituting the given values, we can solve for m1 and m2.

  1. Convert the distance of 20.5 cm to meters by dividing by 100: 20.5 cm / 100 = 0.205 m.
  2. Substitute the given values into the formula: m1 = (8.50 * 10^(-9) N * (0.205 m)^2) / (6.67 * 10^(-11) N m^2/kg^2 * m2).
  3. Substitute the total mass of 5.80 kg into the equation: m1 = (8.50 * 10^(-9) N * (0.205 m)^2) / (6.67 * 10^(-11) N m^2/kg^2 * (5.80 kg - m1)).
  4. Simplify the equation by multiplying and dividing: m1 = (3.455 * 10^(-9) kg m^2 / s^2) / (6.67 * 10^(-11) m^3 kg^(-1) s^(-2) - 3.455 * 10^(-9) kg m^2 / s^2).
  5. Multiply both sides by the denominator and simplify: (6.67 * 10^(-11) m^3 kg^(-1) s^(-2) - 3.455 * 10^(-9) kg m^2 / s^2) * m1 = 3.455 * 10^(-9) kg m^2 / s^2.
  6. Distribute and combine like terms: (6.67 * 10^(-11) m^3 kg^(-1) s^(-2)) * m1 - (3.455 * 10^(-9) kg m^2 / s^2) * m1 = 3.455 * 10^(-9) kg m^2 / s^2.
  7. Combine the like terms and isolate m1: (6.67 * 10^(-11) m^3 kg^(-1) s^(-2) - 3.455 * 10^(-9) kg m^2 / s^2) * m1 = 3.455 * 10^(-9) kg m^2 / s^2.
  8. Divide both sides by the remaining term: m1 = (3.455 * 10^(-9) kg m^2 / s^2) / (6.67 * 10^(-11) m^3 kg^(-1) s^(-2) - 3.455 * 10^(-9) kg m^2 / s^2).
  9. Use a calculator to solve for m1: m1 ≈ 7.415 * 10^(-2) kg.
  10. Substitute the value of m1 into the equation for the total mass: 5.80 kg = m1 + m2.
  11. Solve for m2: m2 = 5.80 kg - m1.
  12. Substitute the value of m1: m2 ≈ 5.80 kg - 7.415 * 10^(-2) kg.
  13. Use a calculator to solve for m2: m2 ≈ 5.728 * 10^(-2) kg.

Therefore, the value of m1 is approximately 0.07415 kg and the value of m2 is approximately 0.05728 kg.

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What are two ways in which all types of precipitation are alike

Answers

The two ways in which all types of precipitation are alike they all come from the clouds,they are all formed by precipitation.

What is precipitation ?

Any liquid or frozen water that condenses in the atmosphere and falls to the ground is known as precipitation. Rain, sleet, and snow are only a few of its various manifestations. Precipitation is one of the three main processes that make up the global water cycle, together with evaporation and condensation.

Rain, sleet, and snow are only a few of its various manifestations. Precipitation is one of the three main processes that make up the global water cycle, together with evaporation and condensation. Water vapour in the clouds condenses into increasing-sized droplets of water, forming precipitation.

The most common forms of precipitation that come from cloud-borne particles are rain, snow, freezing rain, and sleet. The changes in temperature are the primary distinction between these various types of precipitation.

Thus, The two ways in which all types of precipitation are alike they all come from the clouds,they are all formed by precipitation.

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1. they all come from the clouds 2.they are  all formed by precipatation.                       hope this helps enjoyyyyyy!!!!!!!!!!!!!

Ok i bet none of you guys/girls can get this right there's three states of matter solidliquid solid gas but what is the fourth one? 42 points!

Answers

Answer:

plasma is the 4th state

Answer:

plasma in the 4th state

Explanation:

The spectrum produced by a prism or a raindrop is evidence that the average speed of light in the material depends on the light'sA. transmission qualities.
B. color.
C. wave nature.
D. particle nature.

Answers

The correct answer for the question that is being presented above is this one: "B. color." The spectrum produced by a prism or a raindrop is evidence that the average speed of light in the material depends on the light's color. White light is being refracted into different colors.

A ball rolls down an incline with an acceleration of 10 cm/s^2. If it starts with an initial velocity of 0 cm/s and has a velocy of 50 cm/s when it reaches the bottom of the ramp, how long is the ramp?

Answers

Given a = 10 cm/s²
          u = 0 cm/s
          v = 50 cm/s
we know that 
         v²=u²+2aS
        2500=2×10×S
        2500÷20 = S
        S= 125 cm
The ramp is 125 cm

Final answer:

The time for the ball to reach the bottom of the ramp is 5 seconds. Using this time value, the acceleration, and the initial velocity, you can calculate the length of the ramp, which is found to be 125 cm.

Explanation:

The question involves the physics principles of kinematics, specifically the concept of acceleration. Given that the initial velocity is 0 cm/s, the final velocity is 50 cm/s, and the acceleration is 10 cm/s^2, you can find the time it took for the ball to reach the bottom using the formula vf=vi+at (Final velocity = initial velocity + acceleration * time). Substituting the given values, you get the equation 50cm/s = 0cm/s + 10cm/s^2 * time, simplifying which gives time = 5 seconds.

To find the length of the ramp, you can use another kinematic equation, d = vit + 0.5at^2 (Distance = initial velocity * time + 0.5 * acceleration * time^2). Substituting the values we know, (initial velocity = 0, acceleration = 10 cm/s^2, time = 5 s), the equation simplifies to d = 0*5 + 0.5*10*5^2 = 0 + 0.5*10*25 = 125 cm. Therefore, the length of the incline or ramp is 125 cm.

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The energy for the water cycle comes from the Sun true or false?

Answers

Answer: True

Explanation:

Water cycle can be define as the hydrological cycle, in which the constant movement of water in it's various forms takes place among different spheres of the earth.

The main energy source for water cycle comes from the heat energy from the sunlight. The sunlight warms up the water in the water body on a large scale which leads to the evaporation of water. The evaporated water accumulates in the atmosphere the condensation of which leads to the precipitation in the form of rain, snow or hails. This way water comes back to the biosphere and hydrosphere.

On the basis of the above explanation, the statement, The energy for the water cycle comes from the Sun is true.

True. The energy for the water cycle does come from the Sun.

If anyone knows how to do any of these PLEASE help me....im am so confused rn and our teacher sucks at explaining this stuff......

Answers

take 68.2/60 = 1.137 hr
take 56.9/1.137 = 50.043 mi/hr

take 189/211 = 0.896

24.8/2 = 12.4 m
12.4/82.3 = 0.15s

Well, five answers for only five points is pretty slim.  But I've already got
a lot of points, and your plea for help sounds so desperate, that I think
I ought to jump in here and relieve some of your pain.

These aren't difficult problems.  The bummer is that whoever wrote them
got so interested in his dinosaur stories that he kind of hid the actual Math
and Physics under all kinds of stuff that doesn't matter.

1).     Speed  =  (distance covered) / (time to cover the distance)

                       =    (56.9 miles)  /  (68.2 minutes)

                       =      (56.9 / 68.2)  miles/minute

                       =          0.834  mile per minute.

BUT ... the question wants to know the speed in 'mph' ... miles per hour.

Well ... there are 60 minutes in an hour.  If 0.834 mile in covered in 1 minute,
then 60 times as much would be covered in 1 hour.

                    (0.834 mile/minute)  x  (60 minute/hour)  =  50.06 mile/hour

                     
            Rounded to no decimal places  =  50 mph


2).  Use the same formula:

         Speed  =  (distance covered) / (time to cover the distance)

                       =    (189 meters)  /  (211 seconds)

                       =      (189 / 211)  meters/seconds

                       =          0.8957 meters/second

     Round to 3 decimal places:      0.896  m/s


3).  The attacker jumped from 24.8 meters away.
       He already covered half of the distance.
       How far away is he now ?      1/2 of 24.8 m  =  12.4 m .
       He still has 12.4 meters left to go.

       He's moving at 82.3 meters per second.
       When will he arrive here ?

       Time  =  (distance)  /  (speed)

                  =      (12.4 meters)  /  (82.3 m/s)

                  =          (12.4 / 82.3)  seconds

                  =              0.1506 second

       Two decimal places:    0.15 second


4).    Distance  =  (speed) x (time)

                          =  ( 237 km/hr)  x (16.8 seconds) .

Do you see the problem here ?  We have the distance covered in an hour,
but we need to know how much distance is covered in only 16.8 seconds.
We really need to work out the speed in (meters per second).

OK.  237 km = 237,000 meters, so the speed is  237,000 meters/hour.

1 hour is 3,600 seconds. 
So the speed is only one 3600th of 237,000 meters in 1 second.

           (237,000 meters/hour) x (1 hour / 3600 seconds)  =  65.8333 m/s

           Distance  =  (speed)  x  (time)

                            =  (65.8333 meter/second)  x  (16.8 seconds)

                            =   (65.8333 x 16.8)  meters

                            =      1106 meters.     


5).  This is a nasty trick question.  The whole story is irrelevant,
and we don't even care how far Vinny dropped.

Anything that drops on Earth falls with the acceleration of gravity.
It doesn't matter how big or heavy or small or light it is.
Everything falls with the acceleration of gravity on Earth ...  about   9.8 m/s²  .