What is the slope of the line that is perpendicular to the line whose equation is 2x + y = 4.-2
-1/2
1/2
2

Answers

Answer 1
Answer: 2x + y = 4
        y = -2x + 4

Perpendicular Slope: ¹/₂

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The black graph is the graph of y= f(x). Choose the equation for the red graphwhich one: a, b, c, d?

Am solving this problem correct

Answers

a) The degree of the first term is... 1
first \ term = 3t
The degree of the second term is... 2
second \ term = t^2
The degree of the third term is... 4
third \ term = t^4

b) The leading term of the polynomial is... 7t⁴
The leading coefficient of the polynomial is... 7

c) The degree of the polynomial is... 4
a) 1, 2, 4
b) 7t^4,7
c) 4

A trading token is in the shape of a trapezoid and has an area of 25 cm² if the bases are three and 7 cm what is the height of the tokens

Answers

Area = (b1 + b2)/(2) *h
25 = (3 + 7)/(2) * h
25 = (10)/(2)*h
25 = 5h
5 = h
the height is 5

250 + 200h = 300 + 180h250 + 200h = 300 + 180h 
      − 180h           − 180h
250 +  20h = 300
h = credit hours

Answers

250+200h = 300+180h
     -180h            -180h
250+20h = 300
-250         -250
20h = 50
/20     /20
h = 2.5
 

Answer:h=2.5

Step-by-step explanation:

A new car that sells for $19,000 depreciates (decreases in value) 21% each year. What is the decay factor, b? 0.79 0.21 79 21

Answers

Answer: 0.79

Step-by-step explanation:

Given: The cost price of car = $19,000

The rate of depreciation = 21 % = 0.02

The exponential decay equation (depreciation) is given by :-

y=Ab^x, where A is the initial amount and b is the decay factor for x years such that b=(1-r), where r is the rate of decay.

If we substitute the value of r , we get

The decay factor =b = (1-0.21)=0.79

The decay factor is 0.21 ((:

All equation of motion with examples

Answers

Answer:

Answer is below. Hope this helps you!

Step-by-step explanation:

(i)v = u + at

(ii) s = ut + 1/2 *at²

(iii)2as = v²-u²

Examples:

A train starting from rest attains a velocity of 72km/h in 5 minutes. Assuming that the acceleration is uniform, find (i) the acceleration and  (ii)  the distance travelled by the train for attaining this velocity.

72km/h = 20m/s

(i) use v= u+ at

20 = 0 + a*300

20 = 5a

20 / 300= a

1/15 ms² = a

to find distance

use 2as= v²-u²

2 *1/15 * s = (20) - 0²

2/15s = 400

s = 400 * 15/2

s = 3000m = 3 km

a car accelerates with a uniform acceleration of 1m/s². it starts with a  velocity of 18km/h and reaches 36 km/h in 5 seconds find the distance travelled.

18 km /h = 5m/s

36km/h = 10m/s

use - s= ut + 1/2at²

s = 5 * 5 + 1/2 * 1 * (5)²

s = 25 + 25/2

s = 37.5 meters

Answer:

It is described in terms of displacement, distance, velocity, acceleration, time and speed. Jogging, driving a car, and even simply taking a walk are all everyday examples of motion.

...

The three equations are,

v = u + at.

v² = u² + 2as.

s = ut + ½at²

If one vehicle is going 20 mph and another is going 60 mph, the one going 60 mph has __9____ times the force at impact as the one going 20 mph.

Answers

Answer:

Assuming that both vehicles have the same mass: It´s 9 times

Step-by-step explanation:

You can use the formula for kinetic energy which is: K = (mv^2)/(2)

We can calculate two different values for each speed. We assume that the mass is "m"

K_1 = (m(20)^2)/(2) = (400m)/(2) = 200m\n\nK_2 = (m(60)^2)/(2) = (3600m)/(2) = 1800m\n\n

As you can see the K2 is 9 times bigger than K1