How does this model demonstrate the Pythagorean Theorem?Three squares whose corners touch so that the respective edges form a triangle. The smallest square has a side labeled six and is made up of thirty-six smaller squares. The largest square has a side labeled ten and is made up of one hundred smaller squares. The third square has a side labeled eight and is made up of sixty-four smaller squares.

A.
The sum of the lengths of the shortest and the longest sides is equal to twice the length of the middle side. So double the length of the longer leg of any right triangle is equal to the sum of the shorter leg and the hypotenuse.

B.
The sum of the area of the two smaller squares is equal to the area of the larger square. So the sum of the lengths of the two legs of any right triangle squared is equal to the length of the hypotenuse squared.

C.
The sum of the area of the smallest and the largest squares is equal to the area of the middle square. So the sum of the lengths of the shorter leg and the hypotenuse of any right triangle squared is equal to the length of the middle leg squared.

D.
The length of the longest side minus two equals the length of the middle side. The length of the middle side minus two equals the length of the shortest side. So the length of the short leg of any right triangle is equal to the length of the middle leg minus 2, and the length of the hypotenuse is equal to the length of the middle leg plus 2.

Answers

Answer 1

Answer: " B is your best choice but it is very badly stated. this gives an Example of the Pythagorean theorem. it does Not demonstrate it. B is written incorrectly, it should say "sum of squares of the lengths of the legs" Not "sum of the lengths of the two legs of any right angle squared"

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Value of x in the solution to the system of equations.
6x+3y=13
3x-y=4

Answers

The two easiest ways to solve a system of equations (in my opinion) are to add the equations together while getting rid of a variable, or solving for a variable in one equation and plugging it into another. The latter is the method I will use.

3x - y = 4 (solve for y)
3x = 4 + y
3x - 4 = y
y = 3x - 4

Now we can plug y into the other equation:
6x + 3y = 13
6x + 3(3x - 4) = 13
6x + 9x - 12 = 13
15x = 25
x = 25/15
x = 5/3
The answer is x = 5/3

If you ever needed to find y as well, you can plug this into either equation to find y.
3x - y = 4
3(5/3) - y = 4
5 - y = 4
y = 1

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Answers

The range............

I think range is the right answer, thought I don't know if I am correct. I have not done this in a long while.

Solve the inequality.q > 1
q< $(0)/(1)$
q> $(5)/(6)$
q> $(1)/(6)$

Answers

Answer:

q > 5/6

Step-by-step explanation:

The LCD is (2)(3) = 6. Mult. all three terms by 6, we get:

6q - 3 > 2. Isolate q by adding 3 to both sides:

6q > 5. Then q > 5/6 (the third possible answer).

the space club is having so posters printed the printer charges $250 plus $2 per poster how many posters van be printed for $1000

Answers

you can solve this by saying $1000 is equal to 250 + $2 * the amount of posters (x)
1000=250+2x
1000-250=2x
750=2x
x= (750/2)
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Snow accumulated at 4/5 inch/hour. If the snow continues at this rate for 10hours how much snow will accumulate?

Answers

Well, 4/5x10=40/5=8in

Final answer:

The snow will accumulate 4 inches after 10 hours.

Explanation:

To calculate how much snow will accumulate, we need to multiply the rate at which the snow is accumulating by the number of hours. The snow is accumulating at a rate of 4/5 inches per hour. So, in 10 hours, the snow will accumulate:

4/5 inch/hour × 10 hours = 4/5 × 10 = 8/2 = 4 inches

Therefore, 4 inches of snow will accumulate after 10 hours.

Learn more about Calculating snow accumulation here:

brainly.com/question/29066077

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A. [0 –1 7]

B. [0 –1 3]

C. [0 –1 –7]

D. [0 –7 3]

Answers

The answer is C [0 –1 –7]

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