PHYSICS HIGH SCHOOL

Which change increases the electric force between objects? A) Two neutral objects are moved closer together.
B) Electrons are added to two negatively charged objects.
C) Two oppositely charged objects are moved farther apart.
D) The charge on two positively charged objects is reduced.

Answers

Answer 1

Answer:

By definition we have that the electric force is given by:

Where,

k: proportionality constant

q1: electric charge of object 1

q2: electric charge of object 2

d: distance between both objects

Therefore, to increase the electric power there are two possible cases:

1) Add more load to each object

2) Decrease the distance between objects.

The option that increases the electric force for this case is:

Electrons are added to two negatively charged objects.

This is because the values of q1 and q2 increase.

Answer:

A change that increases the electric force between objects is:

B) Electrons are added to two negatively charged objects.

Answer 2

Answer:

Answer

B) Electrons are added to two negatively charged objects.

Explanation:

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Ammonia is a weak base because produce ____ ion in solution?

Answers

ammonia is a weak base ( electrolyte) because ammonia reacts with water to produce ammonium and hydroxide ions. When hydroxide ion reacts with ammonium, it results to water and ammonia. it only proves that ammonia is rather a base because of its acceptance of hydrogen ion from water.

Ammonia is a weak base because it produces hydroxide (OH-) ions in solution.

Why is ammonia a weak acid?

Ammonia is a weak base because it produces hydroxide ions (OH-) in solution.

When ammonia dissolves in water, it accepts a proton from water, forming the ammonium ion (NH4+), and leaves hydroxide ions behind. This partial dissociation results in a small concentration of hydroxide ions, causing the solution to be slightly basic.

Unlike strong bases, which fully dissociate and release a large number of hydroxide ions, ammonia's limited ability to produce hydroxide ions makes it a weak base.

More on ammonia can be found here:brainly.com/question/29519032

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PLEASE HELP ME Color corresponds to the ______________ of light waves. wave speed cycles wavelength

Answers

Wavelength. Each wavelength is a certain color. For instance, shorter wavelengths (like 470nm) will be blue or violet, while longer wavelengths (like 650nm) will be red. Hope this helps! :)

In 1780, in what is now referred to as "Brady's Leap," Captain Sam Brady of the U.S. Continental Army escaped certain death from his enemies by running over the edge of the cliff above Ohio's Cuyahoga River in (Figure 1) , which is confined at that spot to a gorge. He landed safely on the far side of the river. It was reported that he leapt 22 ft (≈ 6.7 m) across while falling 20 ft (≈ 6.1 m).What is the minimum speed with which he’d need to run off the edge of the cliff to make it safely to the far side of the river?

Express your answer to two significant figures and include the appropriate units.

Answers

The minimum speed with which the captain Sam Brady of the US continental army had to run off the edge of the cliff to make it safely to the far side of the river is $\boxed{19.667\text{ ft/s}}$ or $\boxed{5.998\text{ m/s}}$ or $\boxed{6\text{ m/s}}$ or $\boxed{599.8\text{ cm/s}}$ .

Further explanation:

As Captain Sam Brady jumps from the cliff, he moves in two dimension under the action of gravity.

Given:

The height of free fall of the captain Brady is $20\text{ ft}$ or $6.1\text{ m}$ .

The horizontal distance moved by the captain Brady is $22\text{ ft}$ or $6.7\text{ m}$ .

Concept:

The time required to free fall of a body can be calculated by using the expression given below.

$\left( { - s}\right)=ut-(1)/(2)g{t^2}$ ……. (1)

The displacement is considered negative because the captain is moving in vertically downward direction.

Here, $s$ is the distance covered by the body in free fall, $u$ is the initial velocity of the object, $g$ is the acceleration due to gravity and $t$ is the time taken in free fall of a body.

As the Caption jumps off the cliff, he has his velocity in the horizontal direction. The velocity of the captain in vertical direction is zero.

Substitute $0$ for $u$ in the equation (1) .

$s=(1)/(2)g{t^2}$

Rearrange the above expression for $t$ .

$\boxed{t=\sqrt {\frac{{2s}}{g}}}$ …… (2)

Converting acceleration due to gravity in $\text{ft}/\text{s}^2$ .

$\begin{aligned}g&=\left( {9.81\,{\text{m/}}{{\text{s}}^{\text{2}}}} \right)\left( {\frac{{1.0\,{\text{ft/}}{{\text{s}}^{\text{2}}}}}{{0.305\,{\text{m/}}{{\text{s}}^{\text{2}}}}}} \right) \n&=32.16\,{\text{ft/}}{{\text{s}}^{\text{2}}} \n \end{aligned}$

Substitute $20\text{ ft}$ for $s$ and $32.16\,{\text{ft/}}{{\text{s}}^{\text{2}}}$ for $g$ in equation (2) .

$\begin{aligned}t&=\sqrt {\frac{{2\left( {20\,{\text{ft}}} \right)}}{{\left( {32.16\,{\text{ft/}}{{\text{s}}^{\text{2}}}} \right)}}} \n&=1.116\,{\text{s}} \n \end{aligned}$

Therefore, the time taken by captain to free fall a height $20\text{ ft}$ is $1.116\text{ s}$ .

In the same time interval captain has to move $22\text{ ft}$ in horizontal direction. The acceleration is zero in horizontal direction. So, the velocity will be constant throughout the motion in the horizontal direction.

The distance travelled by captain in the horizontal direction is given by,

$x=v\cdot t$

Rearrange the above expression for $v$ .

$\boxed{v=(x)/(t)}$ …… (3)

Here, $x$ is the distance travelled in horizontal direction, $v$ is the velocity of the captain and $t$ is the time.

Substitute $22\text{ ft}$ for $x$ and $1.116\text{ s}$ for $t$ in equation (3) .

$\begin{aligned}v&=\frac{{22\,{\text{ft}}}}{{1.116\,{\text{s}}}} \n&=19.71\,{\text{ft/s}} \n \end{aligned}$

Thus, the minimum speed with which the captain Sam Brady of the US continental army had to run off the edge of the cliff to make it safely to the far side of the river is $\boxed{19.667\text{ ft/s}}$ or $\boxed{5.998\text{ m/s}}$ or $\boxed{6\text{ m/s}}$ or $\boxed{599.8\text{ cm/s}}$ .

Learn more:

1. Energy density stored in capacitor brainly.com/question/9617400

2. Kinetic energy of the electrons brainly.com/question/9059731

3. Force applied by the car on truck brainly.com/question/2235246

Keywords:

Free fall, projectile, gravity, 1780, Brady’s, leap, Captain, Sam Brady, US, continental army, enemies, Ohio’s, Cuyahoga river, 22 ft, 6.7 m, 20 ft, 6.1 m, minimum speed, run off, edge, cliff, safely, far side, river, 19.71 ft/s, 6 m/s, 6 meter/s, 5.99 m/s, 599.8 cm/s.

Final answer:

Using the principles of projectile motion from Physics, Captain Sam Brady would need to run with an initial horizontal speed of approximately 19.64 ft/s to reach the far side of the river.

Explanation:

This problem can be solved using basic Physics, specifically projectile motion. Here, Captain Sam Brady had to run off the edge of the cliff to make it safely to the far side of the river which is 22 ft away while falling 20 ft down. We assume that he jumps horizontally (i.e., his initial vertical velocity is 0).

Firstly, we calculate the time for the vertical fall. Using the equation t = sqrt (2h/g) where h is height and g is the acceleration due to gravity (32.2 ft/s²), we get time t ≈ 1.12s (rounded to two significant figures).

Next, we can use this time to figure out his initial horizontal velocity needed. The equation v = d/t where v is velocity, d is distance, and t is time gives us v ≈ 19.64 ft/s (rounded to two significant figures).

So, Captain Sam Brady would need to run with an initial horizontal speed of approximately 19.64 ft/s to make it safely across the river.

Learn more about Projectile Motion here:

brainly.com/question/20627626

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A 1200 w microwave oven transforms 1.8x10(to the power of 5) J of energy while reheating some food. Calculate how long the food was in the microwave, in mins!? (Please show steps, thanks)

Answers

1200 watts = 1200 joules per second

(1.8 x 10⁵ joules) / (1,200 joules/sec) = 150 sec = 2.5 minutes

Explain the right-hand rule as it applies to rotation of winds around a high or low pressure center.

Answers

Explanation:

The right-hand rule, also known as the Buys-Ballot's law, helps explain the rotation of winds around high and low pressure centers in the Northern Hemisphere. According to this rule:

1. In a low pressure center (cyclone) in the Northern Hemisphere, the wind rotates counterclockwise around the low-pressure center. If you extend your right hand with your thumb pointing upwards, your fingers will curl in the counterclockwise direction, representing the direction of the winds.

2. In a high pressure center (anticyclone) in the Northern Hemisphere, the wind rotates clockwise around the high-pressure center. If you extend your right hand with your thumb pointing upwards, your fingers will curl in the clockwise direction, representing the direction of the winds.

This rule is based on the Coriolis effect, which is caused by the Earth's rotation. As air flows from areas of higher pressure to lower pressure, it is deflected by the Coriolis force due to the Earth's rotation. In the Northern Hemisphere, the Coriolis force deflects moving air to the right. This deflection, combined with the pressure gradient force, results in the counterclockwise rotation around low-pressure centers and clockwise rotation around high-pressure centers.

It is important to note that the right-hand rule is specific to the Northern Hemisphere. In the Southern Hemisphere, the opposite is true. The wind rotates counterclockwise around low-pressure centers and clockwise around high-pressure centers.

Understanding the rotation of winds around pressure centers is essential in meteorology for predicting weather patterns and systems. By studying these rotations, meteorologists can make informed forecasts and predictions about the movements and impacts of weather systems.

Polluted water can contribute to