What are the solutions to the equation (x – 2)(x + 5) = 0?

Answers

Answer 1
Answer:

A product of two (or more) factor can be zero if and only if at least one of the factors is zero.

In other words, you cannot multiply two non-zero real numbers, and have zero as a result.

So, if we want the product of these two factors to be zero, at least one of them has to be zero.

The first factor is zero if

x-2 = 0 \iff x=2

The second factor is zero if

x+5 = 0 \iff x=-5

Answer 2
Answer:

The solutions to the equation are x = 2 and x = -5.

To find the solutions to the equation (x – 2)(x + 5) = 0, you need to set each factor equal to zero and solve for x. When the product of two factors is equal to zero, one or both of the factors must be equal to zero.

Set x - 2 = 0 and solve for x:

x - 2 = 0

x = 2

Set x + 5 = 0 and solve for x:

x + 5 = 0

x = -5

The solutions to the equation are x = 2 and x = -5. When you substitute these values back into the original equation, you get (2 - 2)(2 + 5) = 0 and (-5 - 2)(-5 + 5) = 0, both of which evaluate to 0, confirming that these are indeed the solutions.

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Which unit would you use to measure the amount of water in a swimming pool?pints
quarts
gallons
cups

Answers

Gallons, it's the largest unit that you're given and swimming pools obviously have a lot of water in them

Please help will give brainliest

Answers

give the other person brainliest just answering so they can get it

Simplify please! sqrt(8x^(12) y^(7))

Answers

\sqrt{8 x^(12) y^(7) } = √(8) \sqrt{x^(12)} \sqrt{ y^(6)*y } =√(4) √(2) \sqrt{(x^(6) )^(2) } \sqrt{ (y^(3))^(2)} √(y)=2 √(2) x^(6) y^(3) √(y)

I hope it helps you :)

A line that passes through the point (–1, 3) has a slope of 2. Find another point on the line.a. (–3, 2)
b. (1, 4)
c. (1, 5)
d. (0, 5)

Answers

Using the slope-intercept form of a line, the equation can be generated
y = mx + b

m = 2
and we can solve for b by substituting the given coordinates where the line passes through
3 = 2(-1) + b
b = 5

So, the equation of the line is
 y = 2x + 5

Trying the options using the equation, the answer is
d. (0,5)

A flagpole broke in a storm. 7 meters are still sticking straight out of the ground, where it snapped, but the remaining piece has hinged over and touches the ground at a point 24 meters away horizontally.How tall was the flagpole before it broke?

Answers

32 meters tall.
It would form a right triangle, in which the shorter leg is 7m and the longer leg is 24m.  You're looking for the last side, the hypotenuse.  So use the Pythagorean theorem. a^2 + b^2 = c^2 , in which a and b are the legs and c is the hypotenuse.
Therefore, you get 7^2 + 24^2 = c^2.
Which is, 49 + 576 = c^2
Add, 625 = c^2.
Take the square root of 625, which is 25.   So, the length of the hypotenuse (last side) is 25m.  Add the 7m that is sticking out of the ground, to get 32m.
The broken part forms the hypotenuse of a right angled triangle.

So we have a right angled triangle, the vertical part is 7m, and the horizontal is 24m.

From Pythagoras' Theorem:

x² = 24² + 7²

x² = 576 + 49

x² = 625

x = √625

x = 25

So the broken part is 25m long.

The length of the flagpole before it was broken =  25 + 7

= 32m.

Really beautiful question.

Given that f
(
x
)
=
3
x

7
and
g
(
x
)
=
3
x
, evaluate
f
(
g
(

1
)
)

Answers

Answer:  f(g(-1)) = -16

Step-by-step explanation:

First, we need to find g(−1), which means we substitute -1 in place of x in the function g(x):

g(-1) = 3(-1) = -3

Next, we substitute g(-1) into f(x):

f(g(-1)) = f(-3) = 3(-3) - 7 = -16

Therefore, f(g(-1)) = -16.

The guy above me is correct