MATHEMATICS MIDDLE SCHOOL

(A^5)^6 × a^2 × (a^8)^0

Could you show me the steps so I can understand better?

Answers

Answer 1
Answer:

Answer:

The answer for (a^5)^6 × a^2 × (a^8)^0 is  a^32 or a^(32)

Step-by-step explanation:

Given:

(a^5)^6 × a^2 × (a^8)^0

Solution:

1.By property of indices or law of indices we have

(x^(a)) ^(b) = x^((a* b))\n \therefore (a^(5)) ^(6) = a^((5* 6))\n \therefore (a^(5)) ^(6) = a^((30))\nSimilarly\na^(2) = a^(2)\n \n(a^(8))^(0)} = a^((8* 0))\n(a^(8))^(0)} = a^(0)\ \textrm{Which is also equal to one i.e 1}\n

Therefore the required equation will be

(a^5)^6 × a^2 × (a^8)^0  

(a^(5)) ^(6)* a^(2)* (a^(8))^(0) =a^((30))* a^(2)* a^(0)

2. law of indices

x^(a) * x^(b) = x^((a+b))\n

Therefore,

(a^(5)) ^(6)* a^(2)* (a^(8))^(0) = a^((30+2+0))

(a^(5)) ^(6)* a^(2)* (a^(8))^(0) = a^((32))

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Answers

The length of the base of the parallelogram is 22 cm.

Given:
Area = 396 cm²
height = 18 cm

Area of a parallelogram is computed by multiplying its base to its height.

A = bh
396 cm² = b * 18cm
396 cm²/18cm = b
22 cm = b

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