David invested $1000.ppm what would that money grow to the 18 months at 5.5% interest rate?

Answers

Answer 1

Answer: David invested $1000. Let's solve for the amount of money to grow to the 18 months at 5.5% interest rate?
Let's assume that this 5.5% interest is per month.
=> 1 000 dollars * 0.055 = 55 dollars per month
=> 55 * 18 months = 990 dollars in 18 months.

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Convert the given fraction to a decimal by setting the denominator equal to 100

Combine the like terms to create an equivalent expression.
9y+y

Answers

The equivalent expression after combining the like terms of the expression 9y+y is 10y.

Given an expression:

9y + y

It is required to find the equivalent expression for this expression after combining the like terms.

Like terms are the terms in an expression or an equation that has the same variable to it or is constant.

They can be operated together.

Here, 9y and y are having the same variable, y.

So, they are like terms.

So, add 9y and y.

9y + y = y(9 + 1)

= 10y

Hence the expression is 10y.

Learn more about Like Terms here :

brainly.com/question/29169167

#SPJ6

Answer: 10y

Step-by-step explanation: All variables equal one unless assigned a specific answer. So It is basically 9y+1

9y+1=10y

Final Answer: 10y

Hope this helps! :D

Mr. Falcone pizza shop offers three sizes of pizza. The small medium and large pizzas have diameters of 8 inches 10 inches 12 inches

Answers

The circumference of small size, medium size and large size of pizzas are 25.12 inches, 31.4 inches and 37.68 inches.

Step-by-step explanation:

Given,

The diameter of small pizza = 8 inches,

The diameter of medium pizza = 10 inches and

The diameter of large pizza (d) = 11 inches

To find, the circumference of each size of pizza = ?

We know that,

The circumference of the circle = $2\pi r= \pi d$

∴ The circumference of small size of pizza = 3.14 × 8 = 25.12 inches

The circumference of medium size of pizza = 3.14 × 10 = 31.4 inches

Also,

The circumference of large size of pizza = 3.14 × 12 = 37.68 inches

Thus, the circumference of small size, medium size and large size of pizzas are 25.12 inches, 31.4 inches and 37.68 inches.

You can also refer:

https://brainly.ph/question/1009095

Please help me find the answer and leave steps. Honest educational answers please.

Answers

You just cancel the +2y and the -2y because they are the same value and different signs then solve for X that gives you -3 and then add -15 along with -6 to give you -21 (cancel the negative sign) and you'll divide 21 and 3 to give you 7 and the substitute in the original equation for x (7) to get y. Idk if the answer choices are correct though....

a committee has eleven members. there are 3 members that currently serve as the boards chairman, ranking members, and treasurer. each member is equally likely to serve in any of the positions.

Answers

Answer:

$(1)/(990)$

Step-by-step explanation:

The full question:

"A committee has eleven members. there are 3 members that currently serve as the boards chairman, ranking members, and treasurer. each member is equally likely to serve in any of the positions. Three members are randomly selected and assigned to be the new chairman, ranking member, and treasurer. What is the probability of randomly selecting the three members who currently hold the positions of chairman, ranking member, and treasurer and reassigning them to their current positions?"

The permutation of choosing 3 members from a group of 11 would be:

P(n,r) = $(n!)/((n-r)!)$

Where n would be the total [in this case n is 11] & r would be 3

Which is:

P(11,3) = $(11!)/((11-3)!)=(11!)/(8!)=11*10*9=990$

So there are total of 990 possible way and there is ONLY ONE WAY for them to be reassigned. Hence the probability would be:

1/990

Anybody know the right answer?

Answers

Quadrant I : cot(x) > 0 → -cot(x) < 0

Quadrant II : cot(x) < 0 → -cot(x) > 0

Quadrant III : cot(x) > 0 → -cot(x) < 0

Quadrant IV : cot(x) < 0 → -cot(x) > 0

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$a)\ \left((11\pi)/(6),\ -\sqrt3\right)\n\n(11\pi)/(6)\in\text{Quadrant IV, then -cot(x)} > 0,\ \text{we have}\ -\cot(11\pi)/(6)=-\sqrt3 < 0$

Answer: a)

$b)\n(2\pi)/(3)\in\text{Quadrant II},\ -\cot(x) > 0,\ \text{we have}\ (\sqrt3)/(3) > 0\n\nc)\n(5\pi)/(4)\in\text{Quadrant III},\ -\cot(x) < 0,\ \text{we have}\ -1 < 0\n\nd)\n(4\pi)/(3)\in\text{Quadrant III},\ -\cot(x) < 0,\ \text{we have}\ -(\sqrt3)/(3) < 0$

We know that one answer is only true, so we did not check the correctness of the cotangent value, only to the number sign

I need help please help

Answers

This question is a lot less complicated than it sounds:
cost = c
amount of tickets = s

Since we know that each ticket costs 7$, we multiply the amount of tickets by 7.
c = 7s

The 7 is an independent variable. It will always be multiplied by s, no matter what s is.
The c is a dependent variable. Different numbers for s change what c is.

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