the average amount of annual interest earned across three investment accounts was $2709.00. If one account yielded $1345.00 in the 12 month period, and the second yielded $568.00, what did the thrid account yield?

Answers

Answer 1

Answer: The interest of the third investment to have an annual interest earning of 2,709 would be 6,214. This is calculated using the formula: average = (a+b+c ) / 3. By substituting it would be, 2,709 = (1,345 + 568 +x) / 3. Then it would be 8,127 = 1,345 + 568 +x and by transferring the figures, it will be then 6,214.

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Which describes the calculations that could be used to solve this problem? Levi has 50 hot dogs to pack into boxes and bags. He has one box that will hold 15 hot dogs. He will put the rest of the hot dogs into bags with 5 hot dogs in each bag. How many bags of hot dogs will Levi be able to fill? A. Subtract 50 – 15. Then multiply the difference by 5. B. Add 50 + 15. Then divide the sum by 5. C. Add 5 + 15. Then add 50 to the sum. D. Subtract 50 – 15. Then divide the difference by 5.
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Josiah went to the barber to get his haircut.It cost $18 for the haircut.Josiah tipped the barber 15%.What was the total cost of the haircut including the tip?

Answers

Answer:

Tip -$2.70

Total -$20.70

Step-by-step explanation:

2b^2-9b-5
How do you answer this by factoring

Answers

Maybe ask google i sometimes do that

Simple...

you have: $2b^(2)-9b-5$

Using the box method-->>>

What multiplies to -10 and adds to -9?

-10*1=-10

-10+1=-9

(b-5)(2b+1)

Thus, your answer.

If c = 18, what is 2 x (74 - c)?

Answers

First you substitute 18 into c and solve what's inside the paranthesis which is 56. Distribute the 2 to 56 and you should be getting 112 as your answer. 2x(74-c)=112 if c=18.

2 x (74 - 18)
74-18=56
2x(56)
112x

Simplify the expression: 1/1+cot^2xa.sec^2x
b.csc^2x
c.sin^2x
d.cos^2x
e.tan^2x

Answers

$\sin ^( 2 ){ x } +\cos ^( 2 ){ x } =1\n \n \frac { \sin ^( 2 ){ x } }{ \sin ^( 2 ){ x } } +\frac { \cos ^( 2 ){ x } }{ \sin ^( 2 ){ x } } =\frac { 1 }{ \sin ^( 2 ){ x } } \n \n 1+\cot ^( 2 ){ x } =\csc ^( 2 ){ x }$

Because of this...

$\frac { 1 }{ 1+\cot ^( 2 ){ x } } \n \n =\frac { 1 }{ \csc ^( 2 ){ x } }$

But...

$\frac { 1 }{ \csc ^( 2 ){ x } } =\sin ^( 2 ){ x }$

Therefore:

$\frac { 1 }{ 1+\cot ^( 2 ){ x } } =\sin ^( 2 ){ x }$

Answer:

(c)

Determine the type and number of solutions of 7x^2+3x+8=0

Answers

$7x^2+3x+8=0 \n \na =7, \ b=3 ,\ c=8 \n \n\Delta =b^2 - 4ac = 3^2 -4\cdot 7\cdot 8=9-224=-215\n \n Answer : \ \Delta \ is \ negative,\ this \ gives \ two \ imaginary \ solutions$

$7x^2+3x+8=0\n\n \Delta=3^2-4\cdot7\cdot8=9-224=-115\ \ \Rightarrow\ \ \ no\ real\ solution\n\n\ two\ complex\ solutions\n\n\Delta=-115=115\cdot i^2\ \ \ \Rightarrow\ \ \ √(\Delta) = √(115)\ i\n\nx_1= (-b- √(\Delta) )/(2a) = (-3- √(115)\ i)/(2\cdot 7) = (-3- √(115i))/(14)\n\nx_2= (-b+ √(\Delta) )/(2a) = (-3+ √(115)\ i)/(2\cdot 7) = (-3+ √(115)\ i)/(14)$

40,43,40,39,50,23 what is the median?

Answers

Median is the middle number, but since there is 6 numbers.
Put them in order first
23,39,40,40,43,50
Well in middle is 40 for both sides
So to solve median for this you'd add the two middle numbers together since there is even set of numbers.
40+40 =80 then divide by 2
80÷2=40
Median = 40
*Follow This Example for any other even sets of numbers for Median*

The median of this data set is 40. This is because when put in order from greatest to least the order is:
23, 39, 40, 40, 43, 50
So the middle number is 40.

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