A landscaper is designing a flower garden in the shape of a trapezoid. She wants the shorter base to be 3 yards greater than the height, and the longer base to be 7 yards greater than the height. She wants the area to be 225 square yards. The situation is modeled by the equation . Use the Quadratic Formula to find the height that will give the desired area. Round to the nearest hundredth of a yard.

Answers

Answer 1
Answer:

Let

x--------> shorter base in yards

y--------> the longer base in yards

z-------> the height in yards

we know that

the area of the flower garden in the shape of a tra-pezoid is

A=(1)/(2) (x+y)z

A=225\ yd^(2)

so

225=(1)/(2) (x+y)z --------> equation 1

x=z+3 --------> equation 2

y=z+7 --------> equation 3

Substitute equation  2 and equation  3 in equation  1

225=(1)/(2) ((z+3)+(z+7))z

225=(1)/(2) ((z+3)+(z+7))z\n \n450=[2z+10]z\n \n2z^(2)+10z-450=0

Solve the quadratic equation for z

using a graphing tool

see the attached figure

the solution is

z=12.71\ yd

therefore

the answer is

the height of the flower garden in the shape of a tra-pezoid is 12.71\ yd


Answer 2
Answer: The equation is to be given, judging by the tone problem given but apparently it's not given. The equation can be derived from the problem. The area of a trapezoid is given by the equation A = ((a+b))/(2) h. Also, given that a, is the longer side, then a = h+7 and b (shorter side) = h+3 and h is the height. the equation is then A = ((h+3)(h+7))/(2)h = 225. Solving this quadratic equation, h is 4.84. 

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Answers


Compound interest formula  A = P(1 +r/100)^n
A = Amount
r = rate = 6
n = number of compounding time.
P = Principal = $2000.
Since we are compounding monthly, r = 6% p.a = (6/12)% per month.
n= 3 years = 3*12 = 36 months.
Note that  since we are compounding monthly, our time would be in months.
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A = 2000 * (1 + (6/12)/100 )^36
A = 2000 * (1 +  6/1200)^36
A = 2000 * (1 +  0.005)^36    Use your calculator
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Amount = $2 393.36

That's it. Cheers.

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Answers

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Answers

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The concrete company charges ​$130 for delivering less than yd Superscript 3 of concrete. For yd Superscript 3 and​ more, the charge is ​$​/yd Superscript 3 with a fraction of a yard charged as a fraction of ​$.65 Use function notation to write the charge as a function of the number x of cubic yards​ delivered, where 0x​10, and graph this function. Question content area bottom Part 1 Choose the correct function below.

Answers

Answer:

Step-by-step explanation:

To write the charge as a function of the number of cubic yards delivered, we can define two separate cases:

Case 1: For deliveries less than yd³, the charge is a flat fee of $130.

Case 2: For deliveries of yd³ or more, the charge is $/³, where a fraction of a yard is charged as a fraction of $0.65.

Let's use function notation to write the charge as a function of the number of cubic yards delivered, where 0 ≤ ≤ 10.

The function can be written as:

\[

() =

\begin{cases}

130 & \text{if } < \\

0.65(-) + \frac{}{} & \text{if } ≥ \\

\end{cases}

\]

Here, () represents the charge for cubic yards delivered, and is the threshold value in cubic yards where the charge changes.

To graph this function, we can plot points on a coordinate plane by choosing different values for and . The resulting graph will have two parts: a flat line representing the flat fee of $130 for < , and a linear line representing the variable charge of $/ for ≥ . The point where these two lines meet will be the threshold value (, 130).

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Answers

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Answer:

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Step-by-step explanation:

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Answers

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Because:

5=1³ + 4
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5 = 5       (its correct)

129 = 5³ + 4
129 = 125 + 4
129 = 129