Which two ions have the same electron configuration?A) Na+ and O2- B) Li+ and F- C) Ca2+ and Br- D) Na+ and O3-
Answers
Answer: A) Na+ and O2-
Explanation:
To know the electronic configuration, one has to determine the numbers of electrons present in each atom.
Na+ means a sodium atom that has lost one valence electron. A Sodium atom initially has 11 electrons, but having lost an electron making it 10 electrons remaining with electron configuration of 1s2 2s2 2p6.
O2- means oxygen atom that has gained two valence electrons. An oxygen atom initially has 8 electrons, having gained two electrons makes it 10 electrons with electron configuration of 1s2 2s2 2p6. same as Na+
The purpose of gaining or losing electrons is to attain a stable duplet or octet structure.
The two ions with same electronic configuration are Na and O²
.
What is electronic configuration?
Electronic configuration is defined as the distribution of electrons of an atom or a molecule in orbitals of an atom or of a molecule.It describes each electron which is moving independently in it's orbital.
Electrons are able to move from one configuration to another by either absorption or emission of a quantum of energy, which is called as a photon.It is useful in understanding the structure of periodic table.
Considering the pair of sodium cation and oxygen anion the sodium atom with one positive charge has 10 electrons and oxygen anion with two negative charge has 10 electrons .
The elements with same number of electrons are called isoelectronic species.
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Related Questions
Life is possible on earth because of suitable air water and temperatures true or false
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How do electrons populate atoms?
Which of the following elements will likely form a negative ion in its ionic compounds?a. Li, lithium c. Mg, magnesium b. Al, aluminum d. Cl, chlorine
B) decomposition
C) combustion
Answers
Answer:
Type of reactions :
- Decomposition (O is seperated)
compact bone, marrow, periosteum, spongy bone
B
marrow, spongy bone, compact bone, periosteum
C
spongy bone, periosteum, compact bone, marrow
D
periosteum, compact bone, spongy bone, marrow
Answers
Explanation: The outer part of the bone is called the compact bone.
Final answer:
The correct order of bone layers from outside to inside is Periosteum, compact bone, spongy bone, and marrow. This corresponds to option D in your question.
Explanation:
The structure of a bone from the outside to the inside is labeled as follows: First, the outermost later is the periosteum. It is a dense layer made up of connective tissue, which provides nourishment and support. The next layer inside is the compact bone. It provides hardness and strength.
Beneath the compact bone is the spongy bone which is porous and lighter, offering shock absorption to the bone. Finally, at the very center is the marrow, responsible for the production of red blood cells. So, the correct answer is D: Periosteum, compact bone, spongy bone, marrow.
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Answers
1s^2 2s^2 2p^6 3s^2 3p^6 3d^2 4s^2
Answers
Answer:
one more proton
Explanation:
The symbol for phosphorous is P; it is element 15 on the Periodic Table. That
means phosphorous-31 has 15 protons. The symbol for sulfur is S; it is
element 16 on the Periodic Table. Sulfur-32 has 16 protons.
Answers
106 g Na₂CO₃ -------- 2 x 36.5 g HCl
x g Na₂CO₃ ---------- 750 g HCl
Mass of Na₂CO₃ = 750 x 106 / 2 x 36.5
Mass ( Na₂CO₃) = 79500 / 73
Mass = 1089.04 g
Number of moles = 1089.04 / 106 => 10.27 mols of Na₂CO₃
hope this helps!
Final answer:
To fully react with 750 g of HCl (approximately 20.5 moles), a minimum of 10.25 moles of sodium carbonate is needed.
Explanation:
To calculate the minimum amount of sodium carbonate needed to react fully with 750 g of HCl, we need to start by converting the 750 g of HCl to moles. The molecular weight of HCl is about 36.5 g/mol, so 750 g is about 20.5 mol of HCl. Looking at the reaction equation Na2CO3 + 2HCl → 2NaCl + CO2 + H2O, you can see that you need one mole of sodium carbonate to react with two moles of HCl. Therefore, to fully react with 20.5 mol of HCl, you will need a minimum of 10.25 mol of sodium carbonate.
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