3 times 7 plus 4 to the second power minus 14 divided by 2

Answers

Answer 1
Answer: 3 times 7 plus 4 to the second power minus 14 divided by 2
=> 3 x 7 + 4^2 - 14 / 2
Let's group this one.
=> (
3 x 7) + 4^2 - (14 / 2)
=> 21 + 16 - 7
=> 30
The answer is 30.
Answer 2
Answer: It's 29 not thirty some thing was done wrong to get 30

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One yardstick for measuring how steadily—if slowly—athletic performance has improved is the mile run. In 1958​, the local record for the running of a certain distance was 3​ minutes, 59.3 ​seconds, or 239.3 seconds. In the​ half-century since​ then, the record has decreased by 0.5 seconds per year.

Answers

Answer:

They will hit 180 seconds in 118.6 year

Step-by-step explanation:

Let M be the record for the mile (in seconds)

Let x be the year after 1958

So, x=(year)-19548

We are given that In the​ half-century since​ then, the record has decreased by 0.5 seconds per year

So, slope = m = 0.5

Now we will use point slope form

y = mx+c

So, we can express M as,

M=239.3-0.5 * x

Now we are supposed to find when they will hit 180 seconds

Substitute M = 180 in equation

180=239.3-0.5x

x=118.6

So, they will hit 180 seconds in 118.6 year

Final answer:

You can model the decreasing record time with the linear equation y=239.3-0.5x, where x is years since 1958 and y is the run time in seconds. By using this model, you can find the record time for any given year.

Explanation:

The subject of this question is Mathematics, specifically linear equations. The question mentions an initial record of 239.3 seconds for a run which decreases by 0.5 seconds every year. We are tasked to find the running time after a certain number of years.

Let's let x represent the number of years since 1958 and y represent the number of seconds to run the race. Based on the information provided:

  • The starting time (y-intercept) in 1958 was 239.3 seconds.
  • The rate of decrease (slope) is 0.5 seconds per year.

Therefore, the relationship between x and y can be expressed by the linear equation: y=239.3-0.5x

To find a certain year's running time, we substitute the number of years passed since 1958 into x in the equation above and solve for y. For example, to find the running time in 50 years after 1958 (2008), we replace x with 50: y = 239.3 - 0.5(50) = 214.3 seconds.

Learn more about Linear Equations here:

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Jackie is making flower arrangements. She has 2 roses and 4 daisies. If Jackie wants to make all the arrangements identical and have no flowers left over, what is the greatest number of flower arrangements she can make?help<3

Answers

Let's explore possible case scenarios.

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Case A) Each person gets a rose and a daisy (2 flowers per person)

In this case, Jackie can make 2 such arrangements because she has 2 roses. We have 2 left over daisies.

---------------------

Case B) Each person gets a rose only (1 flower per person)

Only two arrangements are possible for the same reason as case A. In this situation, we have 4 left over daisies.

----------------------

Case C) Each person gets a daisy only (1 flower per person)

We have 4 arrangements possible because we have 4 daisies. The left over flowers are the 2 roses.

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Case D) Each person gets 2 roses

Only one such arrangement is possible, so this only applies to one person really. You can say that 2/2 = 1. We have 4 left over daisies in this case.

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Case E) Each person gets 2 daisies

Since 4/2 = 2, this means we can make 2 arrangements. There are 2 left over roses.

------------------------

Case F) Each person gets 2 daisies and 1 rose

We can see that 4/2 = 2 and 2/2 = 1, meaning that we can make at most 2 arrangements here. There are no leftovers. In contrast, the other cases do have leftovers of some kind.

------------------------

In short, you can do trial and error to see which case works to fit the conditions your teacher set. Case F is what we go for to have each flower bouquet consist of 2 daisies and 1 rose. We'll get 2 bouquets possible. Notice how cases A through E have at least one left over flower (either of one kind or both types), while case F has no leftovers.

Can someone help me out 10 points

Answers

Answer:

1. B (firefighter question)     2. A (dance lesson fee question)     3. A (dolphin question)

Step-by-step explanation:

1. The firefighters gear PLUS his weight is how much he weighs in total.

2. An added fee is usually represented as a registration fee or staring fee. There was 45w which should represent the fee she paid every week.

3. The dolphin swims at a rate of 25 kilometres per hour. The graph represents the distance the dolphin traveled because in two hours the dolphin would travel 50 kilometres (25 kilometres*2 hours) and so on.

Answer:

B

Step-by-step explanation:

A hyperbola is the set of all points in a plane such that the absolute value of the difference of the distances from two fixed points, called the foci, is constant.Please select the best answer from the choices provided

A. True
B. False

Answers

The answer is true, by definition, its true.

Answer:

A. True

Step-by-step explanation:

Got it right on edge

If 16+4x is 10 more than 14, what is the value of 8x?

Answers

16 + 4x = 10 + 14

16 + 4x = 24.

4x = 24 - 16

4x = 8

x = 8 ÷ 4

x = 2

8x = 2 × 8

8x = 16

Final answer = 16.

Final answer:

To find the value of 8x, first solve the equation 16 + 4x = 14 + 10 by isolating the term with 4x. The value of x is found to be 5. Substituting the value of x into 8x gives the answer of 40.

Explanation:

To find the value of 8x, we need to first solve the equation 16 + 4x = 14 + 10. First, we subtract 14 from both sides to isolate the term with 4x. This gives us 16 + 4x - 14 = 14 + 10 - 14. Simplifying, we have 4x + 2 = 24. Next, we subtract 2 from both sides to isolate 4x. This results in 4x = 22. Finally, we divide both sides by 4 to find the value of x, which is 5. Now, we can substitute the value of x into the expression 8x to find the answer.  8x = 8(5) = 40.

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Make x the subject of the formula r = \sqrt{ (ax - p)/(q + bx) }




Answers

Answer:

\boxed{x  =  \frac{p + q {r}^(2) }{a - b {r}^(2) } }

Step-by-step explanation:

Solve  \: for  \: x: \n  =  > r =  \sqrt{ (ax - p)/(q + bx) }  \n  \n </p><p>r =  \sqrt{ (ax - p)/(q + bx) }  \:  is \:  equivalent \: to \:   \sqrt{ (ax - p)/(q + bx) }  = r :\n  =  > \sqrt{ (ax - p)/(q + bx) }  = r \n  \n Raise \:  both \:  sides  \: to \:  the  \: power \:  of  \: two:  \n =  >   (ax - p)/(q + bx)  =  {r}^(2) \n  \n Multiply  \: both  \: sides \:  by  \: (q + b x):  \n  =  > ax - p =  {r}^(2) (q + bx) \n  \n Expand  \: out \:  terms \:  of  \: the \:  right  \: hand  \: side:  \n =  >  ax - p = q {r}^(2) + b {r}^(2)x \n  \n Subtract \:  b {r}^(2)x - p \:   from \:  both \:  sides:  \n  =  >   x(a - b {r}^(2) ) = p + q {r}^(2)  \n  \n  Divide \:  both \:  sides  \: by \:  a - b {r}^(2) :  \n  =  > x  =  \frac{p + q {r}^(2) }{a - b {r}^(2) }