When x=3 and y=5 by how much does the value of 3x^2-2y exceed the value of 2x^2-3/

Answers

Answer 1
Answer:

x = 3

y = 5

3x^2 – 2y

= 3(3)^2 - 2(5)

=> 3(9) - 10 = 17

And 2x^2– 3y

=> 2(3)^2 - 3(5)

=> 2(9) - 15 = 3

17 - 3 = 14

This gives 3x^2 – 2y exceeding 2x^2– 3y by 17 - 3 = 14

Answer 2
Answer: 14 is the correct answer.

When you use x = 3 and

 
y = 5 in the given expressions, 3x2 – 2y = 3(3)2– 2(5) = 27 – 10 = 17 and

2x2 – 3y = 2(3)2 – 3(5) = 18 – 15 = 3.

Then subtract 3 from 17....17-3 = 14.

14 is your answer.

Hope I helped ;]

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ind the equation of a line perpendicular to y - 3x = – 8 that passes through the point (3, 2). (answer in slope-intercept form)

Answers

we have that
Find the equation of a line perpendicular to y - 3x = – 8 that passes through the point (3, 2)
y - 3x = – 8-----> y=3x-8------> the slope m=3

we know that
if two lines are perpendicular 
then
m1*m2=-1
m1=3
so
m2=-1/3

with m=-1/3 and point (3, 2) find the equation of the line
y=mx+b
2=(-1/3)*3+b------> 2=-1+b-----> b=3

the equation of the line is
y=(-1/3)x+3

the answer is
y=(-1/3)x+3

see the attached figure

15 yards to 18 yards

Answers

Answer: The distance between 15 yards to 18 yards is 3 yards.

Step-by-step explanation:

In Markov chains, if I was given a transition probability matrix with each of the probabilities specified, then how do I determine the following:1- Probability that state y is visited at least n times given that you start in state x. I know that I can solve it using Px(# of visits to state y ≥ n) = rhoxy(rhoyy)n−1 where rhoxy is the probability that starting at state x, I will be in state y in some positive time (i.e. rhoxy=Px(Ty<[infinity])). But I am not sure how to calculate rhoxy and I have spent so much time trying to figure it out!

Answers

Answer:

bbcs

Step-by-step explanation:

msade rekfflg.g

Which expression is equivalent to (st)(6)?O s(t(6))
O s(x) × t(6)
Os(6) × t(6)
O 6 × S(x) × t(x)

Answers

Hello!

Answer:

\large \boxed{\sf {\circ} ~~~s(t(6))}

Step-by-step explanation:

→ We want an expression wich is equivalent with (st)(6).

→ Let's develop this expression:

\sf (st)(6)\n\n= \ (st) * 6\n\n= 6st\n\n= 6 * s * t\n\n= s * 6t\n\n= s(6t)\n\n= s(6 * t)\n\n= s((t(6))

Conclusion:

So an equivalent expression of (st)(6) is s((t)(6)).

Final answer:

The term (st)(6) in mathematics signifies that 's' and 't' are multiplied together, and the result is then multiplied by '6'. Using the associative property of multiplication, the equivalent expression is s(t(6)).

Explanation:

In mathematics, the expression (st)(6) signifies multiplication. The presence of parentheses indicates that the variables 's' and 't' should be multiplied together first, and then the product should be multiplied by '6'. This principle is known as the associative property of multiplication, which states that the way in which factors are grouped in a multiplication problem does not change the product. Therefore, the equivalent expression to (st)(6) is s(t(6)), which means 's' multiplied by the product of 't' and '6'.

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8. The base of a circular cone has a diameter of 10 cm and an altitude of 10 cm. The cone is filled with water. A sphere is lowered into the cone until it just fits. Exactly one-half of the sphere remains out of the water. Once the sphere is removed, how much water remains in the cone?

Answers

Answer:

The volume of water that remains on the cone is 523.6 cm³

Step-by-step explanation:

To solve this problem you have to keep in mind the formules that describes the volume of a cone and the volume of a sphere.

Volume of a cone = (πr²h)/3

Volume of a sphere = (4/3)πr³

So, if the base of the cone has a diameter of 10 cm, its radius is 5 cm. Its altitude is 10 cm. ⇒Volume = (πr²h)/3 ⇒ Volume = [π(5²)10) ⇒

          Volume = 785.4 cm³. This is the initial volume of water.

Now if the sphere fits in the cone and half of it remains out of the water, the other half is inside the cone. Estimating the volume of the sphere and dividing it by two, you find the volume of water that was displaced.

Volume of a sphere = (4/3)πr³, here the radius is the same of the base of the cone (5 cm).

⇒ Volume = (4/3)π(5³)  ⇒ Volume = 523.6 cm³ ⇒ The half of this volume is 261.8 cm³. This is the volume of water displaced.

⇒ The volume of water that remains on the cone is 523.6 cm³ (785.4 cm³- 261.8 cm³)

What is 23 squared A. 1,058 B.129 C. 46 D. 529

Answers

The value of 23 squared is 529

What is square of a number?

A square number or perfect square is an integer that is the square of an integer; in other words, it is the product of some integer with itself.

For example, the 3² is 3 × 3 i.e the product of the 3 by itself , which is 9

Similarly, the square of 23 is 23² which is the same as the 23 × 23

= 529

Therefore the square of 23 is 529. this means that 23² = 529 and the square root of 529 is 23.

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23 squared is 529 because 23 x 23 is 529, so the answer is D.