The basic skill of advancing and controlling the ball to your feet while running.

Answers

Answer 1

Answer: Direct Free Kick
Pass
and Dribbling

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It is proposed that future space stations create an artificial gravity by rotating. Suppose a space station is constructed as a 1600-m-diameter cylinder that rotates about its axis. The inside surface is the deck of the space station. What rotation period will provide "normal"gravity?

Answers

The rotation period that will provide normal gravity will be 57.12 seconds.

From the information given, the diameter of the cylinder is 1600m. Therefore, the radius will be:

= Diameter / 2.

= 1600 / 2

= 800m

Acceleration due to gravity = 9.8m/s²

Since a = rw², we'll use the subject of the formula to find w and this will be:

w = √g/✓r

w = ✓9.8 / √800

w = 0.11 rad/s

Therefore, the rotation period will be:

T = 2π/w

T = 2π/0.11

T = (2 × 3.142) / 0.11

T = 57.12 seconds

In conclusion, the correct option is 57.12 seconds.

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Answer

given,

diameter of the cylinder = 1600 m

radius = 800 m

acceleration due to gravity = 9.8 m/s²

a = r ω²

$\omega = \sqrt{(g)/(r)}$

$\omega = \sqrt{(9.8)/(800)}$

$\omega = 0.11\ rad/s$

we know time period

$T = (2\pi )/(\omega )$

$T = (2\pi )/(0.11)$

T = 57.12 s

The more particles a substance has at a given temperature, the more thermal energy it has.

Answers

The statement 'The more particles a substance has at a given temperature, the more thermal energy it has' is true. The kinetic molecular theory of gases has three main laws and one of them is the average kinetic energy of the particles in a gas. The average kinetic energy of the gas particles is the behavior and movement it does in the surroundings. It is directly proportional to temperature wherein if you increase the temperature, the kinetic energy of a particle also increases. It will also decrease its movement or its kinetic energy if the temperature lowers.

What are the primary differences between stars and planets

Answers

Stars don't have moons and planets do

stars aren't big enough to emit enough kight and heat meaning they cant cause nuclear reactions

How many nitrogen atoms are in one molecule of (NH4)2SO4?

Answers

15 nitrogen atoms are in one molecule

Final answer:

In one molecule of (NH4)2SO4 or ammonium sulfate, there are two nitrogen atoms.

Explanation:

The molecule (NH4)2SO4 is known as ammonium sulfate. This molecule is composed of two ammonium ions (NH4) and one sulfate ion (SO4). The ammonium ion consists of one nitrogen atom (N) and four hydrogen atoms (H). Because the formula indicates there are two ammonium ions (as shown by the subscript '2'), this means the overall molecule of ammonium sulfate contains two nitrogen atoms.

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A spacecraft is fueled using hydrazine (N2H4; molecular weight of 32 grams per mole [g/mol]) and carries 1640 kilograms [kg] of fuel. On a mission to orbit a planet, the fuel will first be warmed from −186 degrees Fahrenheit [°F] to 78 degrees Fahrenheit [°F] before being used after the long space flight to reach the planet. The specific heat capacity of hydrazine is 0.099 kilojoules per mole kelvin [kJ/(mol K)]. If there is 300 watts [W] of power available to heat the fuel, how long will the heating process take in units of hours [h]?

Answers

The expression for thermal energy and power we were able to find the time necessary to heat the fuel is t = 689 h

To find

Time

The international measurement system (SI) establishes the fundamental units in the measurement processes, this is defined by convention, giving uniformity in the calculation process and measurement exchange. Before starting the exercise we must reduce the magnitude to the SI system

PM = 32 g / mol ( $(1 kg)/(1000 g)$ g) = 32 10-3 kg / mol

T₀ = 5/9 (ºF -32) + 273.15 = 5/9 (186 32) +273.15 = 152.0 K

T_f = 5 * (78 - 32) +273.15 = 298.7 K

c_e = 0.099 kj / mol k ( $(1000J)/(1 kJ)$ ) = 0.099 10³ J / mol K

The mole is the amount of matter of the international system (SI), the moles exist must be calculated since they are the mass of the compound for this we use a direct rule of proportions, if a mole has more than 32 10⁻³ kg, when moles are 1640 kg

n = $(m)/(PM)$

n = 1640/32 10⁻³

n = 51.25 10³ mol

If we assume that all energy transfer is thermal, we can use

Q = $m\ c_e ( T_f - T_o)$

Q = 51.25 10³ 0.099 10³ (298.7 -152.0)

Q = 7.44 10⁸ J

Power defined by the relationship between work and time

P = $(W)/(t)$

In this case the thermal work is equal to the heat ( W=Q)

t = $(Q)/(P)$

t = 7.44 10⁸ / 300

t = 2.48 10⁶ s

They indicate that the answer is given in hours, let's reduce the time

t = 2.48 106 s (1h / 3600s)

t = 6.89 10² h

In conclusion, with the relationship of thermal energy and power, we were able to set the time necessary for the amount of fuel to be t = 689 h

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Answer:

The value is $t = 689.029 \ hours$

Explanation:

From the question we are told that

The molar mass of hydrazine is $Z = 32 g/mol = (32)/(1000) = 0.032 \ kg/mol$

The initial temperature is $T_i = -186 ^o F = (-186-32) *(5)/(9) +273.15 = 152\ K$

The final temperature is $T_f = 78 ^o F = (78-32) *(5)/(9) +273.15 = 298.7 \ K$

The specific heat capacity is $c_h = 0.099 [kJ/(mol K)] = 0.099 *10^3 J/(mol/K)$

The power available is $P = 300 \ W$

The mass of the fuel is $m = 1640 \ kg$

Generally the number of moles of hydrazine present is

$n = (m)/(Z)$

=> $n = (1640)/(= 0.032)$

=> $n = 51250 \ mol$

Generally the quantity of heat energy needed is mathematically represented as

$Q = n * c_h * (T_f -T_i)$

=> $Q = 51250 * 0.099 *10^3 * (298.7 - 152)$

=> $Q = 7.441516913 * 10^(8) \ J$

Generally the time taken is mathematically represented as

$t = (Q)/(P)$

=> $t = (7.441516913 * 10^(8) )/(300)$

=> t = 2480505.6377 s

Converting to hours

$t = (2480505.6377)/(3600)$

=> $t = 689.029 \ hours$

You use a 1200-watt hair dryer for 10 minutes each day. a. How many minutes do you use the hair dryer in a month? (Assume there are 30 days in the month.) b. How many hours do you use the hair dryer in a month? c. What is the power of the hair dryer in kilowatts? d. How many kilowatt-hours of electricity does the hair dryer use in a month? e. If your town charges $0.15/kWh, what is the cost to use the hair dryer for a month?