A student is offered two different summer jobs. Job A lasts 16 weeks and pays $350.00 per week. Job B lasts 4 months and pays $1,500.00 per month, with monthly raises of 10% of the previous month's salary. How much more does the student earn by accepting Job B (rounded to the nearest cent)?

The required, by accepting job B a student can earn $1361.5 more than Job A.

What is arithmetic?

In mathematics, it deals with numbers of operations according to the statements. There are four major arithmetic operators, addition, subtraction, multiplication, and division,

here,
Job B lasts 4 months and pays $1,500.00 per month, with monthly raises of 10% of the previous month's salary.
Total earnings in 4 months,
= 1500 + 1.1×1500 + 1.1 [1.1×1500] + 1.1×[ 1.1 [1.1×1500] ].
= $6961.5

Job A lasts 16 weeks and pays $350.00 per week.
Total earnings in 16 weeks,
= 16 × 350 = $5600

The difference in earning = Job B - Job A
                                 = 6961.5 - 5600
                                 = 1361.5

Thus, the required, by accepting job B a student can earn $1361.5 more than Job A.

Learn more about arithmetic here:

brainly.com/question/11424589

#SPJ2

Both last 4 months.

Job B = $412.50per/week

Job A = $1600per/month

1650*1.1 = 1815 Month 2's paycheck

1815*1.1 = 1996.5 Month's 3 Paycheck

1996.5*1.1 = 2196.15 Month 4's paycheck

1600*4 = $6400 Job A total

1650+1815+1996.5+2196.15 = $7657.65 Job B total

7657.65-6400 = 1257.65

$1257.65 more thant Job A