What is the advantage of combining carbon from coal with steel?

Answers

Answer 1

Answer:

The role of Carbon in steel is to increase hardness and tensile strength as well as response to heat treatment (hardenability). Increased amounts of carbon also reduces weldability. It is usually present to up to 2% carbon.

Related Questions

If the velocity of a body changes from 13 m/s to 30 m/s while undergoing constant acceleration, what's the average velocity of the body? A. 28 m/s B. 17 m/s C. 21.5 m/s D. 19.5 m/s
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The amount of matter in a substance or object is called:??? What the answer
A force of 450 N accelerates a box across a frictionless surface at a rate of 15 m/s2. What is the mass of the box? 30 N 30 kg 6,750 N 6,750 kg
a ball is dropped from rest at a height of 80 m above the ground. what is the speed just as it hits the ground?

What is a time paradox?

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Hey There Wolfie,

What is a time paradox?

A temporal paradox, time paradox, or time travel paradox is aparadox, an apparent contradiction, or a logical contradiction that is associated with the idea of time and time travel. Temporal paradoxesfall into two broad groups: consistency paradoxes exemplified by the grandfather paradox; and causal loops

The magnitudes of the vectors in this diagram are vx/y = 17.94 meters/second and vy/z = 3.46 meters/second. Find vx/z.

Answers

It's very hard to make out the diagram. I think we need
to see it clearly in order to answer the question.

Answer:

See image

Explanation:

Plato

How to do this problem

Answers

Answer:

v = 12,4 m/s

Explanation:

frictionless means all gravitational Energie (Eg) will be converted to kinetic Energie (Ek)

Ek = 0.5 * m * v^2

Ez = m * g * h

Ek = Ez

0.5 * m * v^2 = m * g * h

divide left and right of the = sign by m.

(This means that the final velocity is independent of the mass of both children !)

0.5 * v^2 = g * h

v^2 = 2 * g * h

v = +- SQRT (2 * g * h)

with

g = 9.8 m/s^2

h = 7,8 m/s

v = +- SQRT (2 * 9.8 * 7.8)

v = +- SQRT (152.88)

(v = - 12,4 m/s has no meaning in this case)

The velocity 7,8 m below the starting point, will be

v = 12,4 m/s

Answer:

the answer is 336.96 mph

Explanation:

hope this helps ^_~

What does Dependent viable meaning in science

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Its the variable which you measure in an experiment. For example, you're conducting an experiment in order to find out how proportions of water affect plant growth, then, your dependent variable should be the height of the plants in the experiment.

What molecules has a zero dipole moment?

Answers

Answer:

Nonpolar molecules

Explanation:

Nonpolar molecules are those molecules that are produced by the union between atoms that have equal electronegativity, so the forces with which the atoms that make up the molecule attract the electrons of the bond are equal, thus causing the cancellation of these forces. An example of an nonpolar molecule is the Oxygen (O2) molecule. In this molecule each oxygen atom attracts the electrons shared towards itself with the same intensity but in opposite directions, therefore the forces of attraction are annulled and the molecule does not become a dipole.

A resistor is connected in series with an AC source that provides a sinusoidal voltage of v of t is equal to V times cosine of begin quantity omega times t end quantity, where V is the maximum voltage, omega is the angular frequency, and t is the time. The current supplied by this source that flows through this resistor is described with the function i of t is equal to I times cosine of begin quantity omega times t end quantity, where I is the maximum current. What is the average power supplied by this AC source?

Answers

Answer:

In circuits, the average power is defined as the average of the instantaneous power over one period. The instantaneous power can be found as:

$p(t)=v(t)i(t)$

So the average power is:

$P=(1)/(T)\intop_(0)^(T)p(t)dt$

But:

$v(t)=v_(m)cos(\omega t) \n \n i(t)=i_(m)cos(\omega t)$

So:

$P=(1)/(T)\intop_(0)^(T)v_(m)cos(\omega t)i_(m)cos(\omega t)dt \n \n P=(v_(m)i_(m))/(T)\intop_(0)^(T)cos^(2)(\omega t)dt \n \n But: cos^(2)(\omega t)=(1+cos(2\omega t))/(2)$

$P=(v_(m)i_(m))/(T)\intop_(0)^(T)((1+cos(2\omega t))/(2) )dt \n\nP=(v_(m)i_(m))/(T)\intop_(0)^(T)[(1)/(2)+(cos(2\omega t))/(2)]dt \n\nP=(v_(m)i_(m))/(T)[(1)/(2)(t)\right|_0^T +(sin(2\omega t))/(4\omega) \right|_0^T] \n \n P=(v_(m)i_(m))/(2T)[(t)\right|_0^T +(sin(2\omega t))/(2\omega) \right|_0^T] \n \n P=(v_(m)i_(m))/(2)$

In terms of RMS values:

$V_(RMS)=V=(v_(m))/(√(2)) \n \n I_(RMS)=I=(i_(m))/(√(2)) \n \n Then: \n \n P=VI$

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Assume that the upward direction is positive and the downward direction is negative. What is the ball's velocity (in m/s) when it returns to the level where it left your hand? (Indicate the direction with the sign of your answer.)