Select one of the factors of 3x2 + 4x − 4.
(x + 4)
(3x + 2)
(3x − 2)
(x − 2)

Answers

Answer 1

Answer: x-c where c is a number is a factor of the function if and only if the result of the operation gives a remainder is 0. It has been said that R is equal to the function of c. Calculation for this are as follows;

R = f(c) = 0 = 3x^2 + 4x - 4

Solving for x, we obtain

x = 2/3
x = -2

From the choices the answer is the 3rd option.

Answer 2

Answer:

Answer:

(3x − 2)

Step-by-step explanation:

Given : $3x^2 + 4x - 4$

To Find : Select one of the factors of $3x^2 + 4x - 4$

Solution:

$3x^2 + 4x - 4=0$

$3x^2 + 6x-2x - 4=0$

$3x(x + 2)-2(x +2)=0$

$(x + 2)(3x-2)=0$

Hence (3x − 2) is one of the factors of $3x^2 + 4x - 4$

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Answer:the Answer is 1/9

Step-by-step explanation:

a farmer has 1235 trees to be planted on a rectangular parcel of land. if there are 24 trees planted in each row and each row must be completed before it is planted, how many trees will be left over after planting?

Answers

The required number of trees that were left over after planting is 11.

Given that,
A farmer has 1235 trees to be planted on a rectangular parcel of land. if there are 24 trees planted in each row and each row must be completed before it is produced, how many trees will be left over after planting is to b determined.

What is arithmetic?

In mathematics, it deals with numbers of operations according to the statements.

Total number of trees = 1235
Total numbers of trees in a row = 24
Number of trees left = quotient + remainder / divisor
= 1235/24
= 51 + 11 / 24

Thus, the required number of trees that were left over after planting is 11.

Learn more about arithmetic here:

brainly.com/question/14753192

#SPJ2

24 trees per row
1235 trees to plant

1235 / 24 = 51 remainder 11

There will be 11 trees left over

Trig help (Problems already solved)?The calculation for the problems are already done but I have to list a reason or what is being done in each step. "Each = and newline made" means a place I have to write what is being done in the calculation.

1. (secx + sinx)cotx = cscx + cosx
=(secx + sinx)cotx = cscx + cosx
=(1 / sinx) + cosx
=cscx + cosx

2. cosx + tanx sinx = secx
=cosx + tanx sinx = cosx + (sinx / cosx)sinx
=cosx + (sin^2x / cosx) = (1 / cosx)(cos^2x + sin^2x)
=1 / cosx
=secx

3. cscx - cosx cotx = sinx
=cscx - cosx cotx = (1 / sinx) - cosx(cosx / sinx)
=(1 / sinx) - (cos^2x / sinx)
=(1 - cos^2x) / sinx
=sin^2x / sinx = sinx

4. (cosx / (1 + cosx)) + (cosx / (1 - cosx)) = 2cotx cscx
=(cosx / (1 + cosx)) + (cosx / (1 - cosx)) = ((cosx (1 - cosx) + cosx (1 + cosx))) / (1 + cosx)(1 - cosx)
=(cosx - cos^2x + cosx + cos^2x) / (1 - cos^2x)
=2cosx / sin^2x
=2(cosx / sinx)(1 / sinx) = 2cotx cscx

Thank you to whoever decides to help me with explaining what is happening on each line.

Answers

The first identity uses the definition of the reciprocal functions $\sec x,\csc x,\cot x$ and the distributive property of multiplication.

$(\sec x+\sin x)\cot x=\left(\frac1{\cos x}+\sin x\right)(\cos x)/(\sin x)$
$=(\cos x)/(\cos x\sin x)+(\cos x\sin x)/(\sin x)$
$=\frac1{\sin x}+\cos x$
$=\csc x+\cos x$

The second uses the definition of $\tan x$ and the distributive property. Then a factor of $\frac1{\cos x}$ is pulled out, which allows you to use the identity $\sin^2x+\cos^2x=1$ .

$\cos x+\tan x\sin x=\cos x+(\sin x)/(\cos x)\sin x$
$=\cos x+(\sin^2x)/(\cos x)$
$=(\cos^2x)/(\cos x)+(\sin^2x)/(\cos x)$
$=\frac1{\cos x}\left(\cos^2x+\sin^2x\right)$
$=\frac1{\cos x}*1$
$=\frac1{\cos x}$
$=1$

The third uses the same ideas as the second: rewrite the reciprocal functions, then invoke the Pythagorean identity $\sin^2x+\cos^2x=1$ , which is equivalent to $\sin^2x=1-\cos^2x$ .

$\csc x-\cos x\cot x=\frac1{\sin x}-\cos x(\cos x)/(\sin x)$
$=\frac1{\sin x}-(\cos^2x)/(\sin x)$
$=\frac1{\sin x}\left(1-\cos^2x\right)$
$=\frac1{\sin x}\sin^2x$
$=(\sin^2x)/(\sin x)$
$=\sin x$

In the last one, you combine the fractions by enforcing common denominators. This lets you add the numerators together, and the denominator can be simplified. Once you do that, you rewrite the factors of cos and sin in the numerator and denominator to make up the cot and csc functions, and you're done.

$(\cos x)/(1+\cos x)+(\cos x)/(1-\cos x)=(\cos x(1-\cos x))/((1+\cos x)(1-\cos x))+(\cos x(1+\cos x))/((1-\cos x)(1+\cos x))$
$=(\cos x(1-\cos x)+\cos x(1+\cos x))/((1-\cos x)(1+\cos x))$
$=(\cos x(1-\cos x+1+\cos x))/(1-\cos^2x)$
$=(2\cos x)/(\sin^2x)$
$=2(\cos x)/(\sin x)\frac1{\sin x}$
$=2\cot x\csc x$

The temperature dropped by −2.5 Celsius degrees for 5 consecutive days. What was the total decrease in temperature over the 5-day period, expressed as a signed number?

Answers

If the temperature dropped by -2.5 for 5 days, then multiply -2.5 and 5 to get the total decrease.
(-2.5)(5) = -12.5
Over the 5-day period, the temperature dropped by -12.5 degrees Celsius.
Hope that helps!!

-12.5

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What is the sum of 3/8 and 1/16

Answers

7/16 is the answer to the addition of those two fractions

(3/8) x 2 = 6/16+ 1/16= 7/16
Hope this helps:)

Evaluate: xy - x (x - y^0) if x = 2 and y = -1/2

Answers

Hi

2(-1/2) - 2(2+(-1/2)^0)
= -2/2 - 2(2+(-1/2)^0)
= -1 - 2(2+(-1/2)^0)
= -1 -2 (2+1)
= -1 -2(3)
= -1 -6
= -7

I hope that's help :)

If you have any further questions please let me know :)

$2(- (1)/(2) ) - 2(2+(- (1)/(2))^0)$

$- (2)/(2) - 2(2+(- (1)/(2) )^0)$

$-1 - 2(2+(- (1)/(2) )^0)$

$-1 -2 (2+1)$

$-1 -2*(3)$ -1 -2(3)

$-1 -6$

$-7$

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Select one of the factors of 3x2 + 4x − 4. (x + 4) (3x + 2) (3x − 2) (x − 2)

Answers

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Select one of the factors of 3x2 + 4x − 4.
(x + 4)
(3x + 2)
(3x − 2)
(x − 2)