Look up the density of n-butyl chloride (1-chlorobutane). Assume that this alkyl halide was prepared instead of the bromide. Decide whether the alkyl chloride would appear as the upper or the lower phase at each stage of the separation procedure: after the reflux, after the addition of water, and after the addition of sodium bicarbonate.
Answers
Answer:
See explanation below
Explanation:
First, you need to know the density of each compound in order to know this.
The density of 1-chlorobutane is 0.88 g/mL,
The density of water is 1 g/mL
The density of sodium bicarbonate is 2.2 g/cm3.
therefore, the one that has a greater density will always go at the lower phase.
In this case, after the reflux, it will stay in the lower phase, basically because you don't have another solvent with a greater density than the butane.
After adding water, it will be in the upper phase, water has a greater density.
After adding bicarbonate, it will be in the upper phase too.
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What is the chemical equation of ccl4, please explain thank you! :-D
Which compound is an electrolyte? 1. H2O 2. C2H6 3. H3PO4 4. CH3OH
Answers
I won't give you the answer, but I will give you the process and then you can plug in the numbers. I'm guessing you are looking for how many MOLES are in 63.658g of Carbon. What you need to do to solve this is to use the molar mass of Carbon plugged into the dimensional analysis process. That might sound confusing, so let me give you a sample question.
Now, you plug in the numbers in your problem into that sample process. And if you don't know where to find the molar mass, it's simple.
The Molar mass of an element is the same as the atomic mass. So Hydrogen has the atomic mass of 1.01u, and it also has the molar mass of 1.01 grams per mole.
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107*7 = 749km in one week
749/1.6 = 468.125 miles
468.125/39 = 12.0032051282 gallons of fuel needed
1 gallon = 4.54609 litres
1.1(Cost per litre)*4.54609(Number of litres per gallon)*12.0032051282(Number of gallons needed) = 60.0244158814 euros cost per week
60.0244158814 * 1.26 = 75.6307640105 dollar cost per week
$75.63
Answer:
$ 62.578
Explanation:
Conversion factors:
1 gal = 3.785 L
1.609km = 1 mi
$1.26 = 1 euro
1 week = 7 days
Converting the car’s mileage from mi/gal to km/L
39 mi/gal x 1 gal/3.785L x 1.609km/1 mi = 16.578 km/L
Finding the L required in a day
107 km x 1L/16.578 km = 6.45 L
Finding the euro spent in day
1.10 euro/L x 6.45 L = 7.095 euro/ day
Finding the euro spent in a week and converting it to dollars
7.095 euro/ day x 7 days x $1.26/ 1 euro = $ 62.578
Answers
A rate equation can be written based on the rate constant k, concentration of reactants and half life time t1/2 of reactant if given. [A⁰] is the initial concentration of reactant A and [A]t be the final concentration.
What is rate of reaction?
Rate of a reaction is the rate of decrease in concentration of reactants or rate of increase in concentration of products. Rate of the reaction written in terms of molar concentration of reactants is called the rate law.
Consider the simplest reaction A gives B. Here the only one reactant is A. The molar concentration of A is written as [A]. The rate constant k is then,
k = [B] / [A]
If any coefficients attached with them it is written as power of the concentration term. Now, the rate of the above reaction is written as follows:
rate r = k [A]
Sometimes the initial and final concentrations of A can be considered. Where, [A⁰] is the initial concentration and [A]t be the final concentration.
The half life t1/2 is the time taken to consume half of the reactants concentration.
To find more about rate law, refer the link below:
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t1/2= half life
[A]= final concentration
k= rate constant
scale
ruler
graduated cylinder
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Answer: Balance
Explanation:
Answer:
balance
Explanation:
because
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The answer for the following problems is mentioned below.
- Therefore the number of moles present in Argon is 0.20 moles.
Explanation:
Mole:
The mass of a substance containing the same number of fundamental units as there are atoms in exactly 12.000 g of .
Given:
volume (v) = 4.7 litres
Volume of argon at STP conditions = 22.4 litres
To find:
volume of argon at STP conditions
We know;
n =
where;
n represents the no of moles
v represents the volume of the argon
V represents the volume of argon at STP
volume of the argon at STP conditions is 22.4 litres
So;
n =
n = 0.20 moles
Therefore the number of moles present in Argon is 0.20 moles.
Answers
Final answer:
The distance from Santa Maria to Los Alamos, which is 16.25 miles, would be approximately 2615178.4 centimeters when converted using the conversion factor of 1 mile = 160934.4 cm.
Explanation:
In order to convert the distance from miles to centimeters, you need to use conversion factors. We know that 1 mile is equivalent to approximately 160934.4 centimeters. Therefore, to find the distance from Santa Maria to Los Alamos in centimeters, you would multiply the number of miles by the number of centimeters in a mile.
The calculation would look like this:
16.25 miles * 160934.4 cm/mile = 2615178.4 cm
So, the distance between Santa Maria and Los Alamos is approximately 2615178.4 centimeters.
Learn more about Distance Conversion here:
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