What has at least one right angle but is not a square

Answers

Answer 1
Answer: There is a Right Triangle

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Write an inequality for the situation. all real numbers at most –9.5 or at least 5.5A. –9.5 ≤ b ≤ 5.5

B. b ≥ –9.5 or b ≥ 5.5

C. b ≤ –9.5 or b ≤ 5.5

D. b ≤ –9.5 or b ≥ 5.5

Answers

Answer:

option (c) is correct.

The given expression all real numbers at most –9.5 or at least 5.5 is written as   b ≤ –9.5  or  b ≥ 5.5

Step-by-step explanation:

Given  expression all real numbers at most –9.5 or at least 5.5

We have to represent the given expression mathematically and choose the correct from given options.

Consider the given expression  all real numbers at most –9.5 or at least 5.5

Let the real number be represented by b

then the given expression contain two terms

1)  all real numbers at most –9.5  

Mathematically written as  b ≤ –9.5    .....(1)

2) all real numbers at least 5.5

Mathematically written as  b ≥ 5.5       ....(2)

Thus, the given expression   all real numbers at most –9.5 or at least 5.5 is written as   b ≤ –9.5  or  b ≥ 5.5

Thus, option (c) is correct.

Hello,

If b represents any real number,

b<=-9.5
or
5.5<=b


Answer  C

Write the 4th degree polynomial function shown by the graph. The factors of the polynomial functions are

Answers

(x+3)(x+1)(x-2)(x-3) was the answer - second choice in my options. 

Answer to the second question - A=2

Answer:

EDGE 2021

1) B

2) a=2

Step-by-step explanation:

you've got this

Raquel and Van live in two different cities. As part of a project, they each record the lowest prices for a gallon of gas at gas stations around their cities on the same day. Raquel’s data reflect a mean price of $3.42 with a standard deviation of 0.07. Van’s data reflect a mean price of $3.78 with a standard deviation of 0.23.Which statement is true about their gas-price data?
A- Raquel’s data are most likely closer to $3.42 than Van’s data are to $3.78.
B- Van’s data are most likely closer to $3.42 than Raquel’s data are to $3.78.
C- Raquel’s data are most likely closer to $3.78 than Van’s data are to $3.42.
D- Van’s data are most likely closer to $3.78 than Raquel’s data are to $3.42.

Answers

the standard deviation shows the dispersion (how close) of the data. Therefore the correct statement is A:
A- Raquel’s data are most likely closer to $3.42 than Van’s data are to $3.78.

A is the answer my folks.

Evaluate f(x) = X(With an exponent of 2) -3x +2, given f(x + 1).

Answers

Answer:

f(x + 1) = x² - x

Step-by-step explanation:

f(x) = x² - 3x + 2 when f(x + 1)

f(x + 1) = (x + 1)² - 3(x + 1) + 2

f(x + 1) = (x² + 2x + 1) + (-3x - 3) + 2

f(x + 1) = x² - x + 0

f(x + 1) = x² - x

Best of Luck!

What is the slope of the line that passes through the points (–1, 13) and (4, –2)?A.-3
B.negative one-third

C.3
D.The slope is unidentified

Answers

y2 - y1
----------
x2 - x1

-2-13/4-(-1)=
-15/5=
-3/1=
-3

Answer A

A taut string of length 10 inches is plucked at the center. The vibration travels along the string at a constant rate of c inches per millisecond in both directions. If x represents the position on the string from the left-most end, so that 0≤x≤10, which of the following equations can be used to find the location x of the vibration after 0.3 milliseconds? A. | x -5 | =0. 3 B. ∣cx−5∣=0.3 C. | x -0.3 | = 5 D. | x - 10 | =0.3c

Answers

Answer:

The correct option is

A.  \ (1)/(c) * \left | x - 5 \right | = 0.3

Step-by-step explanation:

The parameters given are;

The length of the string = 10 inches

The speed or rate of travel of the wave = c inches per millisecond

The position on the string from the left-most end = x

The time duration of motion of the vibration to reach x= 0.3 milliseconds

The distance covered = Speed × Time = c×0.3

Given that the string is plucked at the middle, with the vibration travelling in both directions, the point after 0.3 millisecond is x where we have;

The location on the string where it is plucked = center of the string = 10/2 = 5 inches

Distance from point of the string being plucked (the center of the string) to the left-most end = 5 inches

Therefore, on the left side of the center of the string we have;

The distance from the location of the vibration x (measured from the left most end) to the center of the string = 5 - x = -(x -5)

On the right side of the center, the distance from x is -(5 - x) = x - 5

Therefore, the the equation that can be used to find the location of the vibration after 0.3 milliseconds is (1)/(c) * \left | x - 5 \right | = 0.3 or \left | x - 5 \right | = 0.3 * c which gives the correct option as A