A solution has a (oh-) = 8.6 × 10-5 the poh=, ph=, (h+)=

Answers

Answer 1

Answer: pOh is calculated by the negative logarithm of hydroxide ions concentration. From the given value, we have:

pOH = -log(8.6 x 10 ^-5)
pOH = 4.07

To calculate the pH we use the relation of pOH and pH, expressed as:

14 = pOH + pH
pH = 14 - 4.07 = 9.93
pH = -log [H+]
[H+] = 10^-9.93 = 1.16 x 10^-3 M

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What is the formula for carbon tetrachloride?a. CCl
b. CCl2
c. CCl3
d. CCl4

Answers

The formula for carbon tetrachloride is CCl4. The answer is letetr D. The rest of the choices do not answer the question above.

A hydrocarbon is said to be saturated if: A)           one end of the molecule is hydrophilic while the other end is hydrophobic.
                B)            it has one or more double bonds between carbon atoms.
                C)            it contains more than one functional group.
                D)           each internal carbon atom is covalently bonded to two hydrogen atoms.
                E)            its functional groups include at least one aromatic ring.

Answers

D. If each eternal carbon is bonded to 2 hydrogen atoms, the hydrogen carbon is saturated. An easier way to remember if a hydrocarbon is saturated or not is to look for a double bond between 2 carbons in the chain, if this if present the hydrocarbon is UNsaturated, if this is not present the hydrocarbon is saturated.

The fuel used in many disposable lighters is liquid butane, C4H10. Butane has a molecular weight of 58.1 grams in one mole. How many carbon atoms are in 1.50 g of butane?

Answers

Answer:

6.21 × 10²² Carbon Atoms

Solution:

Data Given:

Mass of Butane (C₄H₁₀) = 1.50 g

M.Mass of Butane = 58.1 g.mol⁻¹

Step 1: Calculate Moles of Butane as,

Moles = Mass ÷ M.Mass

Putting values,

Moles = 1.50 g ÷ 58.1 g.mol⁻¹

Moles = 0.0258 mol

Step 2: Calculate number of Butane Molecules;

As 1 mole of any substance contains 6.022 × 10²³ particles (Avogadro's Number) then the relation for Moles and Number of Butane Molecules can be written as,

Moles = Number of C₄H₁₀ Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹

Solving for Number of Butane molecules,

Number of C₄H₁₀ Molecules = Moles × 6.022 × 10²³ Molecules.mol⁻¹

Putting value of moles,

Number of C₄H₁₀ Molecules = 0.0258 mol × 6.022 × 10²³ Molecules.mol⁻¹

Number of C₄H₁₀ Molecules = 1.55 × 10²² C₄H₁₀ Molecules

Step 3: Calculate Number of Carbon Atoms:

As,

1 Molecule of C₄H₁₀ contains = 4 Atoms of Carbon

So,

1.55 × 10²² C₄H₁₀ Molecules will contain = X Atoms of Carbon

Solving for X,

X = (1.55 × 10²² C₄H₁₀ Molecules × 4 Atoms of Carbon) ÷ 1 Molecule of C₄H₁₀

X = 6.21 × 10²² Atoms of Carbon

$\boxed{6.216 * {\text{1}}{{\text{0}}^{{\text{22}}}}{\text{ atoms}}}$ of carbon is present in 1.50 g of butane.

Further Explanation:

Avogadro’s number indicates how many atoms or molecules a mole can have in it. In other words, it provides information about the number of units that are present in one mole of the substance. It is numerically equal to ${\text{6}}{\text{.022}} * {\text{1}}{{\text{0}}^{{\text{23}}}}\;{\text{units}}$ . These units can be atoms or molecules.

The formula to calculate the moles of ${{\text{C}}_{\text{4}}}{{\text{H}}_{{\text{10}}}}$ is as follows:

${\text{Moles of }}{{\text{C}}_{\text{4}}}{{\text{H}}_{{\text{10}}}} = \frac{{{\text{Given mass of }}{{\text{C}}_{\text{4}}}{{\text{H}}_{{\text{10}}}}}}{{{\text{Molar mass of }}{{\text{C}}_{\text{4}}}{{\text{H}}_{{\text{10}}}}}}$ …… (1)

Substitute 1.50 g for the given mass and 58.1 g/mol for the molar mass of ${{\text{C}}_{\text{4}}}{{\text{H}}_{{\text{10}}}}$ in equation (1).

$\begin{aligned}{\text{Moles of }}{{\text{C}}_{\text{4}}}{{\text{H}}_{{\text{10}}}} &= \left( {{\text{1}}{\text{.50 g}}} \right)\left( {\frac{{{\text{1 mol}}}}{{{\text{58}}{\text{.1 g}}}}} \right)\n&= {\text{0}}{\text{.0258 mol}}\n\end{aligned}$

Since one mole of ${{\text{C}}_{\text{4}}}{{\text{H}}_{{\text{10}}}}$ has ${\text{6}}{\text{.022}} * {\text{1}}{{\text{0}}^{{\text{23}}}}\;{\text{molecules}}$ of ${{\text{C}}_{\text{4}}}{{\text{H}}_{{\text{10}}}}$ . Therefore the formula to calculate the molecules of butane is as follows:

${\text{Molecules of }}{{\text{C}}_{\text{4}}}{{\text{H}}_{{\text{10}}}} = \left( {{\text{Moles of }}{{\text{C}}_{\text{4}}}{{\text{H}}_{{\text{10}}}}} \right)\left( {{\text{Avogadro's Number}}} \right)$ …… (2)

Substitute 0.0258 mol for the moles of ${{\text{C}}_{\text{4}}}{{\text{H}}_{{\text{10}}}}$ and ${\text{6}}{\text{.022}} * {\text{1}}{{\text{0}}^{{\text{23}}}}\;{\text{molecules}}$ for Avogadro’s number in equation (2).

$\begin{aligned}{\text{Molecules of }}{{\text{C}}_{\text{4}}}{{\text{H}}_{{\text{10}}}}{\mathbf{}}&=\left( {0.0258{\text{ mol}}} \right)\left( {\frac{{{\text{6}}{\text{.022}} * {\text{1}}{{\text{0}}^{{\text{23}}}}{\text{ molecules}}}}{{{\text{1 mol}}}}} \right)\n&= 1.554 * {\text{1}}{{\text{0}}^{{\text{22}}}}{\text{ molecules}} \n\end{aligned}$

The chemical formula of butane is ${{\text{C}}_{\text{4}}}{{\text{H}}_{{\text{10}}}}$ . This indicates one molecule of butane has four atoms of carbon. Therefore the number of carbon atoms can be calculated as follows:

$\begin{aligned}{\text{Atoms of carbon}} &= \left( {1.554 * {\text{1}}{{\text{0}}^{{\text{22}}}}{\text{ molecules}}} \right)\left( {\frac{{{\text{4 C atoms}}}}{{{\text{1 molecule of }}{{\text{C}}_{\text{4}}}{{\text{H}}_{{\text{10}}}}}}} \right)\n&= 6.216 * {\text{1}}{{\text{0}}^{{\text{22}}}}{\text{ C atoms}} \n\end{aligned}$

Learn more:

Calculate the moles of chlorine in 8 moles of carbon tetrachloride: brainly.com/question/3064603
Calculate the moles of ions in the solution: brainly.com/question/5950133

Answer details:

Grade: Senior School

Chapter: Mole concept

Subject: Chemistry

Keywords: 1.50 g, 58.1 g/mol, butane, C4H10, Avogadro’s number, $6.216*10^22$ C atoms, $1.554*10^22$ molecules, moles, one mole, chemical formula, carbon atoms, molar mass of C4H10, given mass of C4H10.

An indicator is what type of compound?a. reducing agent
b. oxidizing agent
c. weak base or acid
d. strong base or acid

Answers

The letter (d.) strong base or acid would be the most appropriate answer to the question above. An indicator is a strong base or acid. Indicators are strong base and acid because through this you can determine if a compound is acid or base with its color.

Indicators are compounds which are weak bases or weak acids as they can dissociate into ions .The correct option is C.

Indicator is defined as a chemical substance which is chemically a weak acid or a weak base which changes it's color depending upon the concentration of hydrogen ions present in the solution.They dissociate slightly in water to produce ions.

These are generally derived from plant pigments and are of slightly acidic or basic in nature.There are three types of indicators:

1) natural indicators

2) synthetic indicators

3) olfactory indicators.

These are mainly used in determination of end point of titrations. Every indicator has it's pH range in which it can perform effectively.These are usually organic compounds.

As weak acids and bases are easily dissociated ,thus indicators are weak bases or weak acids.Thus, the correct option is C.

Learn more about indicators,here:

brainly.com/question/29016702

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A solution has a uniform composition and is able to be separated by physical means

has a heterogeneous composition and is able to be separated by physical means

has a heterogeneous composition and is able to be separated by chemical means

has a uniform composition and is only able to be separated by chemical means

Answers

A solution has a uniform composition and is only able to be separated by chemical means.

The bicycle is said to be the most energy-efficient means of transportation. Where does the energy that drives it come from?

Answers

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from the food that the rider eats.

well the food that the person eats powers the mucles and the person uses their wieght/gravity to push down on the pedals which pulls the chain and, since the wheel is a diffarent size, you either get more power and less speed or more speed and less power

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