CHEMISTRY HIGH SCHOOL

In a nuclear reaction, the energy released is equal to 8.1 x 1016 joules. Calculate the mass lost in this reaction. (1 J = 1 kg m2/s2) and the speed of light = 3.00 × 10^8 m/s ]Answer

7.2 x 1032 kg

2.7 x 108 kg

9.0 x 10-1 kg

7.2 x 10-16 kg

Answers

Answer 1
Answer: use the formula E=mc^2
energy given=8.1 x 10^16 joules
speed of light = 3.00 × 10^8 m/s

plug in the values we'll get mass=9.0 x 10-1 kg
Answer 2
Answer:

Answer : The mass lost in this reaction will be, 9.0* 10^(-1)Kg

Explanation :

According to the Einstein equation, the energy is equal to the product of mass and the square of the speed of light.

The mathematical expression is :

E=m* c^2

where,

E = energy  released = 8.1* 10^(16)J

c = speed of light = 3* 10^8m/s

m = mass lost = ?

Now put all the given values in the above formula, we get the mass lost in the reaction.

8.1* 10^(16)J=m* (3* 10^8m/s)^2

8.1* 10^(16)Kg.m^2/s^2=m* (3* 10^8m/s)^2

m=9.0* 10^(-1)Kg

Therefore, the mass lost in this reaction will be, 9.0* 10^(-1)Kg

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Explain why benzoic acid is able to be separated from acetanilide using sodium bicarbonate.

Answers

Benzoic acid is not soluble in water, so the addition of sod

Final answer:

Benzoic acid is separated from acetanilide using sodium bicarbonate by converting it into sodium benzoate, which is soluble in water. Acetanilide remains unaffected in the mixture.

Explanation:

In the process of separating benzoic acid from acetanilide using sodium bicarbonate, the basic nature of sodium bicarbonate reacts with the acidic benzoic acid, leading to the formation of sodium benzoate. The sodium benzoate is highly soluble in water, allowing it to be easily separated from the acetanilide, which remains insoluble. On the other hand, acetanilide is not affected by the sodium bicarbonate and remains unaffected in the mixture.

Learn more about Separation of benzoic acid and acetanilide using sodium bicarbonate here:

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This reaction is an example of what type of reaction? H2SO3(aq) H2O(l) + SO2(g)a. a synthesis reaction
b. a disynthesis reaction
c. a combustion reaction
d. a decomposition reaction

Answers

This reaction H2SO3(aq) H2O(l) + SO2(g) is an example of what a decomposition reaction. It is not a replacement reaction because no other compound is involved. It is not a combustion reaction because no oxygen is involved.

Answer: Option (d) is the correct answer.

Explanation:

A chemical reaction in which a compound dissociates to give two different compounds or atoms is known as a dissociation reaction.

For example, H_(2)SO_(3)(aq) \rightarrow H_(2)O(l) + SO_(2)(g)

Here, sulfurous acid dissociates into water and sulfur dioxide gas. Both water and sulphur dioxide have different properties than sulfurous acid.

Therefore, we can conclude that the given reaction is an example of a decomposition reaction.

A student neutralized 16.4 milliliters of HCl by adding 12.7 milliliters of 0.620 M KOH. What was the molarity of the HCl acid?(1) 0.168 M (3) 0.620 M
(2) 0.480 M (4) 0.801 M

Answers

V ( HCl ) = 16.4 mL / 1000 => 0.0164 L

M( HCl) = ?

V( KOH) = 12.7 mL / 1000 => 0.0127 L

M(KOH) = 0.620 M

Number of moles KOH:

n = M x V

n = 0.620 x 0.0127

n = 0.007874 moles of KOH

number of moles HCl :

HCl + KOH = H2O + KCl

1 mole HCl ------ 1 mole KOH
? mole HCl--------0.007874 moles KOH

moles HCl = 0.007874 * 1 / 1

= 0.007874 moles of HCl

M = n / V

M = 0.007874 / 0.0164

= 0.480 M

Answer (2)

hope this helps!

2H₂O ----> 2H₂ + O₂How many moles of hydrogen are produced when 6.28 mol of oxygen form?

A.) 3.14 mol
B.) 6.28 mol
C.) 12.6 mol
D.) 25.2 mol

Answers

2 H2O ------------> 2 H2 + 1 O2

2 mol H2 ----> 1 mol O2
x mol H2 -----> 6.28 mol O2

x = 6.28 * 2

x ≈ 12.6 mol

answer C

hope this helps!.
6.28 mol O2* (2 mol H2/ 1 mol O2)= 12.6 mol H2

The correct answer is C. 12.6 mol~

Parts per million is used to express the

Answers

It is used to express very small concentrations of solute. Hope this helped ☻

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Answers

The proper word equation  for

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  iron displaces  tin from it compound ( Tin (iv) nitrate to form iron (iii) nitrate and tin.

from the equation above 4 moles of Fe  displaces  3 moles of Sn(NO3)4 to form 4 moles of Fe(NO3)3 and  3 moles of SN
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