A scientist is conducting research to determine how much pressure a dam can withstand. Why are good observations important to his research?

Answers

Answer 1
Answer:

The things that a scientist should consider while observing the force is the environmental conditions,the force that is expected to act on the dam, the means to contain that force,  and compare different types of designs in accordance with the location of the dam


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The cloud of interstellar dust and gas that forms a star is known as a A. protostar.B. white dwarf.C. red giant.D. nebula.User: 15. With an average surface temperature of about 737 K, _______ is the hottest planet. A. MarsB. MercuryC. EarthD. Venus

At the local grocery store, you push a 14.5-kg shopping cart. You stop for a moment to add a bag of dog food to your cart. With a force of 12.0 N you now accelerate the cart from rest through a distance of 2.29 m in 3.00 s. What was the mass of the dog food?

Answers

Answer:

The mass of the dog food added is 9.03 kg

Explanation:

Given;

mass of the shopping cart, m₁ = 14.5 kg

let the mass of the bag added = m₂

the force applied, F = 12 N

initial velocity of the cart-bag system, u = 0

distance traveled by the system, d = 2.29 m

time of motion of the system, t = 3.0 s

The acceleration of the system is calculated as;

d = ut + (1)/(2) at^2\n\n2.29 = 0 + ((1)/(2) * 3^2)a\n\n2.29 = 4.5 a\n\na = (2.29)/(4.5) \n\na = 0.51 \ m/s^2

The total mass of the system (M) is calculated as follows;

F = Ma

M = F/a

M = (12)/(0.51)

M = 23.53 kg

The mass of the dog food added is calculated as;

m₂ = M - m₁

m₂ = 23.53 kg - 14.5 kg

m₂ = 9.03 kg

In Kepler's model of the solar system, the planets move around the Sun in _________ orbits.a. circular
b. elliptical
c. epicyclic
d. continuously changing

Answers

b. elliptical.

The planets move in elliptical orbits round the Sun.

Answer:

B) elliptical

Explanation:

A force of 1500 pounds drags a truck 40 feet in 20 seconds. How much work is accomplished? How much power was required?

Answers

Answer:

The work done and power are 60000 Pounds-feet and 3000 Pounds-feet/sec.

Explanation:

Given that,

Force F = 1500 pounds

Distance d = 40 feet

Time t = 40 sec

Work done :

The work done is the product of the force and distance.

The work done is defined as,

W = F * d

Where, W = work

F = force

d = distance

Put the value into the formula of work

W= 1500*40

W = 60000\ Pounds-feet

Power:

The power is equal to the work done divided by time.

The power is defined as,

P = (W)/(t)

Where, P = power

W = work

t = time

Put the value into the formula of power

P = (60000)/(20)

P=3000\ Pounds-feet/s

Hence, The work done and power are 60000 Pounds-feet and 3000 Pounds-feet/sec.

work = f x s = 1500 x 40
power = w/t = (1500 x 40) / 20

Name three devices that can store electric potential energy

Answers

Potential energy, unlike kinetic, is stored energy. This energy comes from different sources. An object with potential energy also has the ability to produce energy if something triggers it. Example, a charged battery, a car on top of a hill, and capacitors.

How many seconds would an Olympic skier take to race down a 2500 meter course going 250 m/sec?

Answers

Answer:

10 seconds

Explanation:

Hope this is right and that it helps.

You see if the skier is going 250 meters a second 250 times 10 is 2500 so it would take the skier 10 seconds.

Answer:

10 sec.

Explanation:

distance = 2500 meters

velocity = 250 meter/second

time = distance / velocity

       =    2500 meters    

          250 meter/second

       = 10 sec.

A small package is attached to a helium-filled balloon rising at 2 m/s. The package drops from the balloon when it is 14 meters above the ground. What is the velocity of the package just before it hits the ground?

Answers

The velocity of the package just before it hits the ground is 16.7 m/s.

What is velocity?

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

Initial velocity(u)=2 m/s

V(velocity of hitting)=?

S(distance travelled)=  14 meters

The velocity of the package just before it hits the ground is found as;

From the Newton's third equation of motion;

v²=u²+2as.

v²=(-2)²+2(9.81)(14)

v=16.7 m/s

Hence,the velocity of the package just before it hits the ground is 16.7 m/s.

To learn more about the velocity, refer to the link;

brainly.com/question/862972

#SPJ2

I would assume air resistance is negligible and so the acceleration of the package would be approximately 9.81 m/s².

Taking downwards as positive, use v²=u²+2as.
v²=(-2)²+2(9.81)(14)
v=16.7 m/s