MATHEMATICS HIGH SCHOOL

Find the value of the variable if P is between J & K.

JP = 2x ; PK = 7x ; JK = 27

Answers

Answer 1
Answer: J ---- P --- K

JP = 2x
PK = 7x
JK = 27

2x + 7x = 27
9x = 27
x = 27/9
x = 3

The value of P is 3.

JP = 2x = 2(3) = 6
PK = 7x = 7(3) = 21

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Use long division to find the quotient. 

(x²+6x-27) ÷ (x-3)

Answers

( x^2+6x-27 )/(x-3) = ( x^2+6x +3x-3x-27 )/(x-3) = ( x^2+9x-3x-27 )/(x-3) = \n \n =( x(x +9 )-3(x+9) )/(x-3) = ( (x +9 ) (x-3) )/(x-3) = x+9 \n \n \n x-3\neq 0 \nx\neq 3\nD=R\setminus \left \{ 3 \right \}

Graph the second equation to find the solution of the system of equations.y = –x,

y = 2x + 6

What is the point of intersection

Answers

Answer: (-2,2)

Explanation: I plugged it into a graphing calc!

Answer:

So the point of intersection would be -x=2x+6

and then we'll subtract 2x on both sides and get -3x=6

this will result in x=-2

Then we'll substitute that into y=-x, so y=2

Therefore the point of intersection is (-2,2)

Hope I helped, have a nice day :)

Write 5.1 x 10^-3 as an ordinary number.

Answers

Answer:

This would be .0051 as an ordinary number.

Step-by-step explanation:

In order to turn this into a normal number, simply move the decimal place the same amount of times as the exponent.

So this would result in .0051

Find the slope of the line that passes through the points (-2,5) and (-3,-1)

Answers

slope between (x1,y1) and (x2,y2) is
s=(y2-y1)/(x2-x1)

(x,y)
(-2,5)
(-3,-1)
x1=-2
y1=5
x2=-3
y2=-1

slope=(-1-5)/(-3-(-2))=-6/(-3+2)=-6/-1=6

slope=6

find the indicated terms of the arithmetic sequence with the given description. the 50th term is 1001, and the common difference is 6. find the first and second terms.

Answers

Answer:

a₁ = 707 a₂ = 713

Step-by-step explanation:

the nth term of an arithmetic sequence is

a_(n) = a₁ + (n - 1)d

a₁ is the first term, d the common difference , n the term number

given

a₅₀ = 1001 , then

a₁ + 49d = 1001 ← substitute d = 6

a₁ + 49(6) = 1001

a₁ + 294 = 1001 ( subtract 294 from both sides )

a₁ = 707

and a₂ = a₁ + d = 707 + 6 = 713

What is the distance between the points (-1, 4) and (3, 1)

Answers

The distance between the points is 5
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