The volume of a pond being studied for the effects of acid rain is 35 kiloliters (kL). There are 1,000 liters (L) in 1 kL and 10^3 microliters (mL) in 1 L. What is the volume of this pond in microliters?

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Answer 1
Answer: The volume of a pond being studied for the effects of acid rain is 35 kiloliters (kL). There are 1,000 liters (L) in 1 kL and 10^3 microliters (mL) in 1L.

35 kiloliters ( 1000 liters/1 kiloliters) (10^3 microliters / 1liters)
=35,000,000 microliters

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How does the kinetic theory of gases explain the weather changes happening in the troposphere?

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Since the troposphere is heated from below, it tends to be colder as you start moving up since the air gets thinner. The sun's heat radiates which causes the air to be "stirred up" which can cause weather changes.

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A sample of an unknown substance has a mass of 89.5 g. If 345.2 J of heat are required to heat the substance from 285 K to 305 K, what is the specific heat of the substance?

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The specific heat of the unknown sample has been \rm \bold{0.192\;\;J/g^\circ C}.

Specific heat has been defined as the amount of heat required to raise the temperature of 1 gram of substance by 1 degree Celsius.

The specific heat (c) for a substance can be given by:

Q=mc\Delta T ......(i)

Where, the heat required by the substance, Q=345.2\;\text J

The mass of the substance has been, m=89.5\;\text g

The change in temperature of the system has been, \Delta T

The change in temperature has been given as:

\Delta T=T_f-T_i

The initial temperature of the substance, T_i=285\;\text K

The final temperature of the substance, T_f=305\;\text K

Substituting the values for the change in temperature, \Delta T:

\Delta T=305\;-\;285\;K\n\Delta T=20\;\text K

Substituting the values in equation (i):

345.2=89.5\;*\;c\;*\;20\n345.2=1,790c\nc=0.192\rm \;J/g^\circ C

The specific heat of the unknown sample has been \rm \bold{0.192\;\;J/g^\circ C}.

For more information about specific heat, refer to the link:

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The specific heat is the heat needed per unit mass to raise the temperature by 1 degree celsius. So the specific heat = heat/(mass*ΔT) = 345.2/[89.5*(305-285)]=0.193 J/(g*℃). When using ΔT, the unit K and ℃ are the same.

Which liquid has the highest vapor pressure at 75°C?(1) ethanoic acid (3) propanone
(2) ethanol (4) water

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Answer:

1)  Ethanol

Explanation:

If we will have interactions we will need more energy to break them in order to go from liquid to gas. If we need more energy, therefore, the temperature will be higher.

In this case, we can discard the propanone because this molecule don't have the ability to form hydrogen bonds. (Let's remember that to have hydrogen bonds we need to have a hydrogen bond to a heteroatom, O, N, P or S).

Then we have to analyze the hydrogen bonds formed in the other molecules. For ethanol, we will have only 1 hydrogen bond. For water and ethanoic acid, we will have 2 hydrogen bonds, therefore, we can discard the ethanol.  

For ethanoic acid, we have 2 intramolecular hydrogen bonds. For water we have 2 intermolecular hydrogen bonds, therefore, the strongest interaction will be in the ethanoic acid.

The closer boiling point to the 75ºC is the ethanol (boiling point of 78.8 ºC) therefore these molecules would have enough energy to break the hydrogen bonds and to past from liquid to gas.

Final answer:

Among Ethanoic Acid, Ethanol, Propanone, and Water, Propanone has the highest vapor pressure at 75°C because it has the weakest intermolecular forces, making it more likely to vaporize.

Explanation:

The vapor pressure of a substance is determined by how easily particles can escape from the liquid phase and become a gas. In general, the higher the temperature, the higher the vapor pressure.

The four liquids provided in your question are Ethanoic Acid, Ethanol, Propanone, and Water. At 75°C, Propanone is known to have the highest vapor pressure among the listed substances. This is because Propanone, also known as acetone, has weaker intermolecular forces and thus more readily vaporizes.

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What is a limiting reagent? A.) The reactant that is used up first in a reaction B.) The reactant that is used the least reactive in a reaction C.) the reactant with the smallest coefficient in the equation D.) the reactant with the largest coefficient in the equation

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The reactant that is totally consumed during a reaction, or the limiting reagent, decides when the process comes to an end. A limiting reagent is the reactant that is used up first in a reaction. Therefore, option A is correct.

What is a limiting reagent?

A reactant that is completely consumed at the end of a chemical reaction is known as the limiting reagent. Since the reaction cannot proceed without this reagent, the amount of product that can be produced is constrained.

The limiting reactant is the one that is consumed first and sets a limit on the quantity of product(s) that can be produced. Calculate how many moles of each reactant are present and contrast this ratio with the mole ratio of the reactants in the balanced chemical equation to get the limiting reactant.

The terms limiting reagent and limiting agent may also be used to describe the limiting reactant.

Thus, option A is correct.

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Answer: A.) The reactant that is used up first in a reaction

The balanced equation below represents a molecule of bromine separating into two bromine atoms.Br2-->Br + Br
What occurs during this change?
(1) Energy is absorbed and a bond is formed.
(2) Energy is absorbed and a bond is broken.
(3) Energy is released and a bond is formed.
(4) Energy is released and a bond is broken.

Answers

(4) Energy is released and a bond is broken. This happens because when the bromine molecule splits, the energy that was holding the two atoms together is released.

Answer is: (2) Energy is absorbed and a bond is broken.

This energy is called bond-dissociation energy.

Bond-dissociation energy is the measure of bond strength in a chemical bond.

Bond energy of bromine molecule (sigma bond) is energy needed for breaking up one molecule of bromine into two bromine atoms.

When two bromine atoms (Br) form molecule of bromine (Br₂), than energy is released and bond is formed.


What is the best way to learn measurements and how to add and multipy them​

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Answer:

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Explanation: