Jason is saving up for a skateboard and helmet. The skateboard is 45.50 with tax and the helmet is 18.25 with tax. He earned 1/3 of the money by mowing lawns and the rest by babysitting. How much did jason earn with babysitting

Answers

Answer 1
Answer:

Answer:

  2/3 of the money, $42.50

Step-by-step explanation:

The total Jason is saving is ...

  $45.50 +18.25 = $63.75

If 1/3 was earned by mowing, the remaining 2/3 was earned by babysitting. Two thirds of the amount is ...

  (2/3) × $63.75 = $42.50

Jason earned $42.50 by babysitting.


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A line with a slope of 10 passes through the point (9, 3).  What is its equation in point-slope form?​

Answers

Answer:

y=10(x-9)+3

Step-by-step explanation:

Point Slope Formula: y=m(x-x1)+y

y=10(x-9)+3

If each person takes up 2.25 square feet of space, how many people can fit into an area that is 15 feet by 30 feet?A) 17
B) 40
C) 88
D) 200

Answers

D is the answer Multiply 15 times 30 and divide by 2.25

Answer:

D

Step-by-step explanation:

(please help.) (I screenshot the question and choices )

Answers

The second answer on the list is the correct one.

The graph of which function has an axis of symmetry at x =-1/4 ?f(x) = 2x2 + x – 1

f(x) = 2x2 – x + 1

f(x) = x2 + 2x – 1

f(x) = x2 – 2x + 1

Answers

The graph of which function has an axis of symmetry at x = -1/4 is :

f(x) = 2x² + x – 1

Further explanation

Discriminant of quadratic equation ( ax² + bx + c = 0 ) could be calculated by using :

D = b² - 4 a c

From the value of Discriminant , we know how many solutions the equation has by condition :

D < 0 → No Real Roots

D = 0 → One Real Root

D > 0 → Two Real Roots

Let us now tackle the problem!

An axis of symmetry of quadratic equation y = ax² + bx + c is :

\large {\boxed {x = (-b)/(2a) } }

Option 1 :

f(x) = 2x² + x – 1 → a = 2 , b = 1 , c = -1

Axis of symmetry → x = (-b)/(2a) = (-1)/(2(2)) = -(1)/(4)

Option 2 :

f(x) = 2x² – x + 1 → a = 2 , b = -1 , c = 1

Axis of symmetry → x = (-b)/(2a) = (-(-1))/(2(2)) = (1)/(4)

Option 3 :

f(x) = x² + 2x – 1 → a = 1 , b = 2 , c = -1

Axis of symmetry → x = (-b)/(2a) = (-2)/(2(1)) = -1

Option 4 :

f(x) = x² – 2x + 1 → a = 1 , b = -2 , c = 1

Axis of symmetry → x = (-b)/(2a) = (-(-2))/(2(1)) = 1

Learn more

Answer details

Grade: High School

Subject: Mathematics

Chapter: Quadratic Equations

Keywords: Quadratic , Equation , Discriminant , Real , Number

The graph of function \boxed{f(x)=2x^(2)+x-1} has an axis of symmetry as \boxed{x=-(1)/(4)}.

Further explanation:

The standard form of a quadratic equation is as follows:

\boxed{f(x)=ax^(2)+bx+c}

The vertex form of a quadratic equation is as follows:

\boxed{g(x)=a(x-h)^(2)+k}

Axis of symmetry is the line which divides the graph of the parabola in two perfect halves.

The formula for axis of symmetry of a quadratic function is given as follows:

\boxed{x=-(b)/(2a)}

The first function is given as follows:

f(x)=2x^(2)+x-1

The above function is in standard form with a=2, b=1 and c=-1.

Then its axis of symmetry is calculated as,

\begin{aligned}x&=-(b)/(2a)\n&=-(1)/(2*2)\n&=-(1)/(4)\end{aligned}  

The axis of symmetry of first function is x=-(1)/(4).

Express the function f(x)=2x^(2)+x-1 in its vertex form,

\begin{aligned}f(x)&=2x^(2)+x-1\n&=(√(2)x)^(2)+\left(2* √(2)x* (1)/(2√(2))\right)-1+\left((1)/(2√(2))\right)^(2)-\left((1)/(√(2))\right)^(2)\n&=\left(√(2)x+(1)/(2√(2))\right)^(2)-1-(1)/(8)\n&=\left[√(2)\left(x+(1)/(4)\right)\right]^(2)-(9)/(8)\n&=2\left(x-\left(-(1)/(4)\right)\right)^(2)-(9)/(8)\end{aligned}

The above equation is in the vertex form with a=2, h=-(1)/(4) and k=-(9)/(8).

Therefore, its axis of symmetry is given as,

\begin{aligned}x&=h\nx&=-(1)/(4)\end{aligned}  

The graph of function f(x)=2x^(2)+x-1 is shown in Figure 1.

The second function is given as follows:

f(x)=2x^(2)-x+1

The above function is in standard form with a=2, b=-1 and c=1.

Then its axis of symmetry is calculated as,

\begin{aligned}x&=-(b)/(2a)\n&=-((-1))/(2*2)\n&=(1)/(4)\end{aligned}  

The axis of symmetry of second function is x=(1)/(4).

The third function is given as follows:

f(x)=x^(2)+2x-1

The above function is in standard form with a=1, b=2 and c=-1.

Then its axis of symmetry is calculated as,

\begin{aligned}x&=-(b)/(2a)\n&=-(2)/(2*1)\n&=-1\end{aligned}  

The axis of symmetry of third function is x=-1.

The fourth function is given as follows:

f(x)=x^(2)-2x+1  

The above function is in standard form with a=1, b=-2 and c=1.

Then its axis of symmetry is calculated as,

\begin{aligned}x&=-(b)/(2a)\n&=-(-2)/(2*1)\n&=1\end{aligned}  

The axis of symmetry of fourth function is x=1.

Therefore, the function \boxed{f(x)=2x^(2)+x-1} has an axis of symmetry as \boxed{x=-(1)/(4)}.

Learn more:

1. A problem on graph brainly.com/question/2491745

2. A problem on function brainly.com/question/9590016

3. A problem on axis of symmetry brainly.com/question/1286775

Answer details:

Grade: High school

Subject: Mathematics

Chapter: Functions

Keywords:Graph, function, axis, f(x), 2x^2+x-1, axis of symmetry, symmetry, vertex, perfect halves, graph of a function, x =- 1/4.

Determine if the following lines are parallel, perpendicular, or neither. y=x-8 x+y=-5

Answers

Answer:

To determine if two lines are parallel or perpendicular, we need to examine their slopes.

First, let's rearrange the second equation, x+y=-5, to slope-intercept form (y = mx + b):

y = -x - 5

In this form, we can see that the slope of the second line is -1.

The first equation, y=x-8, is already in slope-intercept form, y = mx + b, where the slope is 1.

Comparing the slopes, we can see that the slopes of the two lines are different. The slope of the first line is 1, and the slope of the second line is -1.

Since the slopes are not equal, the lines are not parallel.

Now, let's determine if the lines are perpendicular:

Two lines are perpendicular if the product of their slopes is -1.

The slope of the first line is 1, and the slope of the second line is -1.

Since 1 * -1 = -1, the product of the slopes is -1.

Therefore, the lines y = x - 8 and x + y = -5 are perpendicular.

Step-by-step explanation:

Answer:     Perpendicular

Step-by-step explanation:

Our task is to identify if these lines are parallel or not. The lines are :

  • \rm{y=x-8}
  • \rm{x+y=-5}

A good move would be to write these two equations in the same format. The easiest one is slope-intercept. Equation 1 is already in this form, but the second one isn't.

To write the second equation in slope-intercept, all we need to do is subtract x from both sides, and we get:

  • \rm{y=-5-x}

Now, switch the terms:

  • \rm{y=-x-5}

The slope of the first line is 1, and the slope of the second line is -1.

They can't be parallel, since their slopes are not the same. For them to be perpendicular, their slopes should be negative reciprocals of each other.

Is -1 the negative inverse of 1? Yes.

∴ The lines are perpendicular.

Can the square of an integer be a negative number

Answers

If you square an integer, there is no way to get a negative as a result.

Let's look at -5².

-5² means -5 × -5 or 25.

6² means 6 × 6 or 36.

So, there is no way to end up with a negative.

no it can't
minus on minus gives plus