MATHEMATICS HIGH SCHOOL

WILL MEDAL AND FANThe formula Q = MCT where Q = heat flow, M = mass, C = specific heat, and T = change of temperature is used to calculate heat flow. Solve this formula for T.

T = Q – MC
T = Q + MC
T = QMC
T = Q divided by the quantity M times C

Answers

Answer 1
Answer: The answer is T= Q divided by the quantity M times C. To solve for T, the goal is to isolate T from the rest of the factors which are M and C. To do this, divide M and C from both sides of the equation. This will cancel M and C from the right-hand side, leaving only T. So, there you have it, T is now equal to Q divided by the quantity M times C.
Answer 2
Answer: To solve this formula for T it is the last one.
T = Q divided by the quantity M times C.

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For each value of kk specified in parts (a)–(e), plot the set of points in the plane that satisfy the equationx2 / k − y2 = 1.
a. k = −1
b. k = 1
c. k = 2
d. k = 4
e. k = 10
f. k = 25
g. Describe what happens to the graph of
x2 / k − y2 = 1 as k → [infinity].

Answers

Answer:

Seee answer below.

Step-by-step explanation:

a. k = −1

If K=-1 the equation gets this form:

(x^2/-1) -y^2=1

There aren't natural numbers that being negative, adding them, we get 1 as result. So there is no graph for this equation.

b. k = 1

(x^2/1) -y^2=1

This is the natural form of the equation of an hyperbola. Attached you can find the graph.

c. k = 2

(x^2/2) -y^2=1

This is the natural form of the equation of an hyperbola. Attached you can find the graph.

d. k = 4

(x^2/4) -y^2=1

This is the natural form of the equation of an hyperbola. Attached you can find the graph.

e. k = 10

(x^2/10) -y^2=1

This is the natural form of the equation of an hyperbola. Attached you can find the graph.

f. k = 25

(x^2/25) -y^2=1

This is the natural form of the equation of an hyperbola. Attached you can find the graph.

g. Describe what happens to the graph of

x2 / k − y2 = 1 as k → [infinity].

As K is increasing the value of X will be tending to 0. So the equation for this will be:

− y^2 = 1.The solution for this is in the domain of the imaginary numbers.

Yeah I’m totally lost on this one tbh

Answers

(f\circ g)(x)=f(g(x))\n\nD_g:x\in[-5,\infty)\n\n(f\circ g)(x)=(√(x+5))^2+2=x+5+2=x+7\nD:x\in[-5,\infty)\n

Therefore, the second option.

Please help me with this one
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15x+4y=80

Answers

I hope this helps you
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Answers

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