How many different ways could a baking contest be judged if 15 pies are entered and 4 ribbons are awarded?

Answers

Answer 1
Answer: This is a question of combination since it does not take into account the order of the pies. The answer would be 1365. There are 1365 ways a baking contest ways can be judged if 4 ribbons are awarded with 15 pie entries. 

In case you need the order, then the permutation answer would be 32760.
Answer 2
Answer:

Answer:

1365

Step-by-step explanation:

We are given that 15 pies are entered in the contest.

Out of 15 , 4 are awarded with ribbons.

Now we are supposed to find How many different ways could a baking contest be judged.

Since the order of pie doesn't matter over here.

So, we will use combination.

^nC_r=(n!)/(r!(n-r)!)

Substitute n = 15

r = 4

So, ^(15)C_4=(15!)/(4!(15-4)!)

^(15)C_4=(15!)/(4!(11)!)

^(15)C_4=(15 * 14* 13 * 12 * 11!)/(4!(11)!)

^(15)C_4=(15* 14* 13 * 12)/(4* 3 * 2* 1)

^(15)C_4=1365

Hence there are 1365 ways in which a baking contest could be judged.


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A deposit can be filled by two keys. One poured 140 liters in 8 minutes and the other 130 liters in 7 minutes. How long it will take to fill the tank, drain being empty and closed?, if the two keys are open at the same time, knowing that its capacity is 400 liters?

Answers

its a matter of calculating the two speeds of filling and then add them together.
speed1 = 140 liters / 8 minutes = 17.5 liters per minute
speed2 = 130 liters / 7 minutes = 18.57 liters per minute
So we'll open both keys with speed1 and speed2, x amount of minutes, and fill 400 liters, if we write an equation of these statement that is:
17.5x + 18.57x = 400
solve for x!
36.07x = 400
x = 11.09
therefore it will take 11.09 minutes to fill the 400 liters tank with both keys open.

Facrorize TI un²k - 1/4 an²Q​

Answers