Which product is equivalent to 25x2 – 16?(5x − 4)(5x + 4)
(5x + 8)(5x − 8)
(5x − 4)(5x − 4)
(5x − 8)(5x − 8)

Answers

Answer 1

Answer: ANSWER
$25 {x}^(2) - 16 =( {5x - 4})(5x + 4)$

EXPLANATION

We want to factor the expression,

$25 {x}^(2) - 16$

We can rewrite the expression as

$25 {x}^(2) - 16 = ({5x})^(2) - {4}^(2)$

The expression is now a difference of two squares,

Recall that,

${a}^(2) - {b}^(2) = (a - b)(a + b)$

The expression now becomes;

$25 {x}^(2) - 16 =( {5x - 4})(5x + 4)$

Therefore the correct answer is option A.

Answer 2

Answer:

Answer:

Step-by-step explanation:

Related Questions

Doris put $4000 in a 5year CD paying 6% interest compounded monthly. After 2 years, she withdrew all her money, and as an early withdrawal penalty, she paid back all the interest she made during the first year. How much money was Doris left with? Show your work.
Which equation represents a line that is perpendicular to the line whose equation is y = 4x + 12?y = 4x + 4 y = -4x + 7 y = (-1/4x) + 1 y = (1/4x) + 9
Solve the logarithmic equation. be sure to reject any value that is not in the domain of the original logarithmic expressions. give the exact answer. log8(5x + 8) = log8(5x + 5)
Divide 3.7÷0.006 round the answer the nearest hundredth?
Express sin 404 in terms of the sine of a positive acute angle.

Im h--> 0

((Sqrt 9+h)-3)/h

Answers

$\lim_(h \to 0) ( √(9+h)-3)/(h) = ( √(9+0) -3)/(0)= (0)/(0) \n \lim_(h \to 0) ( √(9+h)-3)/(h)* ( √(9+h)+3 )/( √(9+h) +3)= \n = \lim_(h \to 0) (9+h-9)/(h( √(9+h) +3)) = \n \lim_(n \to 0) (h)/(h( √(9+h)+3) )= \n = (1)/( √(9) +3)$ =
= 1/6

Please help FAST!!

Which equation represents the graph of the linear function?

Answers

The line on that graph is sloping down as it proceeds from
left to right, it drops 3 units for every 1 unit to the right, and
it crosses the y-axis at y=1 .

So the equation of that line is y = -3x + 1 .

Elimination using multiplication.
3x-5y=14
2x+4y=2

Answers

3x - 5y = 14
2x + 4y = 2

We multiply the first equation by 2 and the second equation by 3 to obtain:

6x - 10y = 28
6x + 12y = 6

Subtracting the two equations:

-22y = 22
y = -1

Using this in the first equation:
3x - 5(-1) = 14
x = 3

The solution is:
(3 , -1)

A time/motion word problem"A plane leaves Denver heading due north at 500 mph. Simultaneously, another plane leaves Denver traveling due east at 1200 mph. After how many minutes will the planes be 650 miles apart?"

I know the answer is 30, but I have no clue how to solve the problem itself

Answers

The two planes are flying on the two legs of a right triangle.
The straight distance between them is the hypotenuse of the triangle.

Since the speeds are in mph, let's work the time in hours.
Call the time 'H' that we're looking for.
It's the number of hours after they both take off that they're 650 miles apart.

After 'H' hours, the first plane has gone 500H miles north.
After 'H' hours, the second plane has gone 1200H miles east.
After 'H' hours, they are 650 miles apart.

Do you remember this for a right triangle ? ==> A² + B² = C²

(500H)² + (1200H)² = (650)²

250,000H² + 1,440,000H² = 422,500

1,690,000 H² = 422,500

H² = (422,500) / (1,690,000) = 0.25

H = √0.25 = 1/2 hour = 30 minutes

$x^2=500^2+1200^2\n\nx^2=250000+1440000\ \ \ \Rightarrow\ \ \ \ x^2=1690000\ \ \ \Rightarrow\ \ \ \ x=1300\ [mph]\n\nthe\ distance=650\ miles\n\nthe\ speed= (the\ distance)/(the\ time) \ \ \ \Rightarrow\ \ \ 1300\ [mph]= (650\ [miles])/(the\ time)\n\nthe\ time= (650)/(1300) \ [hr]=0.5\ [hr]=30\ [min]\n\nAns.\ after\ 30\ minutes.$